LeetCode 88. Merge Sorted Array

题目：
Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.

Note:
You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2. The number of elements initialized in nums1 and nums2 are m and n respectively.

思路：
数组nums1中有m个数，数组nums2中有n个数，nums1的空间大于m+n。
将nums2中的数拷贝到nums1中的m个数后面，然后调用sort(begin,end),sort方法懒得自己写了~

代码：

class Solution {
public:void merge(vector<int>& nums1, int m, vector<int>& nums2, int n) {int j=0;for(int i=m;i<m+n;++i){//将nums2中的数拷贝到nums1中的m个数后面nums1[i]=nums2[j++];}sort(nums1.begin(),nums1.end());//然后调用sort}
};

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