一、    列    转    行

create table STU_ROW2COL

(

id      VARCHAR2(10),

intname VARCHAR2(10),

subject VARCHAR2(20),

grade   NUMBER

)

insert into stu_row2col (ID, INTNAME, SUBJECT, GRADE) values ('1', 'ZORRO', '语文', 70);

insert into stu_row2col (ID, INTNAME, SUBJECT, GRADE) values ('2', 'ZORRO', '数学', 80);

insert into stu_row2col (ID, INTNAME, SUBJECT, GRADE) values ('3', 'ZORRO', '英语', 75);

insert into stu_row2col (ID, INTNAME, SUBJECT, GRADE) values ('4', 'SEKER', '语文', 65);

insert into stu_row2col (ID, INTNAME, SUBJECT, GRADE) values ('5', 'SEKER', '数学', 75);

insert into stu_row2col (ID, INTNAME, SUBJECT, GRADE) values ('6', 'SEKER', '英语', 60);

insert into stu_row2col (ID, INTNAME, SUBJECT, GRADE) values ('7', 'BLUES', '语文', 60);

insert into stu_row2col (ID, INTNAME, SUBJECT, GRADE) values ('8', 'BLUES', '数学', 90);

insert into stu_row2col (ID, INTNAME, SUBJECT, GRADE) values ('9', 'PG', '数学', 80);

insert into stu_row2col (ID, INTNAME, SUBJECT, GRADE) values ('10', 'PG', '英语', 90);

SQL>  select t.* from stu_row2col t ;

ID         INTNAME    SUBJECT                   GRADE

---------- ---------- -------------------- ----------

11         ZORRO      语文                         77

1          ZORRO      语文                         70

2          ZORRO      数学                         80

3          ZORRO      英语                         75

4          SEKER      语文                         65

5          SEKER      数学                         75

6          SEKER      英语                         60

7          BLUES      语文                         60

8          BLUES      数学                         90

9          PG         数学                         80

10         PG         英语                         90

想要实现行专列， 就是输出结果是这样的：

SQL>  select * from ( select t.intname,t.subject,t.grade from stu_row2col t)

pivot(sum(grade) for subject in ('语文' 语文,'数学' 数学,'英语' 英语))  ;

INTNAME            语文         数学         英语

---------- ---------- ---------- ----------

SEKER              65         75         60

BLUES              60         90

PG                            80         90

ZORRO             147         80         75

二、    行    转    列

创建一个视图：

create or replace view stu_col2row as

select "INTNAME","语文","数学","英语" from ( select t.intname,t.subject,t.grade from stu_row2col t) pivot(sum(grade) for subject in ('语文' 语文,'数学' 数学,'英语' 英语));

SQL>  select INTNAME 姓名,km 科目, fs 分数 from stu_col2row unpivot(fs for km in(语文,数学,英语));

姓名       科目         分数

---------- ---- ----------

SEKER      语文         65

SEKER      数学         75

SEKER      英语         60

BLUES      语文         60

BLUES      数学         90

PG         数学         80

PG         英语         90

ZORRO      语文         70

ZORRO      数学         80

ZORRO      英语         75