141.Linked List Cycle

class Solution {
public:bool hasCycle(ListNode *head) {ListNode *slow = head, *fast = head;while (fast && fast->next) {slow = slow->next;fast = fast->next->next;if (slow == fast) return true;}return false;}
};

转载于:https://www.cnblogs.com/smallredness/p/10681759.html

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