python中八进制

Syntax to convert octal value to an integer (decimal format),

将八进制值转换为整数(十进制格式)的语法，

    int(oct_value, 8)

Here,

这里，

• oct_value should contain the valid octal value

  oct_value应该包含有效的八进制值

• 8 is the base value of the octal number system

  8是八进制数的基值

Note: oct_value must contain only octal digits (0, 1, 2, 3 ,4 ,5 ,6, 7), if it contains other than these digits a "ValueError" will return.

注意 ： oct_value必须仅包含八进制数字(0、1、2、3、4、5、6、7)，如果它不包含这些数字，则将返回“ ValueError” 。

程序将给定的八进制值转换为整数(十进制) (Program to convert given octal value to integer (decimal))

# function to convert given octal Value
# to an integer (decimal number)
def OctToDec(value):
try:
return int(value, 8)
except ValueError:
return "Invalid Octal Value"
# Main code
input1 = "1234567"
input2 = "7001236"
input3 = "1278"
print(input1, "as decimal: ", OctToDec(input1))
print(input2, "as decimal: ", OctToDec(input2))
print(input3, "as decimal: ", OctToDec(input3))

Output

输出量

1234567 as decimal:  342391
7001236 as decimal:  1835678
1278 as decimal:  Invalid Octal Value

Now, we are going to implement the program – that will take input the number as an octal number and printing it in the decimal format.

现在，我们将实现该程序–将输入的数字作为八进制数字并以十进制格式打印。

程序以八进制格式输入数字 (Program to input a number in octal format)

# input number in octal format and
# converting it into decimal format
try:
num = int(input("Input octal value: "), 8)
print("num (decimal format):", num)
print("num (octal format):", oct(num))
except ValueError:
print("Please input only octal value...")

Output

输出量

RUN 1:
Input octal value: 1234567
num (decimal format): 342391
num (octal format): 0o1234567
RUN 2:
Input octal value: 12700546
num (decimal format): 2851174
num (octal format): 0o12700546
RUN 3:
Input octal value: 12807
Please input only octal value...

翻译自: https://www.includehelp.com/python/input-a-number-in-octal-format.aspx

python中八进制