---恢复内容开始---

[20170603]12c Top Frequency histogram.txt

--//个人对直方图了解很少,以前2种直方图类型对于目前的许多应用来讲已经足够,或者讲遇到的问题很少.
--//抽一点点时间,简单探究12c Top Frequency histogram.

--//以前的频率直方图Frequency histogram,受限bucket(桶的大小),如果有255个不同值,oracle分析后不会建立频率直方图,而是建立高
--//度直方图.这样的情况会导致一些流行值的统计在显示执行计划时差距很大.而12c引入了Top Frequency histogram,注意这里的top,
--//我的理解就是流行值(popular),也就是这样建立的直方图仅仅包括popular,其他non-popular不考虑,这样在sql语句的查询这些
--//popular时,显示的统计信息相对准确,从而有利于oracle选择正确的执行计划.

--//以下是我的学习笔记,也许会存在许多错误,仅仅做一个记录.我也看了许多别人的blog.^_^.而且我目前的环境只有12.0.0.1(版本太
--//低).

1.环境:
SCOTT@test01p> @ ver1
PORT_STRING                    VERSION        BANNER                                                                               CON_ID
------------------------------ -------------- -------------------------------------------------------------------------------- ----------
IBMPC/WIN_NT64-9.1.0           12.1.0.1.0     Oracle Database 12c Enterprise Edition Release 12.1.0.1.0 - 64bit Production              0

--//如果要建立Top Frequency histogram必须要满足几个条件:
--//链接 raajeshwaran.blogspot.co.id/2016/06/top-frequency-histogram-in-12c.html

The database creates a Top frequency histogram, when the following criteria are met.

NDV is greater than n, where n is the requested number of buckets (default 254)
The percentage of rows occupied by Top-frequent values is greater than or equal to the threshold p where p is (1-(1/n)*100).
The estimate_percent parameter in dbms_stats gathering procedure should be auto_sample_size (set to default)

--//翻译过来NDV(也就是字段的不同值)大于N(指bucket的数量).
--//流行值(popular)在Top-frequent中合计数量/总计数量之比要大于(1-(1/n)*100).如果建立10个桶,这样流行值的总计必须在90%以上

2.首先验证(1-(1/n)*100)比值是否正确:
SCOTT@test01p> create table t as select * from dba_objects;
Table created.

select column_name,num_distinct,density,histogram,SAMPLE_SIZE
  from user_tab_col_statistics
  where table_name ='T'
  and column_name ='OWNER';

COLUMN_NAME          NUM_DISTINCT    DENSITY HISTOGRAM       SAMPLE_SIZE
-------------------- ------------ ---------- --------------- -----------
OWNER                          32     .03125 NONE                  91695

--//12c ctas 建立统计信息,但是不会建立直方图.density 1/32=.03125.
SCOTT@test01p> select count(*) from t;
  COUNT(*)
----------
     91695

--//随手写的sql语句:

with a as (select distinct owner,count(*) over(partition by owner) n1 ,count(*) over () n2 from t order by 2 desc ),
b as (select owner,n1,n2,sum(n1) over (order by n1 desc) n3  from a order by n1 desc)
select rownum,owner,n1,n2,n3,round(n3/n2,5) x1,round(1-1/rownum,5) x2 from b;

ROWNUM OWNER                N1         N2         N3         X1         X2
------ ----------------- ----- ---------- ---------- ---------- ----------
     1 SYS               41942      91695      41942     .45741          0
     2 PUBLIC            37142      91695      79084     .86247         .5
     3 APEX_040200        3405      91695      82489      .8996     .66667
     4 ORDSYS             3157      91695      85646     .93403        .75
     5 MDSYS              1819      91695      87465     .95387         .8
     6 XDB                 985      91695      88450     .96461     .83333
     7 SYSTEM              641      91695      89091      .9716     .85714
     8 CTXSYS              405      91695      89496     .97602       .875
     9 WMSYS               387      91695      89883     .98024     .88889
    10 DVSYS               352      91695      90235     .98408         .9
    11 SH                  309      91695      90544     .98745     .90909
    12 ORDDATA             292      91695      90836     .99063     .91667
    13 LBACSYS             209      91695      91045     .99291     .92308
    14 OE                  142      91695      91187     .99446     .92857
    15 SCOTT                96      91695      91283     .99551     .93333
    16 GSMADMIN_INTERNAL    77      91695      91360     .99635      .9375
    17 IX                   58      91695      91418     .99698     .94118
    18 DBSNMP               55      91695      91473     .99758     .94444
    19 PM                   44      91695      91517     .99806     .94737
    20 HR                   35      91695      91552     .99844        .95
    21 OLAPSYS              25      91695      91577     .99871     .95238
    22 OJVMSYS              23      91695      91600     .99896     .95455
    23 DVF                  19      91695      91619     .99917     .95652
    24 FLOWS_FILES          13      91695      91632     .99931     .95833
    25 AUDSYS               12      91695      91644     .99944        .96
    26 ORDPLUGINS           10      91695      91664     .99966     .96154
    27 OUTLN                10      91695      91664     .99966     .96296
    28 BI                    8      91695      91688     .99992     .96429
    29 ORACLE_OCM            8      91695      91688     .99992     .96552
    30 SI_INFORMTN_SCHEM     8      91695      91688     .99992     .96667
    31 APPQOSSYS             5      91695      91693     .99998     .96774
    32 TEST                  2      91695      91695          1     .96875

--//如果加入条件where round(n3/n2,5) >round(1-1/rownum,5),全部输出.也就是这样如果桶小于32,大于1.建立的都是Top Frequency.

