#include <iostream>
#include <cstdlib>
#include <cctype>
#include <string>
using namespace std;int myAtoi(const string &s){    //字符串转化为整数int n = 0;for(auto v : s){if(!isdigit(v)){   //如果不是数字字符cout << "Invalid string!" << endl;exit(EXIT_FAILURE);}}for(auto c : s)if(c >= '0' && c <= '9')  //进行转换n = 10 * n + (c - '0');return n;
}//分离字符串中整数部分和小数部分
void seperateString(string &first, string &last, const string s){for(int i = 0; s[i] != '.'; ++i) //获取整数部分first += s[i];for(auto i = s.find('.')+1; s[i] != '\0'; i++) //获取小数部分last += s[i];}int main(){cout << "Enter an amount in double, for example 11.56: ";string amount;cin >> amount;string intergerPart = "", remainderPart = "";   //整数部分和余数部分int numberOfOneDollars = 0;int remainingAmount = 0;if(amount.find('.') != amount.npos){ //如果包含小数部分seperateString(intergerPart, remainderPart, amount);numberOfOneDollars = myAtoi(intergerPart);remainingAmount = myAtoi(remainderPart);}else{    //如果不包含小数部分numberOfOneDollars = myAtoi(amount);remainingAmount = 0;}// find the number of quarters in the remaining amountint numberOfQuarters = remainingAmount / 25;remainingAmount = remainingAmount % 25;// find the number of dimes in the remaining amountint numberOfDimes = remainingAmount / 10;remainingAmount = remainingAmount % 10;// find the number of nickels in the remaining amountint numberOfNickels = remainingAmount / 5;remainingAmount = remainingAmount % 5;// find the number of pennies in the remaining amountint numberOfPennies = remainingAmount;// display resultscout << "Your amount " << amount << " consists of " << endl <<"  " << numberOfOneDollars << " dollars" << endl <<"  " << numberOfQuarters << " quarters" << endl <<"  " << numberOfDimes << " dimes" << endl <<"  " << numberOfNickels << " nickels" << endl <<"  " << numberOfPennies << " pennies" << endl;return 0;
}