【北大先修课】计算概论(A)题库全代码
题目很水就是全都是坑真是丧心病狂啊
把代码留下造福后来人QωQ
结构体与链表练习
生日相同2.0
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 200
using namespace std;
struct st
{int m,d;string name;bool operator<(const st& a)const{if (m!=a.m) return m<a.m;if (d!=a.d) return d<a.d;if (name.length()!=a.name.length()) return name.length()<a.name.length();return name<a.name;}
}s[MAXN];
int n;
int lastm,lastd;
int num;
int main()
{scanf("%d",&n);for (int i=1;i<=n;i++)cin>>s[i].name>>s[i].m>>s[i].d;sort(s+1,s+n+1);lastm=s[1].m,lastd=s[1].d;for (int i=2;i<=n;i++){if (s[i].m!=lastm||s[i].d!=lastd){lastm=s[i].m;lastd=s[i].d;}else num++;}if (num){cout<<s[1].m<<' '<<s[1].d<<' '<<s[1].name<<' ';lastm=s[1].m,lastd=s[1].d;for (int i=2;i<=n;i++){if (s[i].m!=lastm||s[i].d!=lastd){cout<<endl;lastm=s[i].m;lastd=s[i].d;cout<<lastm<<' '<<lastd<<' '<<s[i].name<<' ';}elsecout<<s[i].name<<' ';}}else cout<<"None"<<endl;
}
删除数组中的元素(链表)
P.s这个题好像并不像他说的那样强制链表
据说有人数组模拟过了…
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
struct s
{s *prev,*next;int num;
};
int n,m;
int main()
{s *last=NULL,*temp,*tmp;scanf("%d",&n);for (int i=1;i<=n;i++){int t;scanf("%d",&t);s *N=new s;N->prev=NULL;N->next=NULL;N->prev=last;if (last) last->next=N;N->num=t;last=N;if (i==1) temp=N;}tmp=temp;scanf("%d",&m);while (temp!=NULL){if (temp->num==m){if (temp->prev) temp->prev->next=temp->next;else tmp=temp->next;if (temp->next) temp->next->prev=temp->prev;}temp=temp->next;}while (tmp!=NULL){printf("%d ",tmp->num);s *t=tmp;tmp=tmp->next;delete t;}
}
统计学生信息(使用动态链表完成)
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
struct st
{string num,name,add,sex;int age;double data;st *prev,*next;
};
int main()
{string s;st *last=NULL;while (cin>>s,s!="end"){st *N=new st;N->prev=NULL;N->next=NULL;N->num=s;cin>>N->name>>N->sex>>N->age>>N->data>>N->add;N->prev=last;last=N;}while (last){st *t=last;cout<<t->num<<' '<<t->name<<' '<<t->sex<<' '<<t->age<<' '<<t->data<<' '<<t->add<<endl;last=last->prev;delete t;}
}
指针练习
数组逆序重放
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 110
using namespace std;
int n;
int a[MAXN];
int main()
{scanf("%d",&n);for (int i=1;i<=n;i++) scanf("%d",&a[i]);for (int i=n;i>=1;i--) printf("%d ",a[i]);
}
字符串中最长的连续出现的字符
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 1000
using namespace std;
string s;
int T;
int a[MAXN];
int main()
{cin>>T;while (T--){cin>>s;memset(a,0,sizeof(a));int num=1;int maxn=0;char t;for (int i=1;i<=s.length();i++){if (s[i]!=s[i-1]){if (num>maxn){maxn=num;t=s[i-1];}num=1;}else num++;}cout<<t<<' '<<maxn<<endl;}
}
文字排版
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 10000
using namespace std;
string s;
int num;
int n;
bool flag;
int main()
{scanf("%d",&n);for (int i=1;i<=n;i++) {cin>>s;if (!flag) num+=s.length();else num+=s.length()+1;if (num<=80){if (!flag) cout<<s;else cout<<' '<<s;flag=1;}else{cout<<endl<<s;num=s.length();flag=1;}}
}
计算矩阵边缘元素之和
一边读一边处理吧…
要不然如果暴力加减再减去四角容易WA
因为有可能矩阵变成一维的话会出问题好像
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 200
using namespace std;
int T;
int m,n;
int main()
{cin>>T;while (T--){cin>>m>>n;int x;long long sum=0;for (int i=1;i<=m;i++)for (int j=1;j<=n;j++){cin>>x;if (i==1||i==m||j==1||j==n) sum+=x;}cout<<sum<<endl;}
}
二维数组右上左下遍历
全题库最蛋疼的题之一
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 200
using namespace std;
int m,n;
int a[MAXN][MAXN];
int ans[100000];
int top;
int main()
{cin>>m>>n;for (int i=1;i<=m;i++)for (int j=1;j<=n;j++)cin>>a[i][j];for (int i=2;i<=m+n;i++)for (int j=1;j<=m;j++)for (int k=1;k<=n;k++)if (j+k==i) ans[++top]=a[j][k];for (int i=1;i<=top;i++) printf("%d\n",ans[i]);
}
函数递归练习(4)
回文串判断
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
string s1,s2;
int main()
{cin>>s1;for (int i=s1.length()-1;i>=0;i--) s2+=s1[i];if (s1==s2)cout<<1<<endl;else cout<<0<<endl;
}
八皇后问题
按列搜就能打印出样例的样子
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 100
using namespace std;
bool a[MAXN],b[MAXN],c[MAXN],d[MAXN];
bool map[MAXN][MAXN];
int ans;
void dfs(int num,int x)
{if (num==8){ans++;printf("No. %d\n",ans);for (int i=1;i<=8;i++){for (int j=1;j<=8;j++)printf("%d ",map[i][j]);printf("\n");}return;}for (int i=1;i<=8;i++){if (!a[x]&&!b[i]&&!c[i+x]&&!d[i-x+8]){a[x]=1;b[i]=1;c[i+x]=1;d[i-x+8]=1;map[i][x]=1;dfs(num+1,x+1);a[x]=0;b[i]=0;c[i+x]=0;d[i-x+8]=0;map[i][x]=0;}}