3.继续测试:
D:\temp>cat a1.sql
cat a1.sql
exec  dbms_stats.gather_table_stats(ownname=>user,tabname=>'T',method_opt=>'for columns owner size &1');
select column_name,num_distinct,density,histogram,SAMPLE_SIZE from user_tab_col_statistics where table_name ='T' and column_name ='OWNER';

SCOTT@test01p> @ a1.sql 2
PL/SQL procedure successfully completed.

COLUMN_NAME          NUM_DISTINCT    DENSITY HISTOGRAM       SAMPLE_SIZE
-------------------- ------------ ---------- --------------- -----------
OWNER                          32     .03125 HYBRID                 5500

SCOTT@test01p> @ a1.sql 3
PL/SQL procedure successfully completed.

COLUMN_NAME          NUM_DISTINCT    DENSITY HISTOGRAM       SAMPLE_SIZE
-------------------- ------------ ---------- --------------- -----------
OWNER                          32 5.4529E-06 TOP-FREQUENCY         91695

SCOTT@test01p> @ a1.sql 4
PL/SQL procedure successfully completed.

COLUMN_NAME          NUM_DISTINCT    DENSITY HISTOGRAM       SAMPLE_SIZE
-------------------- ------------ ---------- --------------- -----------
OWNER                          32 5.4529E-06 TOP-FREQUENCY         91695

SCOTT@test01p> @ a1.sql 31
PL/SQL procedure successfully completed.
COLUMN_NAME          NUM_DISTINCT    DENSITY HISTOGRAM       SAMPLE_SIZE
-------------------- ------------ ---------- --------------- -----------
OWNER                          32 5.4529E-06 TOP-FREQUENCY         91695

SCOTT@test01p> @ a1.sql 32
PL/SQL procedure successfully completed.

COLUMN_NAME          NUM_DISTINCT    DENSITY HISTOGRAM       SAMPLE_SIZE
-------------------- ------------ ---------- --------------- -----------
OWNER                          32 5.4529E-06 FREQUENCY             91695

--//除了bucket=2,32建立的直方图HYBRID,FREQUENCY外,建立的都是TOP-FREQUENCY.
--//以10个bucket为例.解方程式(90235-x)/(91695-x)=0.9 ,得到x=77095.也就是要减少77095.

--//delete t where owner='SYS' and rownum<=41000;
--//delete t where owner='PUBLIC' and rownum<=36095;

SCOTT@test01p> delete t where owner='SYS' and rownum<=41000;
41000 rows deleted.

SCOTT@test01p> delete t where owner='PUBLIC' and rownum<=36095;
36095 rows deleted.

SCOTT@test01p> commit ;
Commit complete.

with a as (select distinct owner,count(*) over(partition by owner) n1 ,count(*) over () n2 from t order by 2 desc ),
b as (select owner,n1,n2,sum(n1) over (order by n1 desc) n3  from a order by n1 desc)
select rownum,owner,n1,n2,n3,round(n3/n2,5) x1,round(1-1/rownum,5) x2 from b where rownum<=11;

ROWNUM OWNER         N1         N2         N3         X1         X2
------ ----------- ---- ---------- ---------- ---------- ----------
     1 APEX_040200 3405      14600       3405     .23322          0
     2 ORDSYS      3157      14600       6562     .44945         .5
     3 MDSYS       1819      14600       8381     .57404     .66667
     4 PUBLIC      1047      14600       9428     .64575        .75
     5 XDB          985      14600      10413     .71322         .8
     6 SYS          942      14600      11355     .77774     .83333
     7 SYSTEM       641      14600      11996     .82164     .85714
     8 CTXSYS       405      14600      12401     .84938       .875
     9 WMSYS        387      14600      12788     .87589     .88889
    10 DVSYS        352      14600      13140         .9         .9
    11 SH           309      14600      13449     .92116     .90909
11 rows selected.
--//backet=10,前面10个值占90%.

SCOTT@test01p> @ a1 10
PL/SQL procedure successfully completed.
COLUMN_NAME          NUM_DISTINCT    DENSITY HISTOGRAM       SAMPLE_SIZE
-------------------- ------------ ---------- --------------- -----------
OWNER                          32 .000034247 TOP-FREQUENCY         14600

--//再减少1条记录.
SCOTT@test01p> delete t where owner='SYS' and rownum<=1;
1 row deleted.

SCOTT@test01p> commit ;
Commit complete.

