第二次作业《软件工程》
1. 设计一个类(不妨叫做A ),实现对一维数组的指定范围内的元素相加运算。
package nsk;import java.util.Scanner;//用于java输入语句的包。public class A {public static void main(String[]args){ int[] arr={-2574,-4010,8243,771,2447,-5197,2556,8044,3314,3617,6065,-2817,3131,6318,2186,-113,629,-2582,-37,-1520,164,2055,-5936,5912,1717,5988,4781,5757,892,-4394,8034,2213,-1080,-2080,5364,106,2657,566,3940,-5116,4583,1806,6555,2621,-7197,528,1626,18,1049,6243,3198,4397,-1325,9087,936,-6291,662,-178,135,-3473,-2385,-165,1713,-7949,-4234,1138,2212,104,6968,-3632,3801,1137,-1296,-1215,4272,6223,-5922,-7723,7044,-2938,-8180,1356,1159,-4022,-3713,1158,-8715,-4081,-2541,-2555,-2284,461,940,6604,-3631,3802,-2037,-4354,-1213,767};int sum=0;Scanner sc = new Scanner(System.in) ;//定义对象,用到Scanner类的nextInt()方法System.out.println("请输入start:");int start=sc.nextInt();System.out.println("请输入end:");int end=sc.nextInt();System.out.println("str为:" +start);System.out.println("end为:" +end);System.out.println("第"+start+"个元素到第"+end+"个元素相加和为");for(int i=start;i<=end;i++)//用for循环语句运算sum+=arr[i]; System.out.println(sum); } }
MyEclipse 6.0运算结果如图:
2. 设计一个类(不妨叫做B ),实现对二维数组的指定范围内的元素相加运算。
package nsk;import java.util.Scanner; public class B {public static void main(String[]args){ int[][]b={ {767,-4619,2209,-7862,-3195,5676,4553,-784,-2010,-3046,1566,-1562,1021,2943,-7241,3847,3222,3001,-1731,-4889,2544,-7893,-1142,7523,7559,867,-4088,2001,-2532,-4488,-8557,5088,-7906,-2104,-1911,-1048,1886,5500,-890,1386,-2080,1431,-1607,5808,-8107,4418,450,1261,-3869,-1184,418,2413,-6418,4607,4059,-444,7821,-2605,-2241,-1390,3047,-1588,8529,1116,4085,4512,4008,4242,6382,-1824,2455,-9217,6014,-2490,-7241,-845,9680,-3756,-5569,3402,4704,-6267,-2393,3191,-965,-5042,-6951,-6184,-8752,525,2144,6195,541,-3336,6904,-3130,-3261,-4770,-34,-1991,292},{7309,2266,2530,481,203,1289,5307,-1328,-4329,5401,6352,2410,-5994,-1825,-8731,-1917,1126,-6189,1290,2701,-1426,-2867,3269,3902,-6483,3591,-313,-53,8749,-742,8649,-276,2687,834,3887,2743,-625,-4357,-5245,-858,-1519,1635,-3765,-318,-4702,-2618,-1070,5750,743,2086,-927,9357,1359,5569,-1483,3141,-685,-1718,-5255,363,2403,1298,861,4910,-5958,6316,-4404,1294,3274,5661,3305,-5349,4768,-7717,3969,742,-1184,-246,3193,5956,-8664,2275,2207,-2697,3871,-5330,-2132,2420,3590,2387,2655,-431,3285,1501,-5325,-2364,1373,-1288,-2344,-3866,1900,}}; int sum=0; Scanner bb = new Scanner(System.in);System.out.println("请输入开始x:");int beginI = bb.nextInt(); System.out.println("请输入结束x:");int overI =bb.nextInt();System.out.println("请输入开始y:");int beginJ = bb.nextInt(); System.out.println("请输入结束y:");int overJ =bb.nextInt();System.out.println("请输入和为:");for(int i=beginI-1;i<=overI-1;i++){for(int j=beginJ-1;j<=overJ-1;j++){sum+=b[i][j];}}System.out.println(b[beginI-1][beginJ-1]+"+...+"+b[overI-1][overJ-1]+"="+sum); }}
