1.输入1-127的ascii码并输出对应字符

#-*-coding:UTF-8-*-

for i in range(0,128):

print chr(i)

2.输入a，b，c，d4个整数，计算a+b-c*d的结果

#-*-coding:UTF-8-*-

a=int(raw_input ("please input number a: "))

b=int(raw_input ("please input number b: "))

c=int(raw_input ("please input number c: "))

d=int(raw_input ("please input number d: "))

result=a+b-c*d

print result

3.计算一周有多少分钟、多少秒钟

#-*-coding:UTF-8-*-

minutes=7*60*24

print("There are %d minutes in one week" % (minutes))

senconds=7*24*60*60

print("There are %d senconds in one week" % (senconds))

4.3个人在餐厅吃饭，想分摊饭费。总共花费35.27美元，他们还想给15%的小费。每个人该怎么付钱，编程实现

#-*-coding:UTF-8-*-

money=35.27*1.15

everone=money/3

print ("everyone should give %f money" % (everone))

5.计算一个12.5m X 16.7m的矩形房间的面积和周长

#-*-coding:UTF-8-*-

length=12.5

width=16.7

area=length*width

print ("the area is %f" % (area))

perimeter=2*length+2*width

print ("the perimeter is %f" % (perimeter))

6.怎么得到9 / 2的小数结果

#-*-coding:UTF-8-*-

a=9.00

b=2.00

result=a/b

print ("the result is %f" % (result))

7.python计算中7 * 7 *7 * 7，可以有多少种写法

#-*-coding:UTF-8-*-

result1=7*7*7*7

print result1

import math

result2=math.pow(7,4)

print result2

result3=1

for i in range(1,5):

result3=result3*7

print result3

8.写程序将温度从华氏温度转换为摄氏温度。转换公式为C = 5 / 9*(F - 32)

#-*-coding:UTF-8-*-

fahrenheit=int(raw_input("please input the Fahrenheit: "))

celsius=(fahrenheit-32)*5/9

print ("it is %f celsius" %(celsius))

9.一家商场在降价促销。如果购买金额50-100元(包含50元和100元)之间，会给10%的折扣，如果购买金额大于100元会给20%折扣。编写一程序，询问购买价格，再显示出折扣(10%或20%)和最终价格。

#一家商场在降价促销。如果购买金额50-100元(包含50元和100元)之间，会给10%的折扣，如果购买金额大于100元会给20%折扣。编写一程序，询问购买价格，再显示出折扣(10%或20%)和最终价格

#-*-coding:UTF-8-*-

price=int(raw_input("please input the price: "))

after_price=0

if price>=50 and price<=100:

after_price=price*(1-0.1)

elif price>100:

after_price=price*(1-0.2)

else:

after_price=price

print ("the price is %f." %(after_price))

10.判断一个数n能否同时被3和5整除

#-*-coding:UTF-8-*-

number=int(raw_input("please input a number: "))

if number%3==0 and number%5==0:

print ("this number %d can be divisible by 3 and 5." %(number))

else:

print ("this number %d can't be divisible by 3 and 5." %(number))

11.求1 + 2 + 3 +….+100

#-*-coding:UTF-8-*-

result=0

for i in range (1,101):

result=result+i;

i=i+1;

print result

12交换两个变量的值

#-*-coding:UTF-8-*-

x=int(raw_input("please input the number x:"))

y=int(raw_input("please input the number y:"))

tmp=x

x=y

y=tmp

print x,y

a=int(raw_input("please input the number a:"))

b=int(raw_input("please input the number b:"))

a,b = b,a

print a,b

13一个足球队在寻找年龄在10到12岁的小女孩(包括10岁和12岁)加入。编写一个程序，询问用户的性别(m表示男性，f表示女性)和年龄，然后显示一条消息指出这个人是否可以加入球队，询问10次后，输出满足条件的总人数。

#-*-coding:UTF-8-*-

result=0

for i in range(1,11):

sex = raw_input("please input your gender:input f for girl,input m for boy: ")

age = int(raw_input("please input your age: "))

if sex == "f" and 10<=age<=12:

print "welcome!you can join the team."

result+=1

else:

print "sorry you can't join the team"

print ("it is %d can join the team" %(result))

14 长途旅行中，刚到一个加油站，距下一个加油站还有200km，而且以后每个加油站之间距离都是200km。编写一个程序确定是不是需要在这里加油，还是可以等到接下来的第几个加油站再加油。 程序询问以下几个问题： 1)你车的油箱多大，单位升 2)目前油箱还剩多少油，按百分比算，比如一半就是0.5 3)你车每升油可以走多远(km) 提示： 油箱中包含5升的缓冲油，以防油表不准。