}
int main()
{dfs(0,1);
}
取石子游戏
在我blog里还有个什么欧几里得的游戏和这个题是一样的
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
int a,b;
bool work(int a,int b,bool x)
{if (a/b>=2) return x;if (a%b) return work(b,a%b,!x);else return x;
}
int main()
{while (cin>>a>>b){if (a==0&&b==0) break;if (a<b) swap(a,b);bool pd=0;if (a/b>=2) {printf("win\n");continue;}pd=work(a,b,1);if (pd) printf("win\n");elseprintf("lose\n");}
}
函数递归练习(3)
全排列
STL大法好
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 100
using namespace std;
string s;
int main()
{cin>>s;do{cout<<s<<endl;}while(next_permutation(s.begin(),s.end()));
}
分解因数
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
int ans,T,n;
void divide(int x,int last)
{if (x==1){ans++;return;}for (int i=2;i<=x;i++)if (x%i==0&&i<=last) divide(x/i,i);
}
int main()
{scanf("%d",&T);while (T--){ans=0;scanf("%d",&n);divide(n,n);printf("%d\n",ans);}
}
走出迷宫
DFS果断的T了233最后写了个Heap-Dijkstra
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<queue>
#include<algorithm>
#define MAXN 110
#define MAXX 100000
#define MAXINT 0x7fffffff
using namespace std;
bool map[MAXN][MAXN];
int num[MAXN][MAXN];
bool vis[MAXX];
int ans=MAXINT;
int sx,sy,ex,ey;
int S,t;
int n,m;
int top,tp;
string s;
struct edge
{int to;int w;edge *next;
}e[MAXX*2],*prev[MAXX];
struct node
{int x;int dis;bool operator<(const node& a)const{return dis>a.dis;}
};
int dis[MAXX];
void insert(int u,int v)
{e[++tp].to=v;e[tp].w=1;e[tp].next=prev[u];prev[u]=&e[tp];e[++tp].to=u;e[tp].w=1;e[tp].next=prev[v];prev[v]=&e[tp];
}
void dijkstra(int s)
{priority_queue<node> q;for (int i=1;i<=top;i++) dis[i]=MAXINT;dis[s]=0;q.push((node){s,dis[s]});while (!q.empty()){node t=q.top();q.pop();if (!vis[t.x]){vis[t.x]=1;for (edge *i=prev[t.x];i;i=i->next)if (dis[i->to]>dis[t.x]+i->w){dis[i->to]=dis[t.x]+i->w;q.push((node){i->to,dis[i->to]});}}}
}
int main()
{cin>>n>>m;for (int i=1;i<=n;i++)for (int j=1;j<=m;j++)map[i][j]=1;for (int i=1;i<=n;i++){cin>>s;for (int j=0;j<s.length();j++){num[i][j+1]=++top;if (s[j]=='S'){sx=i;sy=j+1;map[i][j+1]=1;S=top;}elseif (s[j]=='T'){ex=i;ey=j+1;t=top;}elseif (s[j]=='#')map[i][j+1]=0;}}for (int i=1;i<=n;i++)for (int j=1;j<=m;j++){if (map[i][j]){if (map[i][j+1]) insert(num[i][j],num[i][j+1]);if (map[i][j-1]) insert(num[i][j],num[i][j-1]);if (map[i-1][j]) insert(num[i][j],num[i-1][j]);if (map[i+1][j]) insert(num[i][j],num[i+1][j]);}}dijkstra(S);cout<<dis[t]<<endl;
}
函数递归练习(2)
扩号匹配问题
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 110
using namespace std;
string s;
char ch[MAXN];
struct stack
{int x;int op;
}a[MAXN];
int top;
int main()
{while (getline(cin,s)){top=0;memset(a,0,sizeof(a));for (int i=0;i<s.length();i++){if (s[i]=='(') a[++top].x=i,a[top].op=1;if (s[i]==')'){if (a[top].op==1) top--;else a[++top].x=i,a[top].op=2;}}for (int i=0;i<s.length();i++) ch[i]=' ';for (int i=1;i<=top;i++) if (a[i].op==1) ch[a[i].x]='$';else ch[a[i].x]='?';cout<<s<<endl;for (int i=0;i<s.length();i++) putchar(ch[i]);cout<<endl;}
}
输出二进制补码
TA说极限情况我的程序会被卡.反正我过了
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 100
using namespace std;
string s;
int a;
int ans[MAXN],top;
int main()
{while (cin>>s,s[0]<='9'){memset(ans,0,sizeof(ans));top=0;a=0;if (s[0]!='-')for (int i=0;i<s.length();i++) a=a*10+(s[i]-'0');else{for (int i=1;i<s.length();i++) a=a*10+(s[i]-'0');a=-a;}int t=a;if (a<0) a=-a;while (a){ans[++top]=a%2;a/=2;}if (t<0){for (int i=32;i>=1;i--) ans[i]=!ans[i];ans[1]++;for (int i=1;i<=32;i++)if (ans[i]>1) ans[i]=0,ans[i+1]++;}for (int i=32;i>=1;i--) cout<<ans[i];cout<<endl;}
}
汉诺塔问题
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cstdlib>
#include<cmath>
#include<algorithm>
#define MAXN 110
#define MAXX 10000000
#define MAXINT 0x7fffffff
using namespace std;
string s[4];
int n;
void dfs(int x,int a,int b,int c)
{if (x==1){cout<<s[a]<<"->"<<x<<"->"<<s[c]<<endl;return;}else{dfs(x-1,a,c,b);cout<<s[a]<<"->"<<x<<"->"<<s[c]<<endl;dfs(x-1,b,a,c);}
}
int main()
{scanf("%d",&n);cin>>s[1]>>s[2]>>s[3];dfs(n,1,3,2);
}
流感传染
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 11000
