LeetCode - Reverse Bits

二进制转换和字符串逆序。要考虑int的范围，测试数据是有溢出的。Math.pow是有精度损失的，最好写成整数的。

public class ReverseBits {public static int reverseBits(int n) {StringBuilder sb = new StringBuilder(Integer.toBinaryString(n));StringBuilder s = new StringBuilder(sb.reverse());if(s.length()!=32) {while(s.length() != 32) {s.append("0");}}//System.out.println(s);int ans = 0;for(int i=s.length()-1; i>=0; i--) {if(s.charAt(i) == '1') {//System.out.println(s.length()-1-i);ans += pow(2, s.length()-1-i);}}return ans;}public static int pow(int n, int m) {int ans = 1;for(int i=0; i<m; i++) {ans *= n;}ans = Math.abs(ans);return ans;}

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LeetCode - Reverse Bits

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