#-*-coding:UTF-8-*-

capacity=int(raw_input("please input your car's capacity: "))

percentage=float(raw_input("please input your gas liter remaining percentage now: "))

speed=int(raw_input("please input 1 L gas can run how many km: "))

n=int((capacity*percentage*speed-5)/200)

if capacity*percentage<5:

print "you need add gas here"

elif n==0:

print "you need add gas here"

else:

print ("you need add gas in %d gas station." %(n))

15 现有面包、热狗、番茄酱、芥末酱以及洋葱，数字显示有多少种订购组合，其中面包必订，0不订，1订，比如10000，表示只订购面包

#-*-coding:UTF-8-*-

num = 0

bread=1

if bool(bread):

for hotdog in range(0,2):

for ketchup in range(0,2):

for mustard in range(0,2):

for onion in range(0,2):

num = num + 1

print bread,hotdog,ketchup,mustard,onion

print num

16 基于上题：给出每种食物的卡路里(自定义)，再计算出每种组合总共的卡路里

#15 现有面包、热狗、番茄酱、芥末酱以及洋葱，数字显示有多少种订购组合，其中面包必订，0不订，1订，比如10000， 表示只订购面包

#16 基于上题：给出每种食物的卡路里(自定义)，再计算出每种组合总共的卡路里

#-*-coding:UTF-8-*-

total_calories = 0

bread_calories=int(raw_input("please input the bread calories: "))

hotdog_calories=int(raw_input("please input the hotdog calories: "))

ketchup_calories=int(raw_input("please input the ketchup calories: "))

mustard_calories=int(raw_input("please input the mustard calories: "))

onion_calories=int(raw_input("please input the onion calories: "))

cal1=0

cal2=0

cal3=0

cal4=0

cal5=0

bread=1

totalcalorie=0

if bool(bread):

cal1=bread_calories

for hotdog in range(0,2):

if hotdog==1:

cal2=hotdog_calories

else:

cal2=0

for ketchup in range(0,2):

if ketchup==1:

cal3=ketchup_calories

else:

cal3=0

for mustard in range(0,2):

if ketchup==1:

cal4=mustard_calories

else:

cal4=0

for onion in range(0,2):

if onion==1:

cal5=onion_calories

else:

cal5=0

totalcalorie=cal1+cal2+cal3+cal4+cal5

print bread,hotdog,ketchup,mustard,onion,totalcalorie

17输入5个名字，排序后输出

#-*-coding:UTF-8-*-

name_1 = raw_input("please input name_1:")

name_2 = raw_input("please input name_2:")

name_3 = raw_input("please input name_3:")

name_4 = raw_input("please input name_4:")

name_5 = raw_input("please input name_5:")

a = [name_1,name_2,name_3,name_4,name_5]

b = sorted(a)

print b

19输入一个正整数，输出其阶乘结果

#-*-coding:UTF-8-*-

n=int(raw_input("please input a number: "))

result=1

for n in range (1,n+1):

result=result*n

print result

20 计算存款利息 4种方法可选： 活期，年利率为r1； 一年期定息，年利率为r2； 存两次半年期定期，年利率为r3 两年期定息，年利率为r4 现有本金1000元，请分别计算出一年后按4种方法所得到的本息和。 提示：本息= 本金+ 本金* 年利率* 存款期

#-*-coding:UTF-8-*-

money=1000

r1=0.02

money1=1000*(1+r1)

r2=0.03

money2=1000*(1+r2)

r3=0.04

money3=1000*(1+r3)

r4=0.06

money4=1000*(1+r4)

print money1,money2,money3,money4

21输入3个数字，以逗号隔开，输出其中最大的数

num=raw_input ("please input three number split by , :")

num2=num.split(',')

print num2

max_number=max(num2)

print max_number

22输入一个年份，输出是否为闰年 是闰年的条件： 能被4整数但不能被100整除，或者能被400整除的年份都是闰年。

#-*-coding:UTF-8-*-

year=int(raw_input("please input a year: "))

if year%4==0 and year%100!=0 or year%400==0:

print "this is leap year!"

else:

print "this is not leap year!"

23求两个正整数m和n的最大公约数

#-*-coding:UTF-8-*-

m=int(raw_input("please input number m: "))

n=int(raw_input("please input number n: "))

result=[]

x=0

if m>n:

x=n

else:

x=m

for i in range (1,x):

if m%i==0 and n%i==0:

result.append(i)

print result

b=sorted(result)

print b[-1]