UVA260 Il Gioco dell‘X【DFS】

The game ‘Il Gioco dell’ X’ is played on a N by N board (N ≥ 2). The object of both players, say Black and White, is to join opposite sides of the board by placing in turn their pawns on the board in such a way that a path is made from one side to the other by adjacent (neighboring) pawns of their own color. Although the board is N × N it is not a square but rather diamond-shaped. Let us denote the field on the board in row i and column j by (i, j) (1 ≤ i, j ≤ N). The neighbors of (i, j) are:
(i − 1, j − 1),(i − 1, j),(i, j − 1),(i, j + 1),(i + 1, j),(i + l, j + 1)
provided these fields do not fall outside the board.
    Black tries to join row 1 with row N, while White tries to join column 1 with column N.
    lt is a Deep Mathematical Result that this game cannot end in a draw (that is, without winner). As we will present to you only full boards, there will always be a winner. It may, however, be difficult to see who has won, so some computer assistance would be appreciated.
Examples:

    In example 1 White has won, and in example 2 Black has won.
Input
The input is a text file containing a number of games. Each game is given by: one line containing an integer N, being the number of rows. (N can he any number between 2 and 200). This line is followed by N lines, each consisting of a row of N characters from the set {‘b’,‘w’} denoting the pawns of Black and White respectively. The numbers of black and white pawns will differ by at most one. Note that all positions on the board are filled with pawns. The list of games ends with a single zero on a line of its own. (Of course, this is not a game for which a winner has to be determined.)
Output
The output will be a textfile containing one line for each game. This line should contain the number of the game (starting at 1) followed by a space, and followed by an uppercase ‘B’ if Black did win, or followed by an uppercase ‘W’ if White did win.
Sample Input
4
bbwb
wwbw
bbwb
bwww
4
bbwb
wwbw
bwwb
wwbb
0
Sample Output
1 W
2 B

问题链接：UVA260 Il Gioco dell’X
问题简述：两人轮流在n*n的平行四边形格子中放入黑白两色的棋子，如果黑色方能给创造一个从1~n行的连续线段则黑方胜，否则白方胜利。
问题分析：寻找从顶端到底端的解，黑白必有一方赢。用DFS来解决，也可以用Flood Fill算法来实现。
程序说明：（略）
参考链接：（略）
题记：（略）

AC的C++语言程序如下：

/* UVA260 Il Gioco dell'X */#include <bits/stdc++.h>using namespace std;const int dr[] = {-1, 0, 1, -1, 0, 1};
const int dc[] = {-1, -1, 0, 0, 1, 1};const int N = 200;
char b[N][N + 1];
int n;void dfs(int r, int c)
{if(r >= 0 && r < n && c >= 0 && c < n)if(b[r][c] == 'b') {b[r][c] = '1';for(int i = 0; i < 6; i++)dfs(r + dr[i], c + dc[i]);}
}int main()
{int k = 0;while(~scanf("%d", &n) && n) {for(int i = 0; i < n; i++)scanf("%s", b[i]);for(int i = 0; i < n; i++)if(b[0][i] == 'b') dfs(0, i);int flag = 0;for(int i = 0; i < n; i++)if(b[n - 1][i] == '1') {flag = 1;break;}printf("%d %c\n", ++k, flag ? 'B' : 'W');}return 0;
}

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