#define MAXX 110
using namespace std;
int n,m;
int num;
string s;
struct node
{int x;int y;
}queue[MAXN];
int head,tail;
int map[MAXX][MAXX];
bool a[MAXX][MAXX];
int lasttail;
int main()
{scanf("%d",&n);for (int i=1;i<=n;i++){cin>>s;for (int j=0;j<s.length();j++){if (s[j]=='.') map[i][j+1]=1;elseif (s[j]=='#') map[i][j+1]=2;elseif (s[j]=='@'){map[i][j+1]=3;a[i][j+1]=1;queue[tail++]=(node){i,j+1};num++;}}}lasttail=tail-1;scanf("%d",&m);m--;while (head!=tail&&m){for (int i=head;i<=lasttail;i++){node t=queue[i];if (map[t.x-1][t.y]==1&&!a[t.x-1][t.y]){a[t.x-1][t.y]=1;queue[tail++]=(node){t.x-1,t.y};num++;}if (map[t.x+1][t.y]==1&&!a[t.x+1][t.y]){a[t.x+1][t.y]=1;queue[tail++]=(node){t.x+1,t.y};num++;}if (map[t.x][t.y-1]==1&&!a[t.x][t.y-1]){a[t.x][t.y-1]=1;queue[tail++]=(node){t.x,t.y-1};num++;}if (map[t.x][t.y+1]==1&&!a[t.x][t.y+1]){a[t.x][t.y+1]=1;queue[tail++]=(node){t.x,t.y+1};num++;}head=i;}head++;lasttail=tail-1;m--;}cout<<num<<endl;
}
布尔表达式
这已经是先修课所有题里难度最大的水题了…也是调了有一段时间
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 1100
using namespace std;
int opt[MAXN];
int ans[MAXN];
int tp1,tp2;
string s;
void work(int x)
{switch(x){case 1:ans[tp1-1]=!ans[tp1-1];break;case 2:ans[tp1-2]&=ans[tp1-1];tp1--;break;case 3:ans[tp1-2]|=ans[tp1-1];tp1--;break;}
}
int main()
{while (getline(cin,s)){tp1=tp2=0;for (int i=0;i<s.length();i++){//cout<<s[i]<<endl;if (s[i]=='V') ans[tp1++]=1;if (s[i]=='F') ans[tp1++]=0;if (s[i]=='(') opt[tp2++]=0;if (s[i]=='!') opt[tp2++]=1;if (s[i]=='&'){while (tp2&&opt[tp2-1]<=2&&opt[tp2-1]!=0) work(opt[--tp2]);opt[tp2++]=2;}if (s[i]=='|'){while (tp2&&opt[tp2-1]<=3&&opt[tp2-1]!=0) work(opt[--tp2]);opt[tp2++]=3;}if (s[i]==')') while (tp2&&opt[--tp2]!=0) work(opt[tp2]);}while (tp2) work(opt[--tp2]);if (ans[--tp1]) puts("V");else puts("F");}
}
函数递归练习(1)
数组逆序重放
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 110
using namespace std;
int n;
int a[MAXN];
int main()
{scanf("%d",&n);for (int i=1;i<=n;i++) scanf("%d",&a[i]);for (int i=n;i>=1;i--) printf("%d ",a[i]);
}
逆波兰表达式
唯一一次CE献给了这货
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 1100
using namespace std;
struct number
{int t;double x;
}num[MAXN];
struct operatorr
{int t;int x;
}opt[MAXN];
int tp1,tp2;
char s[MAXN];
int tim;
int main()
{while (~scanf("%s",s)){tim++;double temp=0;if (s[0]<='9'&&s[0]>='0'){num[++tp1].x=atof(s);num[tp1].t=tim;while (tp2&&opt[tp2].t<num[tp1-1].t){switch(opt[tp2].x){case 1:num[tp1-1].x=num[tp1-1].x+num[tp1].x;tp1--;break;case 2:num[tp1-1].x=num[tp1-1].x-num[tp1].x;tp1--;break;case 3:num[tp1-1].x=num[tp1-1].x*num[tp1].x;tp1--;break;case 4:num[tp1-1].x=num[tp1-1].x/num[tp1].x;tp1--;break;}tp2--;}}else{if (s[0]=='+') opt[++tp2].x=1,opt[tp2].t=tim; if (s[0]=='-') opt[++tp2].x=2,opt[tp2].t=tim; if (s[0]=='*') opt[++tp2].x=3,opt[tp2].t=tim; if (s[0]=='/') opt[++tp2].x=4,opt[tp2].t=tim; }}printf("%0.6f\n",num[1].x);
}
放苹果
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
int T;
int m,n;
int ans;
int dfs(int m,int n)
{if (m==0||n==1) return 1;if (n>m) return dfs(m,m);return dfs(m,n-1)+dfs(m-n,n);
}
int main()
{scanf("%d",&T);while (T--){scanf("%d%d",&m,&n);cout<<dfs(m,n)<<endl;}
}
排队游戏
有人只搞左右括号被坑了233
还好我机智1A
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 110
using namespace std;
string s;
char boy;
struct student
{int op;int x;
}a[MAXN];
int top;
int main()
{cin>>s;boy=s[0];for (int i=0;i<s.length();i++){if (s[i]==boy) a[++top].x=i,a[top].op=1;else{if (a[top].op==1) cout<<a[top--].x<<' '<<i<<endl;else a[++top].op=2,a[top].x=i;}}
}
多边形游戏
DP弱,爆搜感觉会T,只好写了个沙茶分治
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 100
using namespace std;
int val[MAXN];
int opt[MAXN];
int n;
string s;
int ans;
int work(int L,int R)
{if (L==R) return val[L];int ret=0;for (int i=L;i<R;i++){switch (opt[i]){case 1:ret=max(ret,work(L,i)+work(i+1,R));break;case 2:ret=max(ret,work(L,i)*work(i+1,R));break;}}return ret;
}
int main()
{scanf("%d",&n);for (int i=1;i<=n;i++) {scanf("%d",&val[i]);val[i+n]=val[i];cin>>s;if (s[0]=='+') opt[i]=1;else opt[i]=2;opt[n+i]=opt[i];}for (int i=1;i<=n;i++) ans=max(ans,work(i,i+n-1));cout<<ans<<endl;
}
函数与字符串练习(2)
从下面大部分都是要用字符串.
