创建数据库

create table student(sno varchar(10) primary key,sname varchar(20),sage numeric(2),ssex varchar(5)
);DROP table student;
DROP TABLE teacher;
create table teacher(tno varchar(10) primary key,tname varchar(20)
);create table course(cno varchar(10),cname varchar(20),tno varchar(20),constraint pk_course primary key (cno,tno)
);create table sc(sno varchar(10),cno varchar(10),score  numeric(4,2),constraint pk_sc primary key (sno,cno)
);
DROP TABLE sc;/*******初始化学生表的数据******/
insert into student values ('s001','张三',23,'男');
insert into student values ('s002','李四',23,'男');
insert into student values ('s003','吴鹏',25,'男');
insert into student values ('s004','琴沁',20,'女');
insert into student values ('s005','王丽',20,'女');
insert into student values ('s006','李波',21,'男');
insert into student values ('s007','刘玉',21,'男');
insert into student values ('s008','萧蓉',21,'女');
insert into student values ('s009','陈萧晓',23,'女');
insert into student values ('s010','陈美',22,'女');/******************初始化教师表***********************/
insert into teacher values ('t001', '刘阳');
insert into teacher values ('t002', '谌燕');
insert into teacher values ('t003', '胡明星');/***************初始化课程表****************************/
insert into course values ('c001','J2SE','t002');
insert into course values ('c002','Java Web','t002');
insert into course values ('c003','SSH','t001');
insert into course values ('c004','Oracle','t001');
insert into course values ('c005','SQL SERVER 2005','t003');
insert into course values ('c006','C#','t003');
insert into course values ('c007','JavaScript','t002');
insert into course values ('c008','DIV+CSS','t001');
insert into course values ('c009','PHP','t003');
insert into course values ('c010','EJB3.0','t002');/***************初始化成绩表***********************/
insert into sc values ('s001','c001',78.9);
insert into sc values ('s002','c001',80.9);
insert into sc values ('s003','c001',81.9);
insert into sc values ('s004','c007',60.9);
insert into sc values ('s001','c002',82.9);
insert into sc values ('s002','c002',72.9);
insert into sc values ('s003','c002',81.9);
insert into sc values ('s001','c003','59');
insert into sc values ('s001','c007','67');
insert into sc values ('s001','c010','98');

–
– 1、查询“c001”课程比“c002”课程成绩高的所有学生的学号；

-- 方法一：SELECT *FROM (SELECT * FROM sc WHERE cno = 'c001') as a,(SELECT * FROM sc WHERE cno = 'c002') as bWHERE a.sno = b.snoAND a.score>b.score

-- 方法二SELECT *FROM student a,sc b,sc cWHERE a.sno = b.snoAND b.cno = 'c001'AND a.sno = c.snoAND c.cno='c002'AND b.score>c.score

– 2、查询平均成绩大于60 分的同学的学号和平均成绩；

SELECT sno,GROUP_CONCAT(cno),avg(score)FROM scGROUP BY sno;

– 3、查询所有同学的学号、姓名、选课数、总成绩；

-- 方法一：SELECT student.sno,sname,sage,ssex,GROUP_CONCAT(cno),sum(score),COUNT(cno) as '选课数'FROM sc,studentWHERE student.sno = sc.snoGROUP BY sno;

– 方法二：

    SELECT student.sno,sname,sage,ssex,GROUP_CONCAT(cno),sum(score),COUNT(cno) as '选课数'FROM sc INNER JOIN studentON student.sno = sc.snoGROUP BY sno;

– 4、查询姓“刘”的老师的个数；

SELECT * ,COUNT(tname)FROM teacherWHERE `tname` LIKE '刘%'

– 5、查询没学过“谌燕”老师课的同学的学号、姓名；

    SELECT sno,snameFROM student WHERE  sno  NOT in (SELECT sno FROM sc WHERE cno  in(SELECT cno FROM course WHERE tno=(SELECT tno FROM teacher WHERE tname ='谌燕')))

