C#复数类Complex的封装

----------------------------------------------------------------------------------------------------------------------------------------------------------本文作者：随煜而安  

时间：   二零一五年七月二十日

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本文给出使用C#语言对于复数类Complex的封装。包括大多数基本的运算及方法，个人感觉总结的蛮全的。话不多说，直接上代码！

/// <summary>/// 复数类/// </summary>public class Complex{#region 字段//复数实部private double real = 0.0;//复数虚部private double imaginary = 0.0;#endregion#region 属性/// <summary>/// 获取或设置复数的实部/// </summary>public double Real{get{return real;}set{real = value;}}/// <summary>/// 获取或设置复数的虚部/// </summary>public double Imaginary{get{return imaginary;}set{imaginary = value;}}#endregion#region 构造函数/// <summary>/// 默认构造函数，得到的复数为0/// </summary>public Complex():this(0,0){}/// <summary>/// 只给实部赋值的构造函数，虚部将取0/// </summary>/// <param name="dbreal">实部</param>public Complex(double dbreal):this(dbreal,0){}/// <summary>/// 一般形式的构造函数/// </summary>/// <param name="dbreal">实部</param>/// <param name="dbImage">虚部</param>public Complex(double dbreal, double dbImage){real = dbreal;imaginary = dbImage;}/// <summary>/// 以拷贝另一个复数的形式赋值的构造函数/// </summary>/// <param name="other">复数</param>public Complex(Complex other){real = other.real;imaginary = other.imaginary;}#endregion#region 重载//加法的重载public static Complex operator +(Complex comp1, Complex comp2){return comp1.Add(comp2);}//减法的重载public static Complex operator -(Complex comp1, Complex comp2){return comp1.Substract(comp2);}//乘法的重载public static Complex operator *(Complex comp1, Complex comp2){return comp1.Multiply(comp2);}//==的重载public static bool operator ==(Complex z1, Complex z2){return ((z1.real == z2.real) && (z1.imaginary == z2.imaginary));}//!=的重载public static bool operator !=(Complex z1, Complex z2){if (z1.real == z2.real){return (z1.imaginary != z2.imaginary);}return true;}/// <summary>/// 重载ToString方法,打印复数字符串/// </summary>/// <returns>打印字符串</returns>public override string ToString(){if (Real == 0 && imaginary == 0){return string.Format("{0}", 0);}if (Real == 0 && (imaginary != 1 && imaginary != -1)){return string.Format("{0} i", imaginary);}if (imaginary == 0){return string.Format("{0}", Real);}if (imaginary == 1){return string.Format("i");}if (imaginary == -1){return string.Format("- i");}if (imaginary < 0){return string.Format("{0} - {1} i", Real, -imaginary);}return string.Format("{0} + {1} i", Real, imaginary);}#endregion#region 公共方法/// <summary>/// 复数加法/// </summary>/// <param name="comp">待加复数</param>/// <returns>返回相加后的复数</returns>public Complex Add(Complex comp){double x = real + comp.real;double y = imaginary + comp.imaginary;return new Complex(x, y);}/// <summary>/// 复数减法/// </summary>/// <param name="comp">待减复数</param>/// <returns>返回相减后的复数</returns>public Complex Substract(Complex comp){double x = real - comp.real;double y = imaginary - comp.imaginary;return new Complex(x, y);}/// <summary>/// 复数乘法/// </summary>/// <param name="comp">待乘复数</param>/// <returns>返回相乘后的复数</returns>public Complex Multiply(Complex comp){double x = real * comp.real - imaginary * comp.imaginary;double y = real * comp.imaginary + imaginary * comp.real;return new Complex(x, y);}/// <summary>/// 获取复数的模/幅度/// </summary>/// <returns>返回复数的模</returns>public double GetModul(){return Math.Sqrt(real * real + imaginary * imaginary);}/// <summary>/// 获取复数的相位角，取值范围（-π，π]/// </summary>/// <returns>返回复数的相角</returns>public double GetAngle(){#region 原先求相角的实现，后发现Math.Atan2已经封装好后注释实部和虚部都为0//if (real == 0 && imaginary == 0)//{//    return 0;//}//if (real == 0)//{//    if (imaginary > 0)//        return Math.PI / 2;//    else//        return -Math.PI / 2;//}//else//{//    if (real > 0)//    {//        return Math.Atan2(imaginary, real);//    }//    else//    {//        if (imaginary >= 0)//            return Math.Atan2(imaginary, real) + Math.PI;//        else//            return Math.Atan2(imaginary, real) - Math.PI;//    }//}#endregionreturn Math.Atan2(imaginary, real);}/// <summary>/// 获取复数的共轭复数/// </summary>/// <returns>返回共轭复数</returns>public Complex Conjugate(){return new Complex(this.real, -this.imaginary);}#endregion}