oracle+生成+sql语句,Oracle使用SQL语句生成日历的实现方法

Oracle使用SQL语句可以实现日历的功能，下面就为您详细介绍Oracle使用SQL语句生成日历的实现方法，希望对您能有所帮助。

1 要构造某年某月的日历，必须先知道这个月的开始时间，结束时间及天数

开始日期例如 2006年11月

select to_date('20061101','yyyymmdd') as startDayOfMon from dual;

结束日期

select last_day(to_date('20061101','yyyymmdd')) as endDayOfMon from dual;

日期区间天数

select last_day(to_date('20061101','yyyymmdd')) - to_date('20061101','yyyymmdd') +1 as DayOfMon

from dual;

2 接下来就是需要得到开始时间到结束时间每一天的结果集

select * from (

select to_date('20061101','yyyymmdd') + level - 1 as everyDay from dual

connect by level<=

(last_day(to_date('20061101','yyyymmdd')) - to_date('20061101','yyyymmdd') +1));

3 再进一步则是将该月中的日期分解成第几周，星期几。

select everyDay,to_char(everyday,'yyyy') as 年,

to_char(everyday,'mm') as 月,

to_char(everyday,'dd') as 日,

to_char(everyday,'dy') as 星期几,

lpad(to_char(everyday,'w'),6) as 该月的第几周,

lpad(to_char(everyday,'ww'),6) as 该年的第几周

from(select to_date('20061101','yyyymmdd') + level - 1 as everyDay from dual

connect by level<=

(last_day(to_date('20061101','yyyymmdd')) - to_date('20061101','yyyymmdd') +1));

4 这个结果集求出来后,接下拉就是使用DECODE函数进行行列转换了

select everyDay,to_char(everyday,'yyyy') as 年,

to_char(everyday,'mm') as 月,

to_char(everyday,'dd') as 日,

to_char(everyday,'dy') as 星期几,

lpad(to_char(everyday,'w'),6) as 该月的第几周,

lpad(to_char(everyday,'ww'),6) as 该年的第几周,

lpad(decode(to_char(everyday,'dy'),'星期日',to_char(everyday,'dd')),3) as 星期日,

lpad(decode(to_char(everyday,'dy'),'星期一',to_char(everyday,'dd')),3) as 星期一,

lpad(decode(to_char(everyday,'dy'),'星期二',to_char(everyday,'dd')),3) as 星期二,

lpad(decode(to_char(everyday,'dy'),'星期三',to_char(everyday,'dd')),3) as 星期三,

lpad(decode(to_char(everyday,'dy'),'星期四',to_char(everyday,'dd')),3) as 星期四,

lpad(decode(to_char(everyday,'dy'),'星期五',to_char(everyday,'dd')),3) as 星期五,

lpad(decode(to_char(everyday,'dy'),'星期六',to_char(everyday,'dd')),3) as 星期六

from(select to_date('20061101','yyyymmdd') + level - 1 as everyDay from dual

connect by level<=

(last_day(to_date('20061101','yyyymmdd')) - to_date('20061101','yyyymmdd') +1));

5 再进一步就是统计汇总了,大家发现一个小问题没有？

就是该月的第几周这里是按本月开始是星期几为开始的日期，很有意思，

这样我们按该日是该年的第几周则是以今年开始日期是星期几为开始日期

select to_char(everyday,'w') as week,

sum(decode(to_char(everyday,'dy'),'星期日',to_char(everyday,'dd'))) as 星期日,

sum(decode(to_char(everyday,'dy'),'星期一',to_char(everyday,'dd'))) as 星期一,

sum(decode(to_char(everyday,'dy'),'星期二',to_char(everyday,'dd'))) as 星期二,

sum(decode(to_char(everyday,'dy'),'星期三',to_char(everyday,'dd'))) as 星期三,

sum(decode(to_char(everyday,'dy'),'星期四',to_char(everyday,'dd'))) as 星期四,

sum(decode(to_char(everyday,'dy'),'星期五',to_char(everyday,'dd'))) as 星期五,

sum(decode(to_char(everyday,'dy'),'星期六',to_char(everyday,'dd'))) as 星期六

from(select to_date('20061101','yyyymmdd') + level - 1 as everyDay

from dual

connect by level<= (last_day(to_date('20061101','yyyymmdd')) - to_date('20061101','yyyymmdd') +1)

)

group by to_char(everyday,'w');

6 以上日历基本成功，但还有一个问题，就是一周的开始时间问题

select to_char(everyday,'ww') as week,