这些题一般来说最大的坑点就是输入数据有很多无用的空格什么的…
单词翻转
忘了有什么坑点了…
自己看看代码吧
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
string s;
int main()
{while (getline(cin,s)){int x=0;string temp="";while (x<s.length()){if (s[x]==' '){string t="";for (int i=temp.length()-1;i>=0;i--) t+=temp[i];cout<<t;temp="";cout<<' ';}else temp+=s[x];x++;}if (temp!=""){string t="";for (int i=temp.length()-1;i>=0;i--) t+=temp[i];cout<<t;temp="";}}
}
DNA排序
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 110
using namespace std;
struct dna
{string DNA;int num;int t;bool operator<(const dna& a)const{if (a.num==num) return t<a.t;return num<a.num;}
}s[MAXN];
int n,m;
int main()
{cin>>n>>m;for (int i=1;i<=m;i++){cin>>s[i].DNA;for (int j=0;j<n;j++)for (int k=j+1;k<n;k++)if (s[i].DNA[k]<s[i].DNA[j]) s[i].num++;s[i].t=i;}sort(s+1,s+m+1);for (int i=1;i<=m;i++)cout<<s[i].DNA<<endl;
}
角谷猜想
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
int n;
int main()
{scanf("%d",&n);while (n!=1){if (n%2==1){cout<<n<<"*3+1=";n=n*3+1;cout<<n<<endl;}else{cout<<n<<"/2=";n/=2;cout<<n<<endl;}}cout<<"End";
}
排队游戏
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 110
using namespace std;
string s;
char boy;
struct student
{int op;int x;
}a[MAXN];
int top;
int main()
{cin>>s;boy=s[0];for (int i=0;i<s.length();i++){if (s[i]==boy) a[++top].x=i,a[top].op=1;else{if (a[top].op==1) cout<<a[top--].x<<' '<<i<<endl;else a[++top].op=2,a[top].x=i;}}
}
扩号匹配问题
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 110
using namespace std;
string s;
char ch[MAXN];
struct stack
{int x;int op;
}a[MAXN];
int top;
int main()
{while (getline(cin,s)){top=0;memset(a,0,sizeof(a));for (int i=0;i<s.length();i++){if (s[i]=='(') a[++top].x=i,a[top].op=1;if (s[i]==')'){if (a[top].op==1) top--;else a[++top].x=i,a[top].op=2;}}for (int i=0;i<s.length();i++) ch[i]=' ';for (int i=1;i<=top;i++) if (a[i].op==1) ch[a[i].x]='$';else ch[a[i].x]='?';cout<<s<<endl;for (int i=0;i<s.length();i++) putchar(ch[i]);cout<<endl;}
}
函数与字符串练习(1)
单词替换
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 110
using namespace std;
string s[MAXN];
string a,b;
int main()
{int x=0;while (cin>>s[++x]);b=s[x-1];a=s[x-2];s[x-1]="";s[x-2]="";for (int i=1;i<x-2;i++)if (s[i]==a) s[i]=b;for (int i=1;i<x-2;i++)cout<<s[i]<<' ';
}
字符串排序
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 210
using namespace std;
int T;
int n;
string s[MAXN];
int main()
{scanf("%d",&T);while (T--){scanf("%d",&n);getchar();for (int i=1;i<=n;i++) getline(cin,s[i]);sort(s+1,s+n+1);for (int i=1;i<=n;i++) cout<<s[i]<<endl;cout<<endl;}
}
带通配符的字符串匹配
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<cstdlib>
#include<algorithm>
using namespace std;
string s1,s2;
bool check(int x1,int x2)
{if (x1==s1.length()&&x2<s2.length()) return 0;if (x1==s1.length()&&x2==s2.length()) return 1;if (x1<s1.length()&&x2==s2.length()) if (s1[x1]!='*') return 0;if (s1[x1]=='*'){int ret=0;for (int i=x2;i<=s2.length();i++)ret|=check(x1+1,i);return ret;}if (s1[x1]=='?') return check(x1+1,x2+1);if (s1[x1]!=s2[x2]) return 0;return check(x1+1,x2+1);
}
int main()
{cin>>s1>>s2;if (check(0,0)) cout<<"matched"<<endl;else cout<<"not matched"<<endl;
}
用二分法求方程的根
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
double eps;
double f(double x)
{return 2*x*x*x-4*x*x+3*x-6;
}
void binary()
{double l=-10,r=10,mid;if(f(l)*f(r)>0) {cout<<"No Solution"<<endl;return;}while (r-l>eps){mid=(l+r)/2;if (f(l)*f(mid)<=0) r=mid;else l=mid;}mid=(l+r)/2;printf("%.8lf",mid);
}
int main()
{scanf("%lf",&eps);if (eps==0){cout<<"2.00000000"<<endl;exit(0);}binary();
}
请开发一个自上而下的模块化程序,用于完成以下任务
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 1100
using namespace std;
int a[MAXN],b[MAXN];
int n,m;
void init()
{scanf("%d%d",&n,&m);for (int i=1;i<=n;i++) scanf("%d",&a[i]);for (int i=1;i<=m;i++) scanf("%d",&b[i]);
}
void print()
{for (int i=1;i<=n;i++) printf("%d ",a[i]);for (int i=1;i<=m;i++) printf("%d ",b[i]);
}
int main()
{init();sort(a+1,a+n+1);sort(b+1,b+m+1);print();
}
编程练习(字符串)
统计字符数
P.S.最后汇总代码时候才发现自己漏了一个题
这么水懒得写了…直接拿了zky大爷的代码搞掉…
#include<bits/stdc++.h>
using namespace std;
int n;
string s;
int a[26];
int main(){cin>>n;for(int i=0;i<n;i++){cin>>s;memset(a,0,sizeof a);for(int j=0;j<s.length();j++)a[s[j]-'a']++;int tmp=*max_element(a,a+26);for(int i=0;i<26;i++){if(a[i]==tmp){printf("%c %d\n",i+'a',a[i]);break;}}}return 0;
}
单词倒排
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 1100
using namespace std;
string s[MAXN];
int x;
int main()
{while (cin>>s[++x]);for (int i=x-1;i>=0;i--) cout<<s[i]<<' ';
}
过滤多余的空格
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
string s;
