1006. Sign In and Sign Out (25)

时间限制

400 ms

内存限制

65536 kB

代码长度限制

16000 B

判题程序

Standard

作者

CHEN, Yue

At the beginning of every day, the first person who signs in the computer room will unlock the door, and the last one who signs out will lock the door. Given the records of signing in's and out's, you are supposed to find the ones who have unlocked and locked the door on that day.

Input Specification:

Each input file contains one test case. Each case contains the records for one day. The case starts with a positive integer M, which is the total number of records, followed by M lines, each in the format:

ID_number Sign_in_time Sign_out_time

where times are given in the format HH:MM:SS, and ID number is a string with no more than 15 characters.

Output Specification:

For each test case, output in one line the ID numbers of the persons who have unlocked and locked the door on that day. The two ID numbers must be separated by one space.

Note: It is guaranteed that the records are consistent. That is, the sign in time must be earlier than the sign out time for each person, and there are no two persons sign in or out at the same moment.

Sample Input:

3
CS301111 15:30:28 17:00:10
SC3021234 08:00:00 11:25:25
CS301133 21:45:00 21:58:40

Sample Output:

SC3021234 CS301133

#include<stdio.h>
struct{char a[16];int in,out;
}id[1000000];
int main(){int m;scanf("%d",&m);int i,in1,in2,in3,out1,out2,out3;for(i=0;i<m;i++){scanf("%s %d:%d:%d %d:%d:%d",id[i].a,&in1,&in2,&in3,&out1,&out2,&out3);id[i].in=in1*10000+in2*100+in3;id[i].out=out1*10000+out2*100+out3;}int small,big,si=0,bi=0;small=id[0].in;big=id[0].out;for(i=1;i<m;i++){if(id[i].in<small){small=id[i].in;si=i;}if(id[i].out>big){big=id[i].out;bi=i;}            }printf("%s %s",id[si].a,id[bi].a);return 0;
}

浙大PAT甲级1006相关推荐

PAT甲级1006 Sign In and Sign Out：[C++题解]字符串处理
文章目录题目分析题目链接题目分析读入三个字符串. 需要记录最早开门的人的id和时间,最晚离开的人的id和时间. 本题的简单之处在于时间的位数都相同,比如 10点和01点.因此这样的时间大小比 ...
浙大PAT甲级1040
浙大PAT甲级1040 原题问题分析原题 1040 Longest Symmetric String (25 分) Given a string, you are supposed to outp ...
浙大PAT甲级1019. General Palindromic Number (20)
1019. General Palindromic Number (20) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN ...
【PAT - 甲级1006】Sign In and Sign Out (25分)（STLmap）
题干: At the beginning of every day, the first person who signs in the computer room will unlock the d ...
浙大PAT甲级1027. Colors in Mars (20)
1027. Colors in Mars (20) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue People ...
浙大 PAT 甲级1009
1009. Product of Polynomials (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yu ...
浙大PAT甲级-1017
银行队列: (却没用到队列) #include <iostream> #include <string> #include <algorithm> #include ...
浙大PAT甲级-1021
还是看了凌大佬的博客才全部ac的 (https://blog.csdn.net/iaccepted/article/details/20454519) #include <iostream> ...
PAT甲级题目解析和知识点分类整理
转载请注明出处个人博客:https://maxusun.github.io/ 今天整理电脑,发现了去年为了考研浙大计算机整理的PAT资料.现在考研已经尘埃落定.想到当时盲目刷题浪费了好多时间,在这里 ...

浙大PAT甲级1006

1006. Sign In and Sign Out (25)

浙大PAT甲级1006相关推荐

最新文章

热门文章