Codeforces Problem-69A Young Physicist

基本思想：

建立vector容器，一个容器代表一列，分别用v1，v2，v3表示。将输入的数据分别存入到三个容器中，判断最后各容器元素之和是否为0，然后输出相应结果即可。

AC代码：

#include <bits/stdc++.h>
using namespace std;int main()
{vector<int> v1,v2,v3;int n;int sumx=0,sumy=0,sumz=0;cin>>n;for (int i=0;i<n;i++){int x,y,z;cin>>x>>y>>z;v1.push_back(x);v2.push_back(y);v3.push_back(z);sumx+=v1[i];sumy+=v2[i];sumz+=v3[i];}cout<<((sumx==0&&sumy==0&&sumz==0)?"YES":"NO")<<endl;return 0;
}

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