五、pygame做一个简单的五子棋游戏

1.设置棋盘

五子棋标准棋盘是15x15的，如果我们每个格子的大小是40x40的话，棋盘应该是40x(15-1)=560的宽度，我们在四面各保留60的边距，那么窗口的长宽各是40x(15-1)+60x2

# -*- coding=utf-8 -*-
import random
import pygame
pygame.init()space = 60 # 四周留下的边距
cell_size = 40 # 每个格子大小
cell_num = 15
grid_size = cell_size * (cell_num - 1) + space * 2 # 棋盘的大小
screencaption = pygame.display.set_caption('FIR')
screen = pygame.display.set_mode((grid_size,grid_size)) #设置窗口长宽while True:for event in pygame.event.get():if event.type == pygame.QUIT:pygame.quit()exit()screen.fill((0,0,150)) # 将界面设置为蓝色for x in range(0,cell_size*cell_num,cell_size):pygame.draw.line(screen,(200,200,200),(x+space,0+space),(x+space,cell_size*(cell_num-1)+space),1)for y in range(0,cell_size*cell_num,cell_size):pygame.draw.line(screen,(200,200,200),(0+space,y+space),(cell_size*(cell_num-1)+space,y+space),1)pygame.display.update() # 必须调用update才能看到绘图显示

2.落子

首先我们定义一个chess_arr数组用于存储落到棋盘上的棋子

chess_arr = []

然后在游戏主循环监听下鼠标弹起事件，然后在捕捉到鼠标弹起事件时获取鼠标位置并把位置添加进chess_arr

for event in pygame.event.get():……if event.type == pygame.MOUSEBUTTONUP: # 鼠标弹起x, y = pygame.mouse.get_pos() # 获取鼠标位置chess_arr.append((x,y))

最后我们在pygame.display.update()前将棋子绘制出来看看效果

可以看到，现在已经能点出棋子了，但是棋子的位置不是纵横线的交叉点，所以我们必须对鼠标位置进行取整，不能把x,y这个位置加的这么随意，处理下x,y位置的代码如下

for event in pygame.event.get():……if event.type == pygame.MOUSEBUTTONUP: # 鼠标弹起x, y = pygame.mouse.get_pos() # 获取鼠标位置xi = int(round((x - space)*1.0/cell_size)) # 获取到x方向上取整的序号yi = int(round((y - space)*1.0/cell_size)) # 获取到y方向上取整的序号if xi>=0 and xi<cell_num and yi>=0 and yi<cell_num:chess_arr.append((xi*cell_size+space,yi*cell_size+space))

现在发现落子位置靠谱多了

为了代码的可读性更好点，以后一些棋盘计算更方便，我们把放入chess_arr数组的绝对坐标改成放入的是格子的序号，也就是把

 chess_arr.append((xi*cell_size+space,yi*cell_size+space))

改成

chess_arr.append((xi,yi))

然后在画棋子的地方也稍作修改，把

pygame.draw.circle(screen,(205,205,205), [x, y], 16,16)

改成

pygame.draw.circle(screen,(205,205,205), [x*cell_size+space, y*cell_size+space], 16,16)

接下来还有个问题，因为进到chess_arr数组前并没有判断某一位置是否已经有棋子，存在重复落子的情况，所以这边还要多加个判断，因为python语言够强大，可以直接判断是否包含tuple或者数组，所以只要多加一个(xi,yi) not in chess_arr的判断就好了，开不开森~

    for event in pygame.event.get():……if event.type == pygame.MOUSEBUTTONUP: # 鼠标弹起……if xi>=0 and xi<cell_num and yi>=0 and yi<cell_num and (xi,yi) not in chess_arr:chess_arr.append((xi,yi))

