CF1062D Fun with Integers

思路：

找规律。

实现：

 1 #include <bits/stdc++.h>
 2 using namespace std;
 3 typedef long long ll;
 4 int main()
 5 {
 6     ll n;
 7     while (cin >> n)
 8     {
 9         ll cnt = 0;
10         for (int i = 2; i * i <= n; i++)
11         {
12             ll tmp = n / i;
13             cnt += (i + 1 + tmp) * (tmp - i) / 2;
14             cnt += (tmp - i + 1) * i;
15         }
16         cout << (cnt << 2) << endl;
17     }
18     return 0;
19 }

转载于:https://www.cnblogs.com/wangyiming/p/9977600.html

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