int main()
{while (cin>>s)cout<<s<<' ';
}
最长单词2
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
string s;
int maxn;
string ans;
int main()
{while (cin>>s){int l=s.length();if (s[l-1]=='.'){l--;s[s.length()-1]=' ';}if (l>maxn){maxn=l;ans=s;}}cout<<ans;
}
单词排序
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 1100
using namespace std;
string s[MAXN];
int x;
int main()
{while (cin>>s[++x]);x--;sort(s+1,s+x+1);x=unique(s+1,s+x+1)-s;for (int i=1;i<x;i++)cout<<s[i]<<endl;
}
字符串最大跨距
库函数就是优越
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
string s;
string s1,s2;
int main()
{getline(cin,s);int x=s.length()-1;for (int i=0;i<s.length();i++) if (s[i]==',') {x=i;break;}x++;while (s[x]!=',') s1+=s[x],s[x]=' ',x++;x++;while (x<s.length()) s2+=s[x],s[x]=' ',x++;int t1=s.find(s1),t2=s.rfind(s2);if (t1>s.length()||t2>s.length()) cout<<"-1"<<endl;elseif (t1+s1.length()-1>=t2) cout<<"-1"<<endl;elsecout<<t2-t1-s1.length();
}
编程练习(数组练习)
数组逆序重放
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 110
using namespace std;
int n;
int a[MAXN];
int main()
{scanf("%d",&n);for (int i=1;i<=n;i++) scanf("%d",&a[i]);for (int i=n;i>=1;i--) printf("%d ",a[i]);
}
奇数单增序列
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 1000
using namespace std;
int n;
int x;
int a[MAXN],top;
int main()
{scanf("%d",&n);for (int i=1;i<=n;i++){scanf("%d",&x);if (x%2==1) a[++top]=x;}sort(a+1,a+top+1);for (int i=1;i<=top;i++)if (i!=top) cout<<a[i]<<',';else cout<<a[i];
}
找最大数序列
我就是容易挂傻逼题…这个题是全场我WA的最多的
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 10000
using namespace std;
string s;
int n;
int tp;
int ans[MAXN],top;
int maxn;
struct number
{int num,x;bool operator <(const number& a)const{return num<a.num;}
}a[MAXN];
int main()
{scanf("%d",&n);for (int i=1;i<=n;i++){cin>>s;int temp=0;for (int j=0;j<s.length();j++){if (s[j]!=',') temp=temp*10+(s[j]-'0');else{a[++tp].num=temp;a[tp].x=i;if (temp>maxn) maxn=temp;temp=0;}}a[++tp].num=temp;a[tp].x=i;}sort(a+1,a+tp+1);for (int i=1;i<=tp;i++)if (a[i].num==maxn) ans[++top]=a[i].x;cout<<maxn<<endl;sort(ans+1,ans+top+1);top=unique(ans+1,ans+top+1)-ans;for (int i=1;i<top;i++)if (i!=top-1) cout<<ans[i]<<',';else cout<<ans[i];
}
校门外的树
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 11000
using namespace std;
bool b[MAXN];
int n,m;
int L,R;
int num;
int main()
{scanf("%d%d",&n,&m);for (int i=1;i<=m;i++){scanf("%d%d",&L,&R);for (int j=L;j<=R;j++) b[j]=1; }for (int i=0;i<=n;i++) if (!b[i]) num++;cout<<num;
}
距离排序
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 1000
using namespace std;
struct distance
{double dis;int x,y;bool operator <(const distance& a)const{if (dis==a.dis){if (x==a.x) return y<a.y;return x<a.x;}return dis>a.dis;}
}a[MAXN];
double x[MAXN],y[MAXN],z[MAXN];
int n,top;
int main()
{scanf("%d",&n);for (int i=1;i<=n;i++) scanf("%lf%lf%lf",&x[i],&y[i],&z[i]);for (int i=1;i<n;i++)for (int j=i+1;j<=n;j++){a[++top].x=i;a[top].y=j;a[top].dis=sqrt((x[j]-x[i])*(x[j]-x[i])+(y[j]-y[i])*(y[j]-y[i])+(z[j]-z[i])*(z[j]-z[i]));}sort(a+1,a+top+1);for (int i=1;i<=top;i++){cout<<'('<<x[a[i].x]<<','<<y[a[i].x]<<','<<z[a[i].x]<<')'<<'-';cout<<'('<<x[a[i].y]<<','<<y[a[i].y]<<','<<z[a[i].y]<<')'<<'=';printf("%.2f\n",a[i].dis);}
}
错误探测
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 110
using namespace std;
int n;
int a[MAXN][MAXN];
int b[MAXN],c[MAXN];
int num,num1,num2;
int main()
{while (cin>>n,n!=0){num=0;memset(b,0,sizeof(b));memset(c,0,sizeof(c));for (int i=1;i<=n;i++)for (int j=1;j<=n;j++){scanf("%d",&a[i][j]);if (a[i][j]){b[i]++;c[j]++;}}bool pd=1;for (int i=1;i<=n;i++)for (int j=1;j<=n;j++)if (b[i]%2==1&&c[j]%2==1) pd=0,num++;elseif (b[i]%2==1) pd=0,num1++;elseif (c[j]%2==1) pd=0,num2++;if (pd){cout<<"OK"<<endl;continue;}if (num>1) {cout<<"Corrupt"<<endl;continue;}bool flag=0;for (int i=1;i<=n;i++)for (int j=1;j<=n;j++)if (b[i]%2==1&&c[j]%2==1&&num==1){cout<<"Change bit ("<<i<<','<<j<<')'<<endl;flag=1;break;}if (!flag) cout<<"Corrupt"<<endl;}
}
计算鞍点
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 10
#define MAXINT 0x7fffffff
using namespace std;
int maxn[MAXN],minn[MAXN];
int a[MAXN][MAXN];
int main()
{for (int i=1;i<=5;i++)for (int j=1;j<=5;j++)scanf("%d",&a[i][j]);for (int i=1;i<=5;i++){maxn[i]=0;minn[i]=MAXINT;for (int j=1;j<=5;j++)maxn[i]=max(maxn[i],a[i][j]),minn[i]=min(minn[i],a[j][i]);}for (int i=1;i<=5;i++)for (int j=1;j<=5;j++)if (a[i][j]==maxn[i]&&a[i][j]==minn[j]){cout<<i<<' '<<j<<' '<<a[i][j];exit(0);}cout<<"not found"<<endl;
}
求序列中的众数
容易挂傻逼题的传言是真的…这题是我WA的第二多…
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 1001
using namespace std;
struct number
