#!/usr/bin/env python3#coding: utf-8#File: args_kwargs_demo.py#Author: lxw#Date: 10/9/17 11:16 AM

"""Demos for "*args" & "**kwargs" in Python.

Reference: [Python中如何使用*args和**kwargs](http://python.jobbole.com/83476/)"""

def func_args(*args):print("type(args):{0}\targs:{1}\n".format(type(args), args))def func_kwargs(**kwargs):print("type(kwargs):{0}\tkwargs:{1}\n".format(type(kwargs), kwargs))def func_args_kwargs(*args, **kwargs):print("type(args):{0}\targs:{1}".format(type(args), args))print("type(kwargs):{0}\tkwargs:{1}\n".format(type(kwargs), kwargs))deffunc(arg1, arg2, arg3):print("arg1:{0}\targ2:{1}\targ3:{2}".format(arg1, arg2, arg3))defmain():#函数定义

func_args_kwargs(1, 2, 3)

func_args_kwargs(1, a = 2, b = 3)

func_args_kwargs(a= 1, b = 2, c = 3)

func_args(1, 2, 3)#func_args(1, a = 2, b = 3) # TypeError: func_args() got an unexpected keyword argument 'a'

#func_args(a = 1, b = 2, c = 3) # TypeError

#func_kwargs(1, 2, 3) # TypeError: func_kwargs() takes 0 positional arguments but 3 were given

#func_kwargs(1, a = 2, b = 3) # TypeError

func_kwargs(a = 1, b = 2, c = 3)print("---" * 10, "\n")#函数调用

args = (1, "two", 3)

func(*args)

args= [1, "two", 3]

func(*args)delargs[0]print(args)

func("One", *args)

args_dic= {"arg3": 3, "arg1": "1", "arg2": "two"}

func(**args_dic)del args_dic["arg1"]print(args_dic)

func(1, **args_dic)if __name__ == '__main__':

main()else:print("Being imported as a module.")"""# Output:

type(args): args:(1, 2, 3)

type(kwargs): kwargs:{}

type(args): args:(1,)

type(kwargs): kwargs:{'a': 2, 'b': 3}

type(args): args:()

type(kwargs): kwargs:{'a': 1, 'b': 2, 'c': 3}

type(args): args:(1, 2, 3)

type(kwargs): kwargs:{'a': 1, 'b': 2, 'c': 3}

------------------------------

arg1:1 arg2:two arg3:3

arg1:1 arg2:two arg3:3

['two', 3]

arg1:One arg2:two arg3:3

arg1:1 arg2:two arg3:3

{'arg3': 3, 'arg2': 'two'}

arg1:1 arg2:two arg3:3"""