C语言自动发牌程序，供大家参考，具体内容如下：

一副扑克有52张牌，打桥牌时应将牌分给4个人。请设计一个程序完成自动发牌的工作。要求：黑桃用S (Spaces)表示，红桃用H (Hearts)表示，方块用D (Diamonds)表示，梅花用C (Clubs)表示。

分析：

要设置数组表现扑克牌

要设置数组表现玩家

要给扑克牌做特定标识，得到结果后玩家要知道自己手中黑桃有哪些、方块有哪些

初步想法：

设置4个字符数组保存4种梅花牌，设置4个字符数组表示4名玩家分配到的牌

每张牌随机发给4名玩家，当玩家的持牌数达到13，不再分配给该名玩家牌

代码展示：

void mycode_13(){srand(unsigned(time(NULL)));/*全部牌*/char S[13] = { '2', '3', '4', '5', '6', '7', '8', '9', 'T', 'J', 'Q', 'K', 'A' };char H[13] = { '2', '3', '4', '5', '6', '7', '8', '9', 'T', 'J', 'Q', 'K', 'A' };char D[13] = { '2', '3', '4', '5', '6', '7', '8', '9', 'T', 'J', 'Q', 'K', 'A' };char C[13] = { '2', '3', '4', '5', '6', '7', '8', '9', 'T', 'J', 'Q', 'K', 'A' };/*4个玩家*/char player1[13], player2[13], player3[13], player4[13];int p1 = 0, p2 = 0, p3 = 0, p4 = 0;distribution(S, player1, player2, player3, player4, &p1, &p2, &p3, &p4);distribution(H, player1, player2, player3, player4, &p1, &p2, &p3, &p4);distribution(D, player1, player2, player3, player4, &p1, &p2, &p3, &p4);distribution(C, player1, player2, player3, player4, &p1, &p2, &p3, &p4);puts("运行结束");for (int i = 0; i < 13; i++)printf("%c ", player1[i]);putchar('\n');for (int i = 0; i < 13; i++)printf("%c ", player2[i]);putchar('\n');for (int i = 0; i < 13; i++)printf("%c ", player3[i]);putchar('\n');for (int i = 0; i < 13; i++)printf("%c ", player4[i]);}void distribution(char * S_H_D_C, char * player1, char * player2, char * player3, char * player4, int *p1, int *p2, int *p3, int *p4){static int h = 1;int r;int a = *p1, b = *p2, c = *p3, d = *p4;for (int i = 0; i < 13; i++){r = (rand() % 4) + 1;while ((r == 1 && (*p1) == 13) || (r == 2 && (*p2) == 13) || (r == 3 && (*p3) == 13) || (r == 4 && (*p4) == 13))  r = (rand() % 4) + 1;switch (r){case 1:  player1[(*p1)++] = S_H_D_C[i];  break;case 2:  player2[(*p2)++] = S_H_D_C[i];  break;case 3:  player3[(*p3)++] = S_H_D_C[i];  break;case 4:  player4[(*p4)++] = S_H_D_C[i];  break;default:  break;}}switch (h++){case 1:  printf("黑桃：\n");  break;case 2:  printf("红桃：\n");  break;case 3:  printf("方块：\n");  break;case 4:  printf("梅花：\n");  break;}printf("Player1:");for (int i = a; i < (*p1); i++)  printf("%c ", player1[i]);putchar('\n');printf("Player2:");for (int i = b; i < (*p2); i++)  printf("%c ", player2[i]);putchar('\n');printf("Player3:");for (int i = c; i < (*p3); i++)  printf("%c ", player3[i]);putchar('\n');printf("Player4:");for (int i = d; i < (*p4); i++)  printf("%c ", player4[i]);putchar('\n');}

以下代码保证了当某个人得到13张牌后不在得牌：

r = (rand() % 4) + 1;while ((r == 1 && (*p1) == 13) || (r == 2 && (*p2) == 13) || (r == 3 && (*p3) == 13) || (r == 4 && (*p4) == 13))  r = (rand() % 4) + 1;

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