3. 设计一个类(不妨叫做C ),实现对三维数组的指定范围内的元素相加运算。
package nsk;import java.util.Scanner; public class C { public static void main(String[]args) { int sum=0; int[][][] cc = new int[][][]{{{767,-4619,2209,-7862,-3195,5676,4553,-784,-2010,-3046,1566,-1562,1021,2943,-7241,3847,3222,3001,-1731,-4889,2544,-7893,-1142,7523,7559,867,-4088,2001,-2532,-4488,-8557,5088,-7906,-2104,-1911,-1048,1886,5500,-890,1386,-2080,1431,-1607,5808,-8107,4418,450,1261,-3869,-1184,418,2413,-6418,4607,4059,-444,7821,-2605,-2241,-1390,3047,-1588,8529,1116,4085,4512,4008,4242,6382,-1824,2455,-9217,6014,-2490,-7241,-845,9680,-3756,-5569,3402,4704,-6267,-2393,3191,-965,-5042,-6951,-6184,-8752,525,2144,6195,541,-3336,6904,-3130,-3261,-4770,-34,-1991,292,},{7309,2266,2530,481,203,1289,5307,-1328,-4329,5401,6352,2410,-5994,-1825,-8731,-1917,1126,-6189,1290,2701,-1426,-2867,3269,3902,-6483,3591,-313,-53,8749,-742,8649,-276,2687,834,3887,2743,-625,-4357,-5245,-858,-1519,1635,-3765,-318,-4702,-2618,-1070,5750,743,2086,-927,9357,1359,5569,-1483,3141,-685,-1718,-5255,363,2403,1298,861,4910,-5958,6316,-4404,1294,3274,5661,3305,-5349,4768,-7717,3969,742,-1184,-246,3193,5956,-8664,2275,2207,-2697,3871,-5330,-2132,2420,3590,2387,2655,-431,3285,1501,-5325,-2364,1373,-1288,-2344,-3866,1900,}}, {{7309,2266,2530,481,203,1289,5307,-1328,-4329,5401,6352,2410,-5994,-1825,-8731,-1917,1126,-6189,1290,2701,-1426,-2867,3269,3902,-6483,3591,-313,-53,8749,-742,8649,-276,2687,834,3887,2743,-625,-4357,-5245,-858,-1519,1635,-3765,-318,-4702,-2618,-1070,5750,743,2086,-927,9357,1359,5569,-1483,3141,-685,-1718,-5255,363,2403,1298,861,4910,-5958,6316,-4404,1294,3274,5661,3305,-5349,4768,-7717,3969,742,-1184,-246,3193,5956,-8664,2275,2207,-2697,3871,-5330,-2132,2420,3590,2387,2655,-431,3285,1501,-5325,-2364,1373,-1288,-2344,-3866,1900,},{1939,-2596,-858,-2040,4980,5915,-744,2107,-2565,-3527,24,2430,1942,1246,-8103,-3588,1762,-1975,-4052,-2843,781,230,3877,-6604,3513,6904,-1993,-516,-4908,2714,1288,-4599,1281,-2047,-2705,-3246,8467,-1460,226,-5227,-6338,-3984,-5094,6312,4502,-2448,-3217,-6147,-752,5938,1933,-4498,6788,-407,-2946,4987,-3366,-7439,-530,1666,-1079,4508,-2868,518,-5588,729,-1388,-7851,-5506,2141,3110,2790,1178,5286,451,-5705,7100,2334,1084,-5854,-4476,1077,-3918,5448,334,-5068,7145,-3070,6044,-7056,6598,-7050,-2211,-221,-2611