为免代码偏差，先更新下目前的完整代码

# -*- coding=utf-8 -*-
import random
import pygame
from pygame.locals import MOUSEBUTTONUP
pygame.init()space = 60 # 四周留下的边距
cell_size = 40 # 每个格子大小
cell_num = 15
grid_size = cell_size * (cell_num - 1) + space * 2 # 棋盘的大小
screencaption = pygame.display.set_caption('FIR')
screen = pygame.display.set_mode((grid_size,grid_size)) #设置窗口长宽chess_arr = []while True:for event in pygame.event.get():if event.type == pygame.QUIT:pygame.quit()exit()if event.type == pygame.MOUSEBUTTONUP: # 鼠标弹起x, y = pygame.mouse.get_pos() # 获取鼠标位置xi = int(round((x - space)*1.0/cell_size)) # 获取到x方向上取整的序号yi = int(round((y - space)*1.0/cell_size)) # 获取到y方向上取整的序号if xi>=0 and xi<cell_num and yi>=0 and yi<cell_num and (xi,yi) not in chess_arr:chess_arr.append((xi,yi))screen.fill((0,0,150)) # 将界面设置为蓝色for x in range(0,cell_size*cell_num,cell_size):pygame.draw.line(screen,(200,200,200),(x+space,0+space),(x+space,cell_size*(cell_num-1)+space),1)for y in range(0,cell_size*cell_num,cell_size):pygame.draw.line(screen,(200,200,200),(0+space,y+space),(cell_size*(cell_num-1)+space,y+space),1)for x, y in chess_arr:pygame.draw.circle(screen,(205,205,205), [x*cell_size+space, y*cell_size+space], 16,16)pygame.display.update() # 必须调用update才能看到绘图显示

3.区分黑白子

这里常规的想法可能有这么两种：1.chess_arr理论应该是黑白相间的，一个隔一个不同颜色画就好了（这种在不考虑正规比赛五手两打或者让子的情况下是没问题的） 2.往chess_arr里填(x,y)时多填一个黑白标记改成(x,y,flag) ，这里我们选择第二种方案
首先，我们全局定义个flag变量

flag = 1 # 1黑 2白

我们把

if xi>=0 and xi<cell_num and yi>=0 and yi<cell_num and (xi,yi) not in chess_arr:chess_arr.append((xi,yi))

这里改成

if xi>=0 and xi<cell_num and yi>=0 and yi<cell_num and (xi,yi,1) not in chess_arr and (xi,yi,2) not in chess_arr:chess_arr.append((xi,yi,flag))flag = 2 if flag == 1 else 2

再把画棋的

for x, y in chess_arr:pygame.draw.circle(screen,(205,205,205), [x*cell_size+space, y*cell_size+space], 16,16)

改成

for x, y, c in chess_arr:chess_color = (30,30,30) if c == 1 else (225,225,225)pygame.draw.circle(screen, chess_color, [x*cell_size+space, y*cell_size+space], 16,16)

现在看起来有点像那么回事了

4.判断输赢

判断输赢的关键当然还是使用chess_arr这个数组，这个数组用来判断胜利并不太方便，我们把它转一个15*15的二维数组来计算，转换代码如下

m = [[0]*15 for i in range(15)] # 先定义一个15*15的全0数组
for x, y, c in chess_arr:m[y][x] = 1 # 上面有棋则标1

我们把这代码一起放到一个check_win(chess_arr, flag)函数里，用于判断某一方是否胜利，基本流程是分别判断最后一颗落下的子的横线、竖线、斜线上是不是有5个以上子，有则返回True，函数代码如下：

def get_one_dire_num(lx, ly, dx, dy, m):tx = lxty = lys = 0while True:tx += dxty += dyif tx < 0 or tx >= cell_num or ty < 0 or ty >= cell_num or m[ty][tx] == 0: return ss+=1def check_win(chess_arr, flag):m = [[0]*cell_num for i in range(cell_num)] # 先定义一个15*15的全0的数组,不能用[[0]*cell_num]*cell_num的方式去定义因为一位数组会被重复引用for x, y, c in chess_arr:if c == flag:m[y][x] = 1 # 上面有棋则标1lx = chess_arr[-1][0] # 最后一个子的xly = chess_arr[-1][1] # 最后一个子的ydire_arr = [[(-1,0),(1,0)],[(0,-1),(0,1)],[(-1,-1),(1,1)],[(-1,1),(1,-1)]] # 4个方向数组,往左＋往右、往上＋往下、往左上＋往右下、往左下＋往右上，4组判断方向for dire1,dire2 in dire_arr:dx, dy = dire1num1 = get_one_dire_num(lx, ly, dx, dy, m)dx, dy = dire2num2 = get_one_dire_num(lx, ly, dx, dy, m)if num1 + num2 + 1 >= 5: return Truereturn False

判断函数完成了，我们再定一个全局变量用于保存游戏状态

game_state = 1 # 游戏状态1.表示正常进行 2.表示黑胜 3.表示白胜

我们在鼠标添加棋子的代码后面做下修改，调用判断胜利的函数

                 if check_win(chess_arr, flag):game_state = 2 if flag == 1 else 3else:flag = 2 if flag == 1 else 1

最后在pygame.display.update()前加个游戏状态判断，用于显示获胜文字

    if game_state != 1:myfont = pygame.font.Font(None,60)white = 210,210,0win_text = "%s win"%('black' if game_state == 2 else 'white')textImage = myfont.render(win_text, True, white)screen.blit(textImage, (260,320))

另外，鼠标事件判断处也要做下修改，判断下游戏状态是不是游戏中

if game_state == 1 and event.type == pygame.MOUSEBUTTONUP: # 鼠标弹起

至此主要的代码都完整了，下面是效果图

最后贴下完整程序，这边没有做禁手的判断和判输，后面有时间再处理

# -*- coding=utf-8 -*-
import random
import pygame
from pygame.locals import MOUSEBUTTONUP
pygame.init()space = 60 # 四周留下的边距
cell_size = 40 # 每个格子大小
cell_num = 15
grid_size = cell_size * (cell_num - 1) + space * 2 # 棋盘的大小
screencaption = pygame.display.set_caption('FIR')
screen = pygame.display.set_mode((grid_size,grid_size)) #设置窗口长宽chess_arr = []
flag = 1 # 1黑 2白
game_state = 1 # 游戏状态1.表示正常进行 2.表示黑胜 3.表示白胜def get_one_dire_num(lx, ly, dx, dy, m):tx = lxty = lys = 0while True:tx += dxty += dyif tx < 0 or tx >= cell_num or ty < 0 or ty >= cell_num or m[ty][tx] == 0: return ss+=1def check_win(chess_arr, flag):m = [[0]*cell_num for i in range(cell_num)] # 先定义一个15*15的全0的数组,不能用[[0]*cell_num]*cell_num的方式去定义因为一位数组会被重复引用for x, y, c in chess_arr:if c == flag:m[y][x] = 1 # 上面有棋则标1lx = chess_arr[-1][0] # 最后一个子的xly = chess_arr[-1][1] # 最后一个子的ydire_arr = [[(-1,0),(1,0)],[(0,-1),(0,1)],[(-1,-1),(1,1)],[(-1,1),(1,-1)]] # 4个方向数组,往左＋往右、往上＋往下、往左上＋往右下、往左下＋往右上，4组判断方向for dire1,dire2 in dire_arr:dx, dy = dire1num1 = get_one_dire_num(lx, ly, dx, dy, m)dx, dy = dire2num2 = get_one_dire_num(lx, ly, dx, dy, m)if num1 + num2 + 1 >= 5: return Truereturn Falsewhile True:for event in pygame.event.get():if event.type == pygame.QUIT:pygame.quit()exit()if game_state == 1 and event.type == pygame.MOUSEBUTTONUP: # 鼠标弹起x, y = pygame.mouse.get_pos() # 获取鼠标位置xi = int(round((x - space)*1.0/cell_size)) # 获取到x方向上取整的序号yi = int(round((y - space)*1.0/cell_size)) # 获取到y方向上取整的序号if xi>=0 and xi<cell_num and yi>=0 and yi<cell_num and (xi,yi,1) not in chess_arr and (xi,yi,2) not in chess_arr:chess_arr.append((xi,yi,flag))if check_win(chess_arr, flag):game_state = 2 if flag == 1 else 3else:flag = 2 if flag == 1 else 1screen.fill((0,0,150)) # 将界面设置为蓝色for x in range(0,cell_size*cell_num,cell_size):pygame.draw.line(screen,(200,200,200),(x+space,0+space),(x+space,cell_size*(cell_num-1)+space),1)for y in range(0,cell_size*cell_num,cell_size):pygame.draw.line(screen,(200,200,200),(0+space,y+space),(cell_size*(cell_num-1)+space,y+space),1)for x, y, c in chess_arr:chess_color = (30,30,30) if c == 1 else (225,225,225)pygame.draw.circle(screen, chess_color, [x*cell_size+space, y*cell_size+space], 16,16)if game_state != 1:myfont = pygame.font.Font(None,60)white = 210,210,0win_text = "%s win"%('black' if game_state == 2 else 'white')textImage = myfont.render(win_text, True, white)screen.blit(textImage, (260,320))pygame.display.update() # 必须调用update才能看到绘图显示