您可以使用pygame的colliderect检查冲突

首先，创建三个矩形，表示三个选项矩形：simulator_rect = pygame.Rect(600, 125, 30, 30)

quiz_rect = pygame.Rect(225, 125, 30, 30)

quit_rect = pygame.Rect(375, 425, 30, 30)

接下来，我们将创建一个表示蓝色选择器rect的rect：

^{pr2}$

现在你得到了只创建一次的矩形，而不是每次都创建的未命名矩形

现在，对于实际的碰撞检测：

^{3}$

最终代码：import pygame

pygame.init()

screen = pygame.display.set_mode((800, 600))

done = False

x = 30

y = 30

clock = pygame.time.Clock()

# RGB values for red

red = (255, 0 ,0)

# Your three button rects :

simulator_rect = pygame.Rect(225, 125, 30, 30)

quiz_rect = pygame.Rect(600, 125, 30, 30)

quit_rect = pygame.Rect(375, 425, 30, 30)

# These represent your three option rects

option_rects = [simulator_rect, quiz_rect, quit_rect]

# Your blue selector rect

selector_rect = pygame.Rect(50, 50, 60, 60)

# The 50, 50 xy coords are temporary

while not done:

for event in pygame.event.get():

if event.type == pygame.QUIT:

done = True

pressed = pygame.key.get_pressed()

if pressed[pygame.K_UP] and y > 0: y -= 5

if pressed[pygame.K_DOWN] and y < 600 - 60: y += 5

if pressed[pygame.K_LEFT] and x > 0: x -= 5

if pressed[pygame.K_RIGHT] and x < 800 - 60: x += 5

# Set the slector rect's coords to x/y

selector_rect.x, selector_rect.y = x, y

screen.fill((0, 0, 0))

color = (0, 128, 255)

pygame.draw.rect(screen, color, selector_rect)

myfont = pygame.font.SysFont("monospace", 15)

label = myfont.render("Start the experiment simulator", 1, (255,255,255))

screen.blit(label, (100, 100))

label2 = myfont.render("Start the quiz", 1, (255,255,255))

screen.blit(label2, (550, 100))

label3 = myfont.render("Quit game", 1, (255,255,255))

screen.blit(label3, (350, 400))

# Use our created rects

pygame.draw.rect(screen, red, simulator_rect)

pygame.draw.rect(screen, red, quiz_rect)

pygame.draw.rect(screen, red, quit_rect)

# Check to see if the user presses the enter key

if pressed[pygame.K_RETURN]:

# Check to see if the selection rect

# collides with any other rect

for rect in option_rects:

# Add rects as needed

if selector_rect.colliderect(rect):

if rect == simulator_rect:

# Do simulations stuff!

print('Simulating!')

elif rect == quiz_rect:

# Do quizzing stuff!

print('Quizzing!')

elif rect == quit_rect:

# Quit!

done = True

pygame.display.flip()

clock.tick(60)

这确实给你的程序增加了一些复杂度，但至少这是一个坚如磐石的方法，你也可以添加一些特性，而且这将保持健壮。在