– 6、查询学过“c001”并且也学过编号“c002”课程的同学的学号、姓名

方法一：
SELECT sno,sname
FROM student
WHERE  sno= ANY
(SELECT  sno FROM sc WHERE sno in
(SELECT sno FROM sc WHERE cno = 'c001') AND cno = 'c002');：
方法二：
SELECT a.sno,a.sname
FROM student a,sc b,sc c
WHERE a.sno = b.sno
AND b.cno = 'c001'
AND a.sno = c.sno
AND c.cno='c002'
方法三：
SELECT *
FROM
(SELECT * FROM sc WHERE cno = 'c001') as a,
(SELECT * FROM sc WHERE cno = 'c002') as b
WHERE a.sno = b.sno 

7、查询学过“谌燕”老师所教的所有课的同学的学号、姓名；

SELECT stu.sno,stu.sname from student stu where stu.sno in(
SELECT s.sno from sc s where s.cno in(
SELECT cno FROM course where tno in(
SELECT tno FROM teacher where tname='谌燕'
)))

8、查询课程编号“c002”的成绩比课程编号“c001”课程低的所有同学的学号、姓名；

SELECT *FROM student a,sc b,sc cWHERE a.sno = b.snoAND b.cno = 'c001'AND a.sno = c.snoAND c.cno='c002'AND b.score<c.score

–
– 9、查询所有课程成绩小于60 分的同学的学号、姓名；

    SELECT * FROM student WHERE SNO IN(SELECT snoFROM scWHERE SCORE<60)

– 10、查询没有学全所有课的同学的学号、姓名；

SELECT student.sno,sname,GROUP_CONCAT(sc.cno),COUNT(DISTINCT sc.cno)FROM student left JOIN scON student.sno=sc.sno GROUP BY student.snoHAVING COUNT(DISTINCT sc.cno)< any(sELECT COUNT(cno) FROM course);

– 11、查询至少有一门课与学号为“s001”的同学所学相同的同学的学号和姓名；

SELECT DISTINCT student.*
FROM student
WHERE sno IN (SELECT snoFROM scWHERE cno IN (SELECT cnoFROM sc WHERE sno = 's001'))  and student.sno!='s001'

– 12、查询至少学过学号为“s004”同学所学一门课的其他同学学号和姓名；s.sno!=’s004’

                SELECT DISTINCTstudent.*
FROMstudent
WHEREsno IN (SELECTsnoFROMscWHEREcno IN (SELECTcnoFROMscWHEREsno = 's004'))  and student.sno!='s004'

13、把“sc”表中“谌燕”老师教的课的成绩都更改为此课程的平均成绩；
参考答案：

update sc as s set s.score=
(select avg(score) from (select * from sc) as kwhere s.cno=k.cno group by k.cno)where cno in (select a.cno from (select * from sc)a,course b,teacher cwhere a.cno=b.cno and b.tno=c.tno and c.tname='谌燕');

–
– 14、查询和“s002”号的同学学习的课程’完全相同’的其他同学学号和姓名；

SELECT * FROM student where sno in(SELECT b.sno FROM
(SELECT sno,GROUP_CONCAT(cno) as gr,COUNT(cno)  FROM sc WHERE sno='s002' GROUP BY sno ) as a,(SELECT sno,GROUP_CONCAT(cno) as grc,COUNT(cno) FROM sc WHERE sno!='s002' GROUP BY sno) as bWHERE a.gr= b.grc
)

– 15、删除学习“谌燕”老师课的sc 表记录；

DELETE FROM sc   WHERE cno in(SELECT cno FROM course WHERE tno=(   SELECT tno FROM teacher WHERE tname ='谌燕'))

16、向SC 表中插入一些记录，这些记录要求符合以下条件：没有上过编号“c002”课程的同学学号、“c002”号课的平均成绩；
此题 有很大差异 与题目

            create table sc1(sno varchar(10),cno varchar(10),score  numeric(4,2),constraint pk_sc primary key (sno,cno));
insert into sc1 values ('s001','c001',78.9);
insert into sc1 values ('s002','c001',80.9);
insert into sc1 values ('s003','c001',81.9);
insert into sc1 values ('s004','c007',60.9);
insert into sc1 values ('s001','c002',82.9);
insert into sc1 values ('s002','c002',72.9);
insert into sc1 values ('s003','c002',81.9);
insert into sc1 values ('s001','c003','59');
insert into sc1 values ('s001','c007','67');
insert into sc1 values ('s001','c010','98');DELETE FROM sc1  WHERE cno='c002'(SELECT avg(sc.score) FROM sc WHERE sc.cno='c002') AS aUPDATE sc SET sc1.score = a;