,-6513,1332,-4269,3093,4146,3059,}},{{7309,2266,2530,481,203,1289,5307,-1328,-4329,5401,6352,2410,-5994,-1825,-8731,-1917,1126,-6189,1290,2701,-1426,-2867,3269,3902,-6483,3591,-313,-53,8749,-742,8649,-276,2687,834,3887,2743,-625,-4357,-5245,-858,-1519,1635,-3765,-318,-4702,-2618,-1070,5750,743,2086,-927,9357,1359,5569,-1483,3141,-685,-1718,-5255,363,2403,1298,861,4910,-5958,6316,-4404,1294,3274,5661,3305,-5349,4768,-7717,3969,742,-1184,-246,3193,5956,-8664,2275,2207,-2697,3871,-5330,-2132,2420,3590,2387,2655,-431,3285,1501,-5325,-2364,1373,-1288,-2344,-3866,1900,},{1939,-2596,-858,-2040,4980,5915,-744,2107,-2565,-3527,24,2430,1942,1246,-8103,-3588,1762,-1975,-4052,-2843,781,230,3877,-6604,3513,6904,-1993,-516,-4908,2714,1288,-4599,1281,-2047,-2705,-3246,8467,-1460,226,-5227,-6338,-3984,-5094,6312,4502,-2448,-3217,-6147,-752,5938,1933,-4498,6788,-407,-2946,4987,-3366,-7439,-530,1666,-1079,4508,-2868,518,-5588,729,-1388,-7851,-5506,2141,3110,2790,1178,5286,451,-5705,7100,2334,1084,-5854,-4476,1077,-3918,5448,334,-5068,7145,-3070,6044,-7056,6598,-7050,-2211,-221,-2611,-6513,1332,-4269,3093,4146,3059,}}};Scanner c = new Scanner(System.in) ;System.out.println("请输入开始X(<=3):");int beginX = c.nextInt() ; System.out.println("请输入结束X(<=3):");int overX =c.nextInt();System.out.println("请输入开始Y(<=2):");int beginY = c.nextInt() ; System.out.println("请输入结束Y(<=2):");int overY =c.nextInt();System.out.println("请输入开始Z(<=100):");int beginZ = c.nextInt() ; System.out.println("请输入结束Z(<=100):");int overZ =c.nextInt();System.out.println("从第"+beginX+"行第"+beginY+"列第"+beginZ+"个到第"+overX+"行第"+overY+"列第"+overZ+"个的和为:");for(int i=beginX-1;i<=overX-1;i++){for(int j=beginY-1;j<=overY-1;j++){for(int k=beginZ-1;k<=overZ-1;k++){sum+=cc[i][j][k]; }}}System.out.println(cc[beginX-1][beginY-1][beginZ-1]+"+...+"+cc[overX-1][overY-1][overZ-1]+"="+sum);}}
小结: 首先看到题目,我难以着手的是如何将excal表格中的数据导入到MyEclipse 6.0中,自己琢磨了一会儿,觉得还是用最实在的方法--一个个手动导入吧。
其次,分析题目:对数组元素相加,这个不难,用for循环语句就可以了,但是如何在“指定范围数据内”相加就比较麻烦了,由同学提示:Scanner类可以实现从键盘读取数据。然后我也参考了其他同学运行好的代码,自己也调试了几遍。通过这次练习,我明白了编写程序就是一个不断发现问题,然后解决问题的过程,一定要多尝试,不怕错误失败,慢慢调试,就一定会有进步的。
转载于:https://www.cnblogs.com/sunshinee/p/4835928.html
第二次作业《软件工程》相关推荐
- 《构建之法》第一次作业 第一篇博客
这个作业属于哪个课程 课程的链接 这个作业要求在哪里 作业要求的链接 我在这个课程的目标是 阅读前人经验教训,寻找自己的目标和未来努力方向 督促自己学习进步,加强独立思考,自我学习能力 增强项目实践能 ...
- 《构建之法》第一次作业——阅读与准备工作
这个作业属于哪个课程 课程链接 这个作业要求在哪里 作业要求 我在这个课程的目标是 学习现代软件工程思想,体验软件开发的过程,以及开发过程中文档的撰写 一.建立博客并介绍自己 我是来自四川攀枝花市的沈 ...
- 《构建之法》第一次作业
这个作业属于哪个课程 这个作业要求在哪里 我在这个课程的目标是 理解软件开发流程,为以后的项目开发做好知识储备 这个作业在哪个具体方面帮助我实现目标 通过大量的阅读和查阅资料对专业有更深的认知,借鉴前 ...
