答案和评论是完美的，我想补充一点，你可以通过将字符代码移动8272轻松地将数字转换为下标，这对应于“0”(代码8320)的字符代码与为“0”(代码48)。

例如：

var text = "N1234567890";

function subNums(str)

{

var newStr = "";

for (var i=0; i

{

// Get the code of the current character

var code = str.charCodeAt(i);

if (code >= 48 && code <= 57)

{

// If it's between "0" and "9", offset the code ...

newStr += String.fromCharCode(code + 8272);

}

else

{

// ... otherwise keep the character

newStr += str[i];

}

}

return newStr

}

// Get the context

var ctx = document.getElementById('myCanvas').getContext('2d');

// Write the string

ctx.font = "20px serif";

ctx.fillText(text, 0, 20);

ctx.fillText(subNums(text), 0, 40);

这显然只是一个将所有数字转换为下标的快速示例，而不一定是您一直想要的数字！

更有用的可能是直接将数值转换为下标，您可以遍历所有数字并创建一个字符串，其字符在“0”(代码8320)和“₉”(代码8329)之间：

// Numerical value to use as subscript

// Don't start it with 0 otherwise it will be read as an octal value!

var index = 1234567890;

function toSub(value)

{

var str = "";

// Get the number of digits, with a minimum at 0 in case the value itself is 0

var mag = Math.max(0, Math.floor(Math.log10(value)));

// Loop through all digits

while (mag >= 0)

{

// Current digit's value

var digit = Math.floor(value/Math.pow(10, mag))%10;

// Append as subscript character

str += String.fromCharCode(8320 + digit);

mag--;

}

return str;

}

// Get the context

var ctx = document.getElementById('myCanvas').getContext('2d');

// Write the string

ctx.font = "20px serif";

ctx.fillText("N" + index, 0, 20);

ctx.fillText("N" + toSub(index), 0, 40);