参考答案

insert into sc (sno,cno,score) select sno,'c002',(select avg(score) from sc where cno='c002')
from sc where sno not in(select sno from sc where cno='c002');

– 17 查询各科成绩最高和最低的分：以如下形式显示：课程ID，最高分，最低分

SELECT cname as '课程ID',s  as '最高分',s3 as '最低分' FROM(SELECT * from course) as b,(SELECT sno,cno,GROUP_CONCAT(score) as a01,MAX(score) as s,MIN(score) as s3  FROM  sc GROUP BY sc.cno ) as awhere  a.cno=b.cno

18按各科平均成绩从低到高和及格率的百分数从高到低顺序（做不出来）

参考答案

select cno,AVG(score),(SELECT COUNT(*) FROM sc b where b.cno=sc.cno and score>60)*100/
(SELECT COUNT(*) FROM sc b where b.cno=sc.cno)"及格率"
FROM sc GROUP BY cno ORDER BY
AVG(score) asc,"及格率"desc;

19、查询不同老师所教不同课程平均分从高到低显示

select max(t.tno),max(t.tname),max(c.cno),max(c.cname),c.cno,avg(score) from sc , course c,teacher t
where sc.cno=c.cno and c.tno=t.tno group by c.cno order by avg(score) desc;

21、查询各科成绩前三名的记录:(不考虑成绩并列情况)

SELECT sno,cname,scoreFROMcourse as c,sc as sGROUP BY cnameORDER BY cname,score DESC LIMIT 0,3WHERE c.cno= s.cnoand c.cname (SELECT cname FROM course WHERE cno in(
SELECT  DISTINCT cno FROM sc
))ORDER BY score DESC LIMIT 0,2

– 22、查询每门课程被选修的学生数

SELECT cname,COUNT(sc.score) as "选修人数"FROMcourse ,sc WHERE course.cno= sc.cnoGROUP BY cname

– 23、查询出只选修了一门课程的全部学生的学号和姓名

SELECT *  FROM student WHERE   sno in(SELECT *FROMcourse ,sc WHERE course.cno= sc.cnoGROUP BY snoHAVING(COUNT(cname)=1))

– 24、查询男生、女生人数

        SELECT  ssex,COUNT(ssex)FROM studentWHERE ssex= "男"
UNIONSELECT  ssex,COUNT(ssex)FROM studentWHERE ssex= "女" 

– 25、查询姓“张”的学生名单

SELECT *FROM studentWHERE `sname` LIKE '张%'

–
– 26、查询同名同姓学生名单，并统计同名人数

select sname,count(*)from student group by sname having count(*)>1;

– 27、1996 年出生的学生名单(注：Student 表中Sage 列的类型是number)

select * FROM student WHERE  sage = 21

– 28、查询每门课程的平均成绩，结果按平均成绩升序排列，平均成绩相同时，按课程号降序排列

SELECT course.cno,cname,AVG( score) FROM course ,sc WHERE course.cno= sc.cnoGROUP BY cnoORDER BY AVG(score)  asc,cno DESC;

– 29、查询平均成绩大于85 的所有学生的学号、姓名和平均成绩

    SELECT student.sno,sname,avg(score)FROM student,sc WHERE student.sno= sc.snoGROUP BY student.snoHAVING (avg(score)>85)

– 30、查询课程名称为“数据库”，且分数低于80 的学生姓名和分数

    SELECT * FROM student WHERE student.sno in (SELECT snoFROM course,sc WHERE course.cno= 'c002'AND sc.score <80GROUP BY sc.sno)

– 31、查询所有学生的选课情况；

select sname,GROUP_CONCAT(cname)FROM student , sc,courseWHERE student.sno=sc.sno AND     course.cno=sc.cnoGROUP BY student.sno