- 构建之法——团队第一次作业
一.团队简介 团队名称:RunningMan 队员 李星晨 201731091410 组长 刘伊凡 201731062603 组员 陈嘉莹 201731104215 组员 唐财伟 2017310624 ...
- 构建之法第二章读后感
本章的实质是在说明,一个合格的软件工程师是怎样的,他应该具备哪些技能. 总结下来,一个合格的工程师在开发时需要同时考虑质量和效率,与之同时需要具备的技能包括:单元测试.效能分析.个人研发流程(PSP) ...
- 《构建之法》 第二次作业
<构建之法> 第二次作业 git地址 github链接 git用户名 namehousiqi 学号后五位 62124 博客地址 个人博客 作业链接 作业 1. 题目简介 阿超家里的孩子上小 ...
- 构建之法——团队第二次作业
团队第二次作业 一.简介 这个作业属于哪个课程 课程地址 这个作业要求在哪里 作业要求 团队名称 RunningMan 这个作业的目标 对我们选择的题目"校园跑腿"进行需求分析,分 ...
- 第二届构建之法论坛预告(草案)
(草案) 时间:2018年7月初 (暂定 7/9 - 7/11) 地点: 北京航空航天大学 活动:为期三天的软件工程教案设计培训和软件专业教育方法的讨论 时间 内容 工具 备注 第一天上午 1. 论坛 ...
- [第二届构建之法论坛] 预培训文档(C++版)
本博客是第二届构建之法论坛暨软件工程培训活动预培训文档中[适用于结对编程部分的C++版本],需要实验者有一部分C++基础. 目录 Part0.背景 Part1.配置环境 Part2.克隆项目 Part ...
- 第一次软工作业(构建之法)
第一次软工作业(构建之法) 关于构建之法的若干个问题 1.第一章32页,原文:"有人认为,"中文编程",是解决程序员编程效率的一个秘密武器,请问它是一个"银弹& ...
最新文章
- 使用CV2和Keras OCR从图像中删除文本
- 用net连某台电脑c盘怎么连_关于电脑的4个冷知识,恐怕90%的人连第一个都不知道!...
- [Android] 按钮单击事件的五种写法
- 项目在eclipse中部署到tomcat时部署到了wtpwebapps文件夹下
- python中表示单一数据的类型被称为_各种Python数据类型的完整列表
- 别在被骗了!!!!!!
- python闭环最短路径_最短路径算法的实现(dijskstra):Python
- ad19做直插封装 ipc_AD19的IPC封装向导使用
- soliworks三维机柜布局(三)绘制电气线路图
- 中兴新支点操作系统_中兴新支点 OS 销量都过两亿套了?赶紧下载安装体验了一把...
- Qt笔记(六十三)之Qt实现窗口以及控件的全屏效果
- u盘插上显示计算机限制,U盘插到电脑上不显示图标的解决方法(以金士顿8GU盘为例)...
- 三进制与八进制相互转换
- 广发样样行这样做可以提额
- 大航海时代2阿兰攻略(SFC日版)(续)
- 本体开发日记07-我与java分词组件的爱恨情仇
- windows如何打开.key keynote文件
- 微计算机应用是核心吗,北大核心哪个杂志好投
- NLP Stemming与Lemmatization的区别
- Android MD5加密法
热门文章
- Mapper系列一:基本使用
- 《考研计算机专业基础综合考试解析配套1000题》错题集20155314刘子健
- VSCode内用markdown写代码时出现很多段落标记的解决方案
- 电脑在关机状态远程也可以控制吗
- 判断是否是直角三角形的算法研究
- 三款学生必备的学习笔记工具,让你暑假变学霸
- MATLAB强化学习工具箱(十二)强化学习智能体创建总览
- modelsim-win64-10.4-se.exe安装
- wap建站程序源码_壹起航:用WAP建站有何利弊
- 【情态动词练习题】mustn‘t 和 don‘t have to