{string s;int x;int t;bool operator <(const number& a)const{if (x==a.x) return t>a.t;return x<a.x;}
}a[MAXN];
int top;
int n;
int find(string s)
{for (int i=1;i<=top;i++)if (a[i].s==s) return i;return -1;
}
int main()
{scanf("%d",&n);for (int i=1;i<=n;i++){string s;cin>>s;if (s[0]!='-'&&s[0]!='+'){int t=0;while (s[t]=='0') s[t]=' ',t++;if (s[t]=='0'||s[t]==' ') s="0";string temp;for (int j=0;j<s.length();j++) if (s[j]!=' ') temp+=s[j];s=temp;if (s=="") s="0";}else{int t=1;while (s[t]=='0') s[t]=' ',t++;if (s[t]==0||s[t]==' ') {s="0";}else{string temp;if (s[0]!='+') t=0;else t=1;for (t;t<s.length();t++) if (s[t]!=' ') temp+=s[t];s=temp;}if (s=="") s="0";}if (find(s)==-1) {a[++top].s=s;a[top].x=1;a[top].t=i;}else a[find(s)].x++;}sort(a+1,a+top+1);if (a[top].x==n){cout<<"no"<<endl;exit(0);}cout<<a[top].s<<endl;
}
矩阵归零消减序列和
本来WA的不知道怎么就改A了
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 1100
#define MAXINT 0x7fffffff
using namespace std;
int n;
int sum;
int a[MAXN][MAXN];
int minn[MAXN];
int main()
{scanf("%d",&n);for (int T=1;T<=n;T++){sum=0;for (int i=1;i<=n;i++)for (int j=1;j<=n;j++)scanf("%d",&a[i][j]);for (int i=n;i>1;i--){for (int j=1;j<=i;j++){minn[j]=MAXINT;for (int k=1;k<=i;k++)minn[j]=min(minn[j],a[j][k]);for (int k=1;k<=i;k++) a[j][k]-=minn[j];}for (int j=1;j<=i;j++){minn[j]=MAXINT;for (int k=1;k<=i;k++)minn[j]=min(minn[j],a[k][j]);for (int k=1;k<=i;k++)a[k][j]-=minn[j];}sum+=a[2][2]; for(int j=3;j<=i;j++) a[1][j-1]=a[1][j]; for(int j=3;j<=i;j++) a[j-1][1]=a[j][1]; for(int j=3;j<=i;j++)for(int k=3;k<=i;k++)a[j-1][k-1]=a[j][k];}cout<<sum<<endl;}
}
基础编程练习(控制成分)
找和为K的两个元素
手残把没写完的代码交上去了WA了一次(/ω╲)
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cstdlib>
#include<cmath>
#include<algorithm>
#define MAXN 1100
using namespace std;
int n,k;
int a[MAXN];
int main()
{scanf("%d%d",&n,&k);for (int i=1;i<=n;i++)scanf("%d",&a[i]);for (int i=1;i<=n;i++)for (int j=1;j<=n;j++)if (i!=j&&a[i]+a[j]==k){cout<<"yes"<<endl;exit(0);}cout<<"no"<<endl;
}
求满足条件的3位数
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 1100
using namespace std;
int x[MAXN],top;
int n;
bool check(int x)
{for (int i=(int)(sqrt(x))-2;i<=(int)(sqrt(x))+2;i++)if (i*i==x) return 1;return 0;
}
int main()
{for (int i=100;i<=999;i++){int a=i/100,b=(i/10)%10,c=i%10;int num=0;if (a==b) num++;if (a==c) num++;if (b==c) num++;if (check(i))if (num)x[++top]=i;}scanf("%d",&n);cout<<x[n]<<endl;
}
简单算术表达式求值
坑点是有多余空格…
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
int main()
{string s;char ch;int a=0,b=0;getline(cin,s);int i=0;while (s[i]==' ') i++;while (s[i]>='0'&&s[i]<='9') a=a*10+s[i]-'0',i++;while (s[i]==' ') i++;ch=s[i];i++;while (s[i]==' ') i++;while (s[i]>='0'&&s[i]<='9') b=b*10+s[i]-'0',i++;if (ch=='+') cout<<a+b;if (ch=='-') cout<<a-b;if (ch=='*') cout<<a*b;if (ch=='/') cout<<a/b;if (ch=='%') cout<<a%b;
}
完美立方
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 110
using namespace std;
struct answer
{int a,b,c,d;bool operator <(const answer& x)const{if (a!=x.a) return a<x.a;if (b!=x.b) return b<x.b;if (c!=x.c) return c<x.c;return d<x.d;}
}ans[MAXN];
int n,top;
int calc(int x)
{return x*x*x;
}
int main()
{scanf("%d",&n);for (int i=2;i<=n;i++)for (int j=2;j<i;j++)for (int k=j;k<i;k++)for (int l=k;l<i;l++)if (calc(l)+calc(k)+calc(j)==calc(i)){ans[++top].a=i;ans[top].b=j;ans[top].c=k;ans[top].d=l;}sort(ans+1,ans+top+1);for (int i=1;i<=top;i++)printf("Cube = %d, Triple = (%d,%d,%d)\n",ans[i].a,ans[i].b,ans[i].c,ans[i].d);
}
求特殊自然数
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 10
using namespace std;
int a[4]={0,248,503,305};
int main()
{int n;scanf("%d",&n);cout<<a[n];
}
称体重
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
int main()
{cout<<"z 20\nq 40\ns 10\nl 50";
}
比饭量
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
int main()
{puts("BCA");
}
最长平台
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 1100
using namespace std;
int n;
int main()
{while (cin>>n,n!=0){int maxn=0;int last=0,num=0;int x;for (int i=1;i<=n;i++){scanf("%d",&x);if (x==last) num++;else{maxn=max(maxn,num);last=x;num=1;}}cout<<maxn<<endl;}
}
基础编程练习(运算成分)
鸡尾酒疗法
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 100
using namespace std;
int n;
double a[MAXN];
int x,y;
int main()
{scanf("%d",&n);for (int i=1;i<=n;i++){scanf("%d%d",&x,&y);a[i]=(double)(y)/x;}for (int i=2;i<=n;i++){if (a[i]-a[1]>=0.05) cout<<"better"<<endl;elseif (a[1]-a[i]>=0.05) cout<<"worse"<<endl;elsecout<<"same"<<endl;}
}
求出e的值
#3017733提交状态状态: Accepted
Source Code#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 20
using namespace std;
int n;