– 32、查询任何一门课程成绩在70 分以上的姓名、课程名称和分数；

            SELECT sname,GROUP_CONCAT(cname),GROUP_CONCAT(score)FROM student , sc,courseWHERE student.sno=sc.sno AND     course.cno=sc.cnoand score>70GROUP BY student.sname 

– 33、查询不及格的课程，并按课程号从大到小排列

        SELECT cname,tnoFROM student , sc,courseWHERE student.sno=sc.sno AND     course.cno=sc.cnoand score<70ORDER BY tno DESC

– 34、查询课程编号为c001 且课程成绩在80 分以上的学生的学号和姓名；

    SELECT *FROM student , sc,courseWHERE student.sno=sc.sno AND     course.cno=sc.cnoand score>80AND sc.CNO = 'C001'

– 35、求选了课程的学生人数

    select snameFROM student , sc,courseWHERE student.sno=sc.sno AND     course.cno=sc.cnoGROUP BY student.sname

– 36、查询选修“谌燕”老师所授课程的学生中，成绩最高的学生姓名及其成绩
我的答案：

SELECT sname,scoreFROM sc,studentWHERE  score = (select max(score)from sc,course where sc.cno = course.cno)AND cno in(SELECT cno FROM course WHERE tno in(SELECT tno FROM teacher WHERE tname ='谌燕'))AND sc.sno=student.sno参考答案：select st.sname,score from student st,sc ,course c,teacher twhere st.sno=sc.sno and sc.cno=c.cno and c.tno=t.tnoand t.tname='谌燕' and sc.score=(select max(score)from sc where sc.cno=c.cno);

– 37、查询各个课程及相应的选修人数

    select cname, COUNT(sname) as '选修人数'from student st,sc,course cwhere st.sno=sc.sno and sc.cno=c.cno GROUP BY cname

– 38、查询不同课程成绩相同的学生的学号、课程号、学生成绩

    SELECT  a.sno,sname,b.cno,b.scoreFROM student a,sc b,sc cWHERE a.sno = b.snoAND a.sno = c.snoAND b.score=c.scoreAND c.cno   != b.cnoGROUP BY sno

39、查询每门功课成绩最好的前两名

– 40、统计每门课程的学生选修人数（超过10 人的课程才统计）。要求输出课程号和选修人数，查询结果按人数降序排列，
– 若人数相同，按课程号升序排列

SELECT cname,count(score)   as '选修人数'FROM course ,sc WHERE course.cno= sc.cnoGROUP BY cnameORDER BY count(score) desc,course.cno aSC;

– 41、检索至少选修两门课程的学生学号

SELECT s.sno,GROUP_CONCAT(cname),COUNT(cname)FROM course as c,sc,student as sWHERE c.cno= sc.cnoAND s.sno= sc.snoGROUP BY  sc.snoHAVING (COUNT(cname)>1)

– 42、查询全部学生都选修的课程的课程号和课程名

SELECT *,cname,count(score)FROM course as a,sc WHERE a.cno= sc.cno GROUP BY cnameHAVING COUNT(score)= any(sELECT COUNT(cno) FROM course)

– 43、查询没学过“谌燕”老师讲授的任一门课程的学生姓名

    SELECT student.sname FROM student WHERE student.sno   not in(SELECT cno FROM course WHERE tno in(SELECT tno FROM teacher WHERE tname ='谌燕'))

–
– 44、查询两门以上不及格课程的同学的学号及其平均成绩

SELECT *,COUNT(score),GROUP_CONCAT(score)FROM course as a,sc where score <70and a.cno = sc.cnoHAVING COUNT(score)>2

– 45、检索“c004”课程分数小于60，按分数降序排列的同学学号

SELECT *fROM course as a,sc where sc.cno = 'c004'and score <90and a.cno = sc.cnoORDER BY score DESC

–

– 46、删除“s002”同学的“c001”课程的成绩

delete from sc where sno='s002' and cno='c001';

高级查询习题1-46相关推荐

1. MySQL高级查询习题

   MySQL高级查询习题 提示: emp员工表(empno员工号/ename员工姓名/job工作/mgr上级编号/hiredate受雇日期/sal薪金/comm佣金/deptno所属部门编号) dept ...

