UVa10019：Funny Encryption Method

题目：给一个数字，计算其为十进制和十六进制时转化为二进制后每个位上1的个数。

#include <stdio.h>int f(int num)
{int sum=0;while(num!=0){sum+=num%2;num/=2;}return sum;
}int main()
{int test, num;scanf("%d",&test);while(test--){scanf("%d",&num);int b1=0, b2=0;b1=f(num);while(num!=0){b2+=f(num%10);num/=10;}printf("%d %d\n",b1,b2);}
}

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UVa10019：Funny Encryption Method

题目：给一个数字，计算其为十进制和十六进制时转化为二进制后每个位上1的个数。

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