Leet Code OJ 231. Power of Two [Difficulty: Easy]
题目：
Given an integer, write a function to determine if it is a power of two.
分析：
题意是给定一个整数，判断它是不是2的幂。
代码实现：
public class Solution {public boolean isPowerOfTwo(int n) {if(n<1){return false;}if(n==1){return true;}if((n&1)==0) {return isPowerOfTwo(n/2);} else{return false;}}
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