Leet Code OJ 83. Remove Duplicates from Sorted List [Difficulty: Easy]

题目：
Given a sorted linked list, delete all duplicates such that each element appear only once.

For example,
Given 1->1->2, return 1->2.
Given 1->1->2->3->3, return 1->2->3.

翻译：
给定一个排序号的链表，删除所有的重复元素，保证每个元素只出现一次。

分析:
在当前节点删除下一节点，会比较容易操作，只需要修改next指针。

代码：

/*** Definition for singly-linked list.* public class ListNode {*     int val;*     ListNode next;*     ListNode(int x) { val = x; }* }*/
public class Solution {public ListNode deleteDuplicates(ListNode head) {if(head==null){return null;}ListNode currentNode=head;while(currentNode.next!=null){if(currentNode.next.val==currentNode.val){currentNode.next=currentNode.next.next;}else{currentNode=currentNode.next;}}return head;}
}

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