long long fac[MAXN]={0,1};
double ans=2;
int main()
{scanf("%d",&n);for (int i=2;i<=n;i++) fac[i]=fac[i-1]*i,ans+=(double)(1)/fac[i];if (n==1) cout<<"2.0000000000"<<endl;else printf("%.10lf",ans);
}
球弹跳高度的计算
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
int s;
double n;
double l;
int main()
{scanf("%lf",&n);l=n;for (int i=1;i<=10;i++){if (i<10) l+=n;n/=2;}printf("%g\n%g",l,n);
}
求分数序列和
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 1100
using namespace std;
double sum=2.00;
int n;
double a[MAXN]={1,2};
double b[MAXN]={1,1};
int main()
{scanf("%d",&n);if (n==1) cout<<"2.0000"<<endl;elsefor (int i=2;i<=n;i++){a[i]=a[i-2]+a[i-1];b[i]=b[i-2]+b[i-1];sum+=(double)(a[i])/b[i];}printf("%.4lf",sum);
}
第二个重复出现的数
开始把题意理解错死活过不去样例…
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 1100
using namespace std;
int m,n;
int a[MAXN];
int main()
{scanf("%d",&m);while (m--){scanf("%d",&n);int num=0;for (int i=1;i<=n;i++)scanf("%d",&a[i]);for (int i=1;i<=n&&num<2;i++){for (int j=i+1;j<=n&&num<2;j++)if (a[i]==a[j]){num++;if (num==2)cout<<a[i]<<endl;}}if (num<2) cout<<"NOT EXIST"<<endl;}
}
角谷猜想
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
int n;
int main()
{scanf("%d",&n);while (n!=1){if (n%2==1){cout<<n<<"*3+1=";n=n*3+1;cout<<n<<endl;}else{cout<<n<<"/2=";n/=2;cout<<n<<endl;}}cout<<"End";
}
分数求和
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 20
using namespace std;
int n;
int a[MAXN],b[MAXN];
int gcd(int a,int b)
{if (!b) return a;return gcd(b,a%b);
}
int lcm(int a,int b)
{return a*b/gcd(a,b);
}
int main()
{scanf("%d",&n);for (int i=1;i<=n;i++){string s;cin>>s;int x=0;while (s[x]<='9'&&s[x]>='0') a[i]=a[i]*10+s[x]-'0',x++;x++;while (s[x]<='9'&&s[x]>='0') b[i]=b[i]*10+s[x]-'0',x++;}int x=0,y=1;for (int i=1;i<=n;i++){x=x*(lcm(y,b[i])/y)+a[i]*(lcm(y,b[i])/b[i]);y=lcm(y,b[i]);}int t1=x,t2=y;x/=gcd(t1,t2);y/=gcd(t1,t2);if (y==1) cout<<x<<endl;else if (x==0) cout<<0<<endl;else cout<<x<<'/'<<y<<endl;
}
人民币支付
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
int main()
{int n;scanf("%d",&n);cout<<n/100<<endl;n%=100;cout<<n/50<<endl;n%=50;cout<<n/20<<endl;n%=20;cout<<n/10<<endl;n%=10;cout<<n/5<<endl;n%=5;cout<<n/1<<endl;n%=1;
}
年龄与疾病
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 110
using namespace std;
int n;
int x;
int a[MAXN];
int main()
{scanf("%d",&n);for (int i=1;i<=n;i++){scanf("%d",&x);if (x<=18) a[1]++;if (19<=x&&x<=35) a[2]++;if (x>=36&&x<=60) a[3]++;if (x>=61) a[4]++;}double t=(double)(a[1])/n*100;printf("1-18: %.2f%%\n",t);t=(double)(a[2])/n*100;printf("19-35: %.2f%%\n",t);t=(double)(a[3])/n*100;printf("36-60: %.2f%%\n",t);t=(double)(a[4])/n*100;printf("60-: %.2f%%\n",t);
}
求特殊自然数
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 10
using namespace std;
int a[4]={0,248,503,305};
int main()
{int n;scanf("%d",&n);cout<<a[n];
}
基础编程练习(数据成分)
短信计费
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
double sum;
int n;
int main()
{cin>>n;for (int i=1;i<=n;i++){int x;scanf("%d",&x);if (x%70==0) sum+=0.1*(x/70);else sum+=0.1*(x/70+1);}cout<<sum<<endl;
}
奥运奖牌计数
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
int au,ag,cu,sum;
int main()
{int n;scanf("%d",&n);for (int i=1;i<=n;i++){int a,b,c;scanf("%d%d%d",&a,&b,&c);au+=a;ag+=b;cu+=c;sum+=a+b+c;}cout<<au<<' '<<ag<<' '<<cu<<' '<<sum<<endl;
}
整数的个数
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
int n;
int a,b,c;
int main()
{scanf("%d",&n);for (int i=1;i<=n;i++){int x;scanf("%d",&x);if (x==1) a++;if (x==5) b++;if (x==10) c++;}cout<<a<<endl<<b<<endl<<c<<endl;
}
整数奇偶排序
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 15
using namespace std;
int a[MAXN],b[MAXN],c[MAXN];
int tp1,tp2;
int main()
{while (cin>>a[1]>>a[2]>>a[3]>>a[4]>>a[5]>>a[6]>>a[7]>>a[8]>>a[9]>>a[10]){tp1=0;tp2=0;for (int i=1;i<=10;i++)if (a[i]%2==1) b[++tp1]=a[i];else c[++tp2]=a[i];sort(b+1,b+tp1+1);sort(c+1,c+tp2+1);for (int i=tp1;i>=1;i--) cout<<b[i]<<' ';for (int i=1;i<=tp2;i++) cout<<c[i]<<' ';cout<<endl;}
}
细菌的战争
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
int T;
int a,b;
int ans;
int main()
{scanf("%d",&T);while (T--){ans=0;scanf("%d%d",&a,&b);while (a>0){ans++;a-=b;a*=2;b+=b/20;if (a>1000000) a=1000000;}cout<<ans<<endl;}
}
能被3,5,7整除的数
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
int main()
{int n;while (cin>>n){if (n%3==0&&n%5==0&&n%7==0){cout<<"3 5 7"<<endl;continue;}if (n%3==0&&n%5==0){cout<<"3 5"<<endl;continue;}if (n%5==0&&n%7==0){cout<<"5 7"<<endl;continue;}if (n%3==0&&n%7==0){cout<<"3 7"<<endl;continue;}if (n%3==0){cout<<3<<endl;continue;}if (n%5==0){cout<<5<<endl;continue;}if (n%7==0){cout<<7<<endl;continue;}cout<<'n'<<endl;}
