shell 脚本实现乘法口诀表的两种方法——shell与C语言

话不多说直接给出代码(执行c语言时没有gcc编译器会报错的哦！)：

1 #!/bin/bash

2 if [ $# -eq 0 ]

3 then

4 echo "welcome you!"

5 echo "this is a test with 2 methods to output arbitrarily mux table!"

6 else

7 echo "sorry you input invliad argc!"

8 echo "you input other argc before!"

9 exit 0

10 fi

11

12 while ((1))

13 do

14 echo "you can choose 'shell' 'gcc' or 'quit' command"

15 read -p "please input your choice:" choice

16

17 if [ $choice == "shell" ]

18 then

19 echo "will do show shell"

20 read -p "please input a num you want:" num

21 touch 6.sh

22 echo "" > 6.sh

23 echo '#!/bin/bash

24 for ((j=1;j<=$1;j++))

25 do

26 for((i=1;i<=j;i++))

27 do

28 echo -ne "$i*$j=$[$i*$j]\t"

29 done

30 echo -e "\r"

31 done

32 ' >> 6.sh

33 chmod 777 6.sh

34 cat 6.sh

35 source 6.sh $num

36 exit 0

37 elif [ $choice == "gcc" ]

38 then

39 echo "will do show c"

40 touch 6.c

41 echo "" > 6.c

42 echo '#include

43

44

45

46

47 int main(int argc,char **argv)

48 { if(argc<2)

49 perror("argc num is not correct！please do it again!");

50 printf("%s\n",argv[1]);

51 int num;

52 num=atoi(argv[1]);

53 int i,j;

54 for (j=1;j<=num;j++)

55 {

56 for(i=1;i<=j;i++)

57 {

58 printf("%d*%d=%d\t",i,j,i*j);

59 }

60 printf("\n");

61 }

62

63 return 0;

64 }' >> 6.c

65 cat 6.c

66 #判断是否有安装gcc编译器

67 pName=$(rpm -qa | grep "$gcc")

68 if [ $? -eq 0]

69 then

70 echo "gcc had installed!"

71 else

72 echo "gcc is not installed!"

73 yum install -y gcc

74 fi

75 gcc -o 6 6.c

76 read -p "please input a number you want:" number

77 ./6 $number

78 exit 0

79 elif [ $choice == "quit" ]

80 then

81 exit 0

82 else

83 echo "you don't choose a correct choice!"

84 fi

85 done