ROWNUM OWNER         N1         N2         N3         X1         X2
------ ----------- ---- ---------- ---------- ---------- ----------
     1 APEX_040200 3405      14599       3405     .23324          0
     2 ORDSYS      3157      14599       6562     .44948         .5
     3 MDSYS       1819      14599       8381     .57408     .66667
     4 PUBLIC      1047      14599       9428      .6458        .75
     5 XDB          985      14599      10413     .71327         .8
     6 SYS          941      14599      11354     .77772     .83333
     7 SYSTEM       641      14599      11995     .82163     .85714
     8 CTXSYS       405      14599      12400     .84937       .875
     9 WMSYS        387      14599      12787     .87588     .88889
    10 DVSYS        352      14599      13139     .89999         .9
    11 SH           309      14599      13448     .92116     .90909
11 rows selected.
--//现在前10占.89999.

SCOTT@test01p> @ a1 10
PL/SQL procedure successfully completed.

COLUMN_NAME          NUM_DISTINCT    DENSITY HISTOGRAM       SAMPLE_SIZE
-------------------- ------------ ---------- --------------- -----------
OWNER                          32    .018378 HYBRID                14599

--//可以发现建立的直方图不是TOP-FREQUENCY,而是HYBRID(混合型直方图).

4.转化成TOP-FREQUENCY.
SCOTT@test01p> insert into t  select * from dba_objects where owner='SYS' and rownum=1;
1 row created.

SCOTT@test01p> commit ;
Commit complete.

SCOTT@test01p> @ a1 10
PL/SQL procedure successfully completed.

COLUMN_NAME          NUM_DISTINCT    DENSITY HISTOGRAM       SAMPLE_SIZE
-------------------- ------------ ---------- --------------- -----------
OWNER                          32 .000034247 TOP-FREQUENCY         14600

--//DENSITY=1/SAMPLE_SIZE/2, 1/14600/2=.00003424657534246575正好符合.

5.现在看看执行计划:
SCOTT@test01p> select count(*) from t where owner='DVSYS';
  COUNT(*)
----------
       352

SCOTT@test01p> @ dpc '' ''
PLAN_TABLE_OUTPUT
-------------------------------------
SQL_ID  2at34f0zaqhzj, child number 0
-------------------------------------
select count(*) from t where owner='DVSYS'
Plan hash value: 2966233522
---------------------------------------------------------------------------------------------------------------------
| Id  | Operation          | Name | Starts | E-Rows |E-Bytes| Cost (%CPU)| E-Time   | A-Rows |   A-Time   | Buffers |
---------------------------------------------------------------------------------------------------------------------
|   0 | SELECT STATEMENT   |      |      1 |        |       |   428 (100)|          |      1 |00:00:00.01 |    1544 |
|   1 |  SORT AGGREGATE    |      |      1 |      1 |     8 |            |          |      1 |00:00:00.01 |    1544 |
|*  2 |   TABLE ACCESS FULL| T    |      1 |    352 |  2816 |   428   (0)| 00:00:01 |    352 |00:00:00.01 |    1544 |
---------------------------------------------------------------------------------------------------------------------
Query Block Name / Object Alias (identified by operation id):
-------------------------------------------------------------
   1 - SEL$1
   2 - SEL$1 / T@SEL$1
Predicate Information (identified by operation id):
---------------------------------------------------
   2 - filter("OWNER"='DVSYS')

--//可以发现e_rows=A-Rows.可以发现非常准确.
--//查看直方图信息.

SCOTT@test01p> select endpoint_number,endpoint_actual_value from user_tab_histograms where table_name ='T' and column_name ='OWNER' order by 1;
ENDPOINT_NUMBER ENDPOINT_ACTUAL_VALU
--------------- --------------------
           3405 APEX_040200
           3810 CTXSYS
           4162 DVSYS
           5981 MDSYS
           9138 ORDSYS
          10185 PUBLIC
          11127 SYS
          11768 SYSTEM
          12155 WMSYS
          13140 XDB
10 rows selected.

--//4162-3810=352,可以发现正好符合.也就是popular值统计很正确.看看非popular值.

SCOTT@test01p> select count(*) from t where owner='DVSYS1';
  COUNT(*)
----------
         0

Plan hash value: 2966233522        
---------------------------------------------------------------------------------------------------------------------
| Id  | Operation          | Name | Starts | E-Rows |E-Bytes| Cost (%CPU)| E-Time   | A-Rows |   A-Time   | Buffers |
---------------------------------------------------------------------------------------------------------------------
|   0 | SELECT STATEMENT   |      |      1 |        |       |   428 (100)|          |      1 |00:00:00.01 |    1544 |
|   1 |  SORT AGGREGATE    |      |      1 |      1 |     8 |            |          |      1 |00:00:00.01 |    1544 |
|*  2 |   TABLE ACCESS FULL| T    |      1 |     66 |   528 |   428   (0)| 00:00:01 |      0 |00:00:00.01 |    1544 |
---------------------------------------------------------------------------------------------------------------------

SCOTT@test01p> select count(*) from t where owner='SCOTT';
  COUNT(*)
----------
        96

Plan hash value: 2966233522
---------------------------------------------------------------------------------------------------------------------
| Id  | Operation          | Name | Starts | E-Rows |E-