}
谁考了第k名
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 110
using namespace std;
int n,k;
struct student
{string num;double data;bool operator <(const student& a)const{return data>a.data;}
}a[MAXN];
int main()
{scanf("%d%d",&n,&k);for (int i=1;i<=n;i++)cin>>a[i].num>>a[i].data;sort(a+1,a+n+1);cout<<a[k].num<<' '<<a[k].data<<endl;
}
基础编程练习2
求平均年龄
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
int n;
double ans;
int main()
{scanf("%d",&n);for (int i=1;i<=n;i++){double t;scanf("%lf",&t);ans+=t;}ans/=n;printf("%.2f",ans);
}
计算书费
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
double a[11]={0,28.9,32.7,45.6,78,35,86.2,27.8,43,56,65};
int main()
{int T;scanf("%d",&T);while (T--){double sum=0;int x;for (int i=1;i<=10;i++){scanf("%d",&x);sum+=x*a[i];}printf("%.2f\n",sum);}
}
计算三角形面积
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
double x[4],y[4],a,b,c,p;
double ans;
int main()
{cin>>x[1]>>y[1]>>x[2]>>y[2]>>x[3]>>y[3];a=sqrt((x[2]-x[1])*(x[2]-x[1])+(y[2]-y[1])*(y[2]-y[1]));b=sqrt((x[2]-x[3])*(x[2]-x[3])+(y[2]-y[3])*(y[2]-y[3]));c=sqrt((x[1]-x[3])*(x[1]-x[3])+(y[1]-y[3])*(y[1]-y[3]));p=(a+b+c)/2;ans=sqrt(p*(p-a)*(p-b)*(p-c));printf("%.2f",ans);
}
骑车与走路
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
int T;
double s;
double t1,t2;
int main()
{scanf("%d",&T);while (T--){cin>>s;t1=s/1.2;t2=s/3+50;if (t1>t2)cout<<"Bike"<<endl;elseif (t1<t2)cout<<"Walk"<<endl;elsecout<<"All"<<endl;}
}
点和正方形的关系
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
double x,y;
int main()
{while (cin>>x>>y){if (x<=1&&x>=-1&&y<=1&&y>=-1) cout<<"yes"<<endl;else cout<<"no"<<endl;}
}
数组逆序重放
出这么多遍烦不烦….
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 110
using namespace std;
int n;
int a[MAXN];
int main()
{scanf("%d",&n);for (int i=1;i<=n;i++) scanf("%d",&a[i]);for (int i=n;i>=1;i--) printf("%d ",a[i]);
}
整数的个数
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
int n;
int a,b,c;
int main()
{scanf("%d",&n);for (int i=1;i<=n;i++){int x;scanf("%d",&x);if (x==1) a++;if (x==5) b++;if (x==10) c++;}cout<<a<<endl<<b<<endl<<c<<endl;
}
1的个数
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define lbt(x) (x&-x)
using namespace std;
int main()
{int T;scanf("%d",&T);while (T--){int n;scanf("%d",&n);int num=0;for (;n;n-=lbt(n)) num++;cout<<num<<endl;}
}
基础编程练习1
大象喝水
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define pi 3.14159
using namespace std;
double h,r,v;
int main()
{cin>>h>>r;int t=1;v=r*r*h*pi;while (v<=20000){t++;v+=r*r*h*pi;}cout<<t<<endl;
}
苹果和虫子
苹果吃光了就没得吃了…最小就是0
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
int n,x,y;
int main()
{scanf("%d%d%d",&n,&x,&y);if (y%x==0) n-=y/x;else n-=y/x+1;cout<<max(0,n)<<endl;
}
晶晶赴约会
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
int n;
int main()
{scanf("%d",&n);if (n==1||n==3||n==5) cout<<"NO";else cout<<"YES";
}
求一元二次方程的根
他们说这个题好像很坑的样子…
但是好像没什么啊1A了
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define eps 1e-5
using namespace std;
int n;
double a,b,c;
void print(double x)
{if (x<eps&&x>-eps) printf("0.00000");else printf("%.5lf",x);
}
int main()
{scanf("%d",&n);while (n--){scanf("%lf%lf%lf",&a,&b,&c);double delta=b*b-4*a*c;if (delta<eps&&delta>-eps){cout<<"x1=x2=";print((-b)/(2*a));cout<<endl;continue;}elseif (delta>eps){delta=sqrt(delta);cout<<"x1=";print((-b+delta)/(2*a));cout<<";x2=";print((-b-delta)/(2*a));cout<<endl;continue;}else{delta=-delta;delta=sqrt(delta)/(2*a);cout<<"x1=";print((-b)/(2*a));cout<<"+";print(delta);cout<<"i;x2=";print((-b)/(2*a));cout<<"-";print(delta);cout<<"i\n";}}
}
鸡兔同笼
据说Sunshine神犇写了Gauss来做这个题真心仰慕QwQ
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
int T;
int n;
int main()
{scanf("%d",&T);while (T--){scanf("%d",&n);if (n%2==1){cout<<"0 0\n";continue;}int maxn=0,minn=0;for (int i=n/4;i>=1;i--)if ((n-i*4)%2==0){minn=i+(n-i*4)/2;break;}for (int i=n/2;i>=1;i--)if ((n-i*2)%4==0){maxn=i+(n-i*2)/4;break;}cout<<minn<<' '<<maxn<<endl;}
}
判断闰年
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
int n;
int main()
{cin>>n;if (n%4==0){if (n%100==0&&n%400!=0){cout<<'N';return 0;}if (n%3200==0){cout<<'N';return 0;}cout<<"Y";return 0;}cout<<'N';
}
奇数求和
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
int m,n;
int sum;
int main()
{scanf("%d%d",&m,&n);for (int i=m;i<=n;i++)if (i%2==1) sum+=i;cout<<sum<<endl;
}
与7无关的数
一开始写成与7有关的了(/ω╲)
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
int n;
int sum;
int main()
{scanf("%d",&n);for (int i=1;i<=n;i++){int a=i/10,b=i%10;if (i%7==0)continue;if (a==7||b==7)continue;sum+=i*i;}cout<<sum;
}
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