2. mysql高级查询练习题_MySQL高级查询习题

   MySQL高级查询习题 提示: emp员工表(empno员工号/ename员工姓名/job工作/mgr上级编号/hiredate受雇日期/sal薪金/comm佣金/deptno所属部门编号) dept ...

3. jqgrid自定义列表开发=》实现高级查询

   标题已指出本文要说的三件事,首先是主角jqgrid,将应用在自定义列表中,重点介绍如何实现高级查询. 使用jqgrid实现自定义列表分为两大步骤,首先是要根据业务完成jqgrid的对象定义,即列表的描 ...

4. oracle将查询结果声明为伪表,Oracle查询操作（增删改查，伪表，高级查询）实例讲解...

   SQL查询操作:增删改查 一.SQL操作符 算术操作符 + - * / 比较操作符 = != < > <= >= BETWEEN--AND IN LINK IS NULL 逻辑 ...

5. ORACLE sql 高级查询

   Oracle-SQL高级查询 --一个题目涉及到的50个Sql语句  --(下面表的结构以给出,自己在数据库中建立表.并且添加相应的数据,数据要全面些. 其中Student表中,SId为学生的ID) ...

6. Mysql高级查询语句练习

   Mysql高级查询语句练习 DROP TABLE IF EXISTS `tblcourse`; CREATE TABLE `tblcourse` ( `CourseId` varchar(3) NOT ...

7. SQL高级查询（层次化查询，递归）

   SQL 高级查询 前面我们写了一下 SQL 的极简入门,今天来说点高级查询.没看到的朋友可以点击下面链接查看. 1 小时 SQL 极速入门(一) 1 小时 SQL 极速入门(二) 1 小时 SQL 极 ...

8. ylb：SQL 表的高级查询-多表连接和子查询

   ylbtech-SQL Server: SQL Server-表的高级查询-多表连接和子查询 SQL Server 表的高级查询-多表连接和子查询. 1,ylb:表的高级查询-多表连接和子查询 返回顶 ...

9. MySQL简单快速入门 (三)高级查询——JEPLUS软件快速开发平台

   03.SQL高级查询_分组: 1).需求:一条查询,查询出每种商品的最高价格 2).分组的命令:group by 分组字段 3).实现上例: select category_id,max(price) ...

最新文章

1. NCBI中SRA数据库简介
2. js中!和!!的区别及用法
3. 影响SDN和NFV部署速度的两个因素
4. MySQL BlackHole 存储引擎使用
5. java语言程序设计教程翁恺第二版课后答案_《JAVA语言程序设计教程(第2版)/翁恺 肖少拥》翁恺，肖少拥著【摘要 书评 在线阅读】-苏宁易购图书...
6. POI--HSSFCellStyle类
7. html设置控件位置大小,下面那个代码段设置myButton控件显示在HTML页左上角100px的位置 - 问答库...
8. linux rvm,RVM 实用指南
9. AutoCAD dwg(dxf)图外有多余的点或者线解决办法
10. ocr带单字坐标离线识别
11. DM数据库归档备份还原
12. UCOS操作系统——任务的挂起与恢复（四）
13. lora终端连接云服务器_开源LoRa网关与服务器
14. Openfile安装和使用
15. HTTP Status 400- Parameter conditions “username“ not met for actual request parameters:
16. MySQL解压版安装及配置(本地windows环境)
17. 读书笔记：机器学习实战(2)——章3的决策树代码和个人理解与注释
18. Credit Card Fraud Detection（信用卡欺诈检测相关数据集）
19. iOS--无法加载dae文件
20. ftp服务器怎么用，3步完成ftp的安装与使用

热门文章

1. 数据结构(陈越、何钦铭)学习笔记
2. CentOS 163镜像使用帮助
3. 数学小抄: 对于齐次变换矩阵的伴随算子求导性质
4. Trinoo DDOS 攻击软件分析
5. getvod.php_PHPvod模板开发手册PHPvod模板开发手册.pdf
6. BP商业计划书应该怎样撰写？
7. 用chrome浏览器上的Markdown Viewer打开本地的md文件
8. php养老院管理系统论文,基于Web的养老院管理系统的设计任务书
9. k8s之pod管理详解
10. golang的GJSON库