遇到一个难题，须要将单列数据根据分列显示，须要用到Pivot语法。html

参照现有的query，写了一段相似如下script片断的sql语句，问题搞定。经验总结：能用SQL搞定的问题，就不要人工去处理(效率低、易出错)。sql

OCD

AS

(

SELECT *

FROM (

SELECT DISTINCT

ra.HDP_ID,

'OCD' || CAST(ROW_NUMBER() OVER(PARTITION BY ra.HDP_ID

ORDER BY ra.HRA_ID desc) AS VARCHAR(10)) Seq,

p.PN_ID AS TNID,

p.PERSON_FULL_NAME AS OCD

FROM HDDO.HRA_V ra,

HDDO.PERSON_V p

WHERE p.HP_ID = ra.HP_ID

AND ra.CONTACT_ROLE = 'OCD'

)

PIVOT (

MAX(TNID) as TNID,

MAX(OCD)

FOR Seq in('OCD1' AS OCD1, 'OCD2' AS OCD2, 'OCD3' AS OCD3,'OCD4' AS OCD4,'OCD5' AS OCD5)

)

),

-----------------------------------------------------------------------------------------------------------------------------------

oracle

Pivot

Present information in a spreadsheet-type crosstab report from any relational table using simple SQL.app

Pivot

As you know, relational tables are, well, tabular—that is, they are presented in a column-value pair. Consider the case of a table named CUSTOMERS.ui

SQL> desc customers

Name Null? Type

----------------------------------------- -------- ---------------------------

CUST_ID NUMBER(10)

CUST_NAME VARCHAR2(20)

STATE_CODE VARCHAR2(2)

TIMES_PURCHASED NUMBER(3)

When this table is selected: this

select cust_id, state_code, times_purchased

from customers

order by cust_id;

The output is: spa

CUST_ID STATE_CODE TIMES_PURCHASED

------- ---------- ---------------

1 CT 1

2 NY 10

3 NJ 2

4 NY 4

...

and so on ...

Note how the data is represented as rows of values: For each customer, the record shows the customer's home state and how many times the customer purchased something from the store. As the customer purchases more items from the store, the column times_purchased is updated.

rest

Now consider a case where you want to have a report of the purchase frequency each state - that is, how many customers bought something only once, twice, thrice and so on, from each state. In regular SQL, you can issue the following statement:

select state_code, times_purchased, count(1) cnt

from customers

group by state_code, times_purchased;

Here is the output:

ST TIMES_PURCHASED CNT

-- --------------- ----------

CT 0 90

CT 1 165

CT 2 179

CT 3 173

CT 4 173

CT 5 152

...

and so on ...

This is the information you want but it's a little hard to read. A better way to represent the same data may be through the use of crosstab reports, in which you can organized the data vertically and states horizontally, just like a spreadsheet:

Times_purchased

CT NY NJ ...

and so on ...

1 0 1 0 ...

2 23 119 37 ...

3 17 45 1 ...

...

and so on ...

Prior to Oracle Database 11g, you would do that via some sort of a decode function for each value and write each distinct value as a separate column. The technique is quite nonintuitive however.

Fortunately, you now have a great new feature called PIVOT for presenting any query in the crosstab format using a new operator, appropriately named pivot. Here is how you write the query:

select * from (

select times_purchased, state_code

from customers t

)

pivot

(

count(state_code)

for state_code in ('NY','CT','NJ','FL','MO')

)

order by times_purchased

/

Here is the output:

. TIMES_PURCHASED 'NY' 'CT' 'NJ' 'FL' 'MO'

--------------- ---------- ---------- ---------- ---------- ----------

0 16601 90 0 0 0

1 33048 165 0 0 0

2 33151 179 0 0 0

3 32978 173 0 0 0

4 33109 173 0 1 0

... and so on ...

This shows the power of the pivot operator. The state_codes are presented on the header row, instead of a column. Pictorially, here is the how the traditional tabular format looks:

Figure 1 Traditional tabular representation

In a crosstab report, you want to transpose the Times Purchased column to the header row as shown in Figure 2. The column becomes the row, as if the column were rotated 90 degrees anti-clockwise to become the header row. This figurative rotation needs to have a pivot point and in this case the pivot point happens to be the count(state_code) expression.

Figure 2 Pivoted representation

This expression needs to be in the syntax of the query:

...

pivot

(

count(state_code)

for state_code in ('NY','CT','NJ','FL','MO')

)

...

The second line, "for state_code ...," limits the query to only those values. This line is necessary, so unfortunately you have to know the possible values beforehand. This restriction is relaxed in the XML format of the query, described later in this article.

Note the header rows in the output:

. TIMES_PURCHASED 'NY' 'CT' 'NJ' 'FL' 'MO'

--------------- ---------- ---------- ---------- ---------- ----------

The column headers are the data from the table itself: the state codes. The abbreviations may be self explanatory but suppose you want to display the state names instead of abbreviations, ("Connecticut" instead of "CT")? In that case you have to make a little adjustment in the query, in the FOR clause as shown below:

select * from (

select times_purchased as "Puchase Frequency", state_code

from customers t

)

pivot

(

count(state_code)

for state_code in ('NY' as "New York",'CT' "Connecticut",'NJ' "New Jersey",'FL' "Florida",'MO' as "Missouri")

)

order by 1

/

Puchase Frequency New York Connecticut New Jersey Florida Missouri

----------------- ---------- ----------- ---------- ---------- ----------

0 16601 90 0 0 0

1 33048 165 0 0 0

2 33151 179 0 0 0

3 32978 173 0 0 0

4 33109 173 0 1 0

...

and so on ...

The FOR clause can have aliases for the values there, which will become the column headers.