1 print(1>1 or 3<4 or 4>5 and 2>1 and 9>8 or 7<6)  #or 一个为Ture 结果Ture
 2 print(not 2 >1 and 3<4 or 4>5 and 2>1 and 9>8 or 7<6) # f
 3 print(1>2 and 3<4 or 4>5 and 2>1 or 9<8 and 4>6 or 3<2 ) #f
 4
 5 print(8 or 3 and 4 or 2 and 0 or 9 and 7) #8
 6 print(0 or 2 and 3 and 4 or 6 and 0 or 3) #4
 7 print( 4  or 3)  #4  #or x y    x or y   x 值为Ture不为0的话， 结果为x
 8 print(5 and 9 or 10 and 2 or 3 and 5 or 4 or 5)  #9
 9 print(6 or 2>1) #6
10 print(0 or 5< 4) #f
11 print(5<4 or 3) #3
12 print(2>1 or 6) #t
13 print(3 and 2>1) #t
14 print(2>1 and 0) #0
15 print(2>1 and 3) #3
16 print(3>1 and 2 or 2 <3 and 4 or 3>2) #2

1 func = lambda x:x+1
2 func(10)
3 print(func(10))    #输出11

1 name = ["alex","tom"]
2 for i in name:
3     fun=lambda x:x+"_sb"
4     print(fun(i))   #输出alex_sb   tom_sb

1 f =lambda x,y,z:(x+1,y+1)   #处理多个值时，要手动变成元祖格式
2 print(f(1,2,3))     

1 # map函数
2 nul = [1,2,3,4,5,6,7]
3 def map_test(func,array):   #func =lambda x:x+1  #array=[1,2,3,4,5,6,7]
4     ret=[]
5     for i in array:
6         res=func(i)      #调取函数
7         ret.append(res)
8     return ret
9 print(map_test(lambda x:x+1,nul))

1 ##############map使用################
2 nl = [1,2,3,4,5,6]
3 print(list(map(lambda x:x+1,nl)))
4 ll = "alex"
5 print(list(map(lambda x:x.upper(),ll)))

1 ln = ["alex_sb","tom","Jim"]
2 print(list(filter(lambda x:x.endswith("sb"),ln)))
3 print(list(filter(lambda x:not x.endswith("sb"),ln)))  #取结尾不含sb的人

1 #######过滤#########
2 people = 【
3     {“name”:"alex1","age":100} ,
4     {“name”:"alex2","age":1000} ,
5     {“name”:"alex3","age":10000} ,
6     {“name”:"alex4","age":18} ,
7 ]
8
9 print(list(filter(lambda p:p["age"]<=18,people)))

1 # reduce函数
2 from functools import reduce   #导入reduce函数模块
3 ln = [1,2,3,100]
4 print(reduce(lambda x,y:x*y,ln,100))     #100是指点一个基数（初始值）然后相乘

1 l = ["a","b","c","11"]
2 print(list(max(l)))
3
4 age_dic = {"alex_age":18,"tom_age":20,"zhangsan_age":22}
5 for i in zip(age_dic.values(),age_dic.keys()):
6     print(i)    #查看zip函数列出的元祖
7 print(list(max(zip(age_dic.values(),age_dic.keys()))))    

 1 people = [
 2     {"name":"alex","age":20},
 3     {"name":"tom","age":28},
 4     {"name":"zhangsan","age":30},
 5     {"name":"lisi","age":40}
 6 ]
 7 print(max(people,key=lambda dic:dic["age"]))
 8
 9 #max(people,key=lambda dic:dic["age"]) 这一行分解理解为以下for循环
10 ret =[]
11 for i in people:
12     ret.append(i["age"])
13 print(ret)
14 max(ret)

1 people = [
2     {"name":"alex","age":20},
3     {"name":"tom","age":28},
4     {"name":"zhangsan","age":30},
5     {"name":"lisi","age":40}
6 ]
7 print(sorted(people,key=lambda dic:dic["age"]))