题意：

n个点，分成两组A，B，如果点i在A中，那么贡献值\(a_i\)，反之为\(b_i\)。
现要求任意\(i \in A，j \in B\)不存在 \(x_i >= x_j\) 且 \(y_i <= y_j\)，也就是说A中点不在B中点的右下方。

思路：

https://blog.nowcoder.net/n/7205418146f3446eb0b1ecec8d2ab1da

代码：

#include<cmath>
#include<set>
#include<map>
#include<queue>
#include<cstdio>
#include<vector>
#include<cstring>
#include <iostream>
#include<algorithm>
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
const int maxn = 1e5 + 5;
const int M = 50 + 5;
const ull seed = 131;
const int INF = 0x3f3f3f3f;
const int MOD = 1000000007;
struct Node{int x, y, a, b;
}p[maxn];
bool cmp(Node x, Node y){if(x.x == y.x) return x.y > y.y;return x.x < y.x;
}
vector<int> vv;
ll Max[maxn << 2], lazy[maxn << 2];
void pushup(int rt){Max[rt] = max(Max[rt << 1], Max[rt << 1 | 1]);
}
void pushdown(int rt){if(lazy[rt]){lazy[rt << 1] += lazy[rt];lazy[rt << 1 | 1] += lazy[rt];Max[rt << 1] += lazy[rt];Max[rt << 1 | 1] += lazy[rt];lazy[rt] = 0;}
}
void build(int l, int r, int rt){Max[rt] = lazy[rt] = 0;if(l == r) return;int m = (l + r) >> 1;build(l, m, rt << 1);build(m + 1, r, rt << 1 | 1);
}
void update(int L, int R, int l, int r, int v, int rt){if(L > R) return;if(L <= l && R >= r){Max[rt] += v;lazy[rt] += v;return;}pushdown(rt);int m = (l + r) >> 1;if(L <= m)update(L, R, l, m, v, rt << 1);if(R > m)update(L, R, m + 1, r, v, rt << 1 | 1);pushup(rt);
}
void change(int pos , int l, int r, ll v, int rt){if(l == r){Max[rt] = max(Max[rt], v);return;}pushdown(rt);int m = (l + r) >> 1;if(pos <= m)change(pos, l, m, v, rt << 1);elsechange(pos, m + 1, r, v, rt << 1 | 1);pushup(rt);
}
ll query(int L, int R, int l, int r, int rt){if(L <= l && R >= r){return Max[rt];}pushdown(rt);int m = (l + r) >> 1;ll MAX = -1;if(L <= m)MAX = max(MAX, query(L, R, l, m, rt << 1));if(R > m)MAX = max(MAX, query(L, R, m + 1, r, rt << 1 | 1));pushup(rt);return MAX;
}
int main(){int n;while(~scanf("%d", &n)){vv.clear();for(int i = 1; i <= n; i++){scanf("%d%d%d%d", &p[i].x, &p[i].y, &p[i].a, &p[i].b);vv.push_back(p[i].y);}vv.push_back(-1);sort(vv.begin(), vv.end());vv.erase(unique(vv.begin(), vv.end()), vv.end());for(int i = 1; i <= n; i++) p[i].y = lower_bound(vv.begin(), vv.end(), p[i].y) - vv.begin() + 1;sort(p + 1, p + n + 1, cmp);build(1, vv.size(), 1);for(int i = 1; i <= n; i++){ll tmp = query(1, p[i].y, 1, vv.size(), 1);update(p[i].y, vv.size(), 1, vv.size(), p[i].b, 1);update(1, p[i].y - 1, 1, vv.size(), p[i].a, 1);change(p[i].y, 1, vv.size(), tmp + p[i].b, 1);}printf("%lld\n", Max[1]);}return 0;
}