在数据库遇到性能问题的时候，可能从io,cpu等角度能够下手找到性能瓶颈，日志的切换也是影响性能的一个因素，如果日志切换台频繁，等待时间就会在日志相关的事件上,从数据库的角度来说，肯定是io的瓶颈。

可以通过如下的shell脚本来得到一个简单的报告。

脚本如下：

sqlplus -s $DB_CONN_STR@$SH_DB_SID<

set linesize    150

set pages       100

set feedback    off

set verify      off

col dbname      new_value dbname

col time_stamp  new_value time_stamp

col timestamp_np        noprint

col year_np             noprint

col month_np            noprint

col mon                 for a3

col day                 for a2

ttitle off

SELECT name dbname, substr(to_char(sysdate,'YYYY-Mon-DD HH24:MI:SS'),1,20)

time_stamp

FROM v\$database

/

col bytes format 9,999,999,999,999

col member format a60

select group#,thread#,sequence#,members,bytes/1024/1024 size_MB,archived,status

from v\$log order by 1,2;

ttitle left "Redo Switch times per hour" center "&dbname" right "&time_stamp"

set term on

col tps00 for 999 head "00"

col tps01 for 999 head "01"

col tps02 for 999 head "02"

col tps03 for 999 head "03"

col tps04 for 999 head "04"

col tps05 for 999 head "05"

col tps06 for 999 head "06"

col tps07 for 999 head "07"

col tps08 for 999 head "08"

col tps09 for 999 head "09"

col tps10 for 999 head "10"

col tps11 for 999 head "11"

col tps12 for 999 head "12"

col tps13 for 999 head "13"

col tps14 for 999 head "14"

col tps15 for 999 head "15"

col tps16 for 999 head "16"

col tps17 for 999 head "17"

col tps18 for 999 head "18"

col tps19 for 999 head "19"

col tps20 for 999 head "20"

col tps21 for 999 head "21"

col tps22 for 999 head "22"

col tps23 for 999 head "23"

SELECT *

FROM

( SELECT substr(year_np,1,8)  timestamp_np,

substr(year_np,5,2) Mon, substr(year_np,7,2) Day,

sum(decode(substr(year_np,9,2),'00',cnt,0))   tps00,

sum(decode(substr(year_np,9,2),'01',cnt,0))   tps01,

sum(decode(substr(year_np,9,2),'02',cnt,0))   tps02,

sum(decode(substr(year_np,9,2),'03',cnt,0))   tps03,

sum(decode(substr(year_np,9,2),'04',cnt,0))   tps04,

sum(decode(substr(year_np,9,2),'05',cnt,0))   tps05,

sum(decode(substr(year_np,9,2),'06',cnt,0))   tps06,

sum(decode(substr(year_np,9,2),'07',cnt,0))   tps07,

sum(decode(substr(year_np,9,2),'08',cnt,0))   tps08,

sum(decode(substr(year_np,9,2),'09',cnt,0))   tps09,

sum(decode(substr(year_np,9,2),'10',cnt,0))   tps10,

sum(decode(substr(year_np,9,2),'11',cnt,0))   tps11,

sum(decode(substr(year_np,9,2),'12',cnt,0))   tps12,

sum(decode(substr(year_np,9,2),'13',cnt,0))   tps13,

sum(decode(substr(year_np,9,2),'14',cnt,0))   tps14,

sum(decode(substr(year_np,9,2),'15',cnt,0))   tps15,

sum(decode(substr(year_np,9,2),'16',cnt,0))   tps16,

sum(decode(substr(year_np,9,2),'17',cnt,0))   tps17,

sum(decode(substr(year_np,9,2),'18',cnt,0))   tps18,

sum(decode(substr(year_np,9,2),'19',cnt,0))   tps19,

sum(decode(substr(year_np,9,2),'20',cnt,0))   tps20,

sum(decode(substr(year_np,9,3),'21',cnt,0))   tps21,

sum(decode(substr(year_np,9,3),'22',cnt,0))   tps22,

sum(decode(substr(year_np,9,2),'23',cnt,0))   tps23

FROM (SELECT to_char(first_time,'YYYYMMDDHH24') year_np,count(*) cnt

FROM v\$log_history where first_time>sysdate -15

GROUP BY to_char(first_time,'YYYYMMDDHH24')

)

GROUP BY substr(year_np,1,8), substr(year_np,5,2), substr(year_np,7,2)

)

ORDER BY timestamp_np

/

<

exit;

来自 “ ITPUB博客 ” ，链接：http://blog.itpub.net/23718752/viewspace-1176479/，如需转载，请注明出处，否则将追究法律责任。