我有一个User集合，如下所示：

User :{

"_id" : ObjectId("59f6dc660a975a3e3290ea01"),

"basicInfo" : {

"name" : "xxxx",

"age" : 27,

"gender" : "Male"

}

"otherInfo" {

"projects" : [

{

"_id" : ObjectId("59f6f9230a975a67cc7d7638"),

"name" : "Test Project",

"projectImage" : "images/project/59f6f9230a975a67cc7d7638.jpg",

"desc" : "This is a testing project",

"status" : "Active",

"verifyDet" : {

"method" : "Admin",

"status" : "PENDING",

"isVerified" : false

}

},

{

"_id" : ObjectId("59f6f9230a975a67cc7d5556"),

"name" : "Test Project Two",

"projectImage" : "images/project/59f6f9230a975a67cc7d5556.jpg",

"desc" : "This is a testing project",

"status" : "Closed",

"verifyDet" : {

"method" : "Admin",

"status" : "APPROVED",

"isVerified" : true

}

}

]

}

}

注意：一个用户可以成为多个项目的一部分 . 但他需要得到Admin的批准才能参与项目活动 . 验证由verifyDet管理，项目由projects数组管理 .

实际要求是以这样的方式显示成员列表：具有待验证的成员按字母顺序排在最前面，然后按字母顺序向管理员批准/验证成员 .

当我在mongo shell上运行以下查询时，我得到的用户列表只有一个项目详细信息(_id = 59f6f9230a975a67cc7d7638)，我想要搜索并按验证待定用户和用户名排序结果 . 结果恰如其分 .

db.User.aggregate(

{$unwind:"$otherInfo.projects"},

{

$match:{

"otherInfo.projects._id":ObjectId("59f6f9230a975a67cc7d7638"),

"otherInfo.projects.status":"Active"

}

},

{$group: {_id: {"_id":"$_id", "basicInfo":"$basicInfo"}, "projects": {$push: "$otherInfo.projects"}}},

{$project:{"_id":"$_id._id", "basicInfo":"$_id.basicInfo", "otherInfo.projects":"$projects"}},

{$sort:{"otherInfo.projects.verifyDet.isVerified":1, "basicInfo.name":1}}

)

但是当我在Spring中创建相同的聚合时，如下所述，我得到例外：

public List fetchUsersList(String projectId, Pageable pageable) {

//unwind operation

AggregationOperation unwindOp = Aggregation.unwind("$otherInfo.projects");

Criteria criteria = Criteria.where("otherInfo.projects._id").is(new ObjectId(projectId));

criteria.and("otherInfo.projects.status").is("Active");

AggregationOperation matchOp = Aggregation.match(criteria);

AggregationOperation groupOp = Aggregation.group(

Fields.from(Fields.field("_id", "$_id")).and(Fields.field("basicInfo","$basicInfo"))).push("$otherInfo.projects").as("projects");

AggregationOperation projectOp = Aggregation.project(

Fields.from(Fields.field("_id","$_id._id"),

Fields.field("basicInfo","$_id.basicInfo"),

Fields.field("otherInfo.projects","$projects")));

AggregationOperation sortOp = Aggregation.sort(Direction.DESC, "otherInfo.projects.verifyDet.isVerified").and(Direction.DESC, "basicInfo.name");

Aggregation agg = Aggregation.newAggregation(unwindOp, matchOp, groupOp, projectOp, sortOp);

AggregationResults results = mongoTemplate.aggregate(agg,

"User", User.class);

return results.getMappedResults();

}

例外：

2017-12-15 19:24:31,852 ERROR GlobalExceptionHandler:75 - Exception Stack Trace :

java.lang.IllegalArgumentException: Invalid reference 'otherInfo.projects.verifyDet.isVerified'!

at org.springframework.data.mongodb.core.aggregation.ExposedFieldsAggregationOperationContext.getReference(ExposedFieldsAggregationOperationContext.java:99)

at org.springframework.data.mongodb.core.aggregation.ExposedFieldsAggregationOperationContext.getReference(ExposedFieldsAggregationOperationContext.java:80)

at org.springframework.data.mongodb.core.aggregation.SortOperation.toDBObject(SortOperation.java:73)

at org.springframework.data.mongodb.core.aggregation.AggregationOperationRenderer.toDBObject(AggregationOperationRenderer.java:56)

at org.springframework.data.mongodb.core.aggregation.Aggregation.toDbObject(Aggregation.java:580)

at org.springframework.data.mongodb.core.aggregation.Aggregation.toString(Aggregation.java:596)

at com.grpbk.gp.repository.impl.UserRepositoryCustomImpl.fetchUsersList(UserRepositoryCustomImpl.java:1128)

at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)

at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)

at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)

at java.lang.reflect.Method.invoke(Method.java:498)

请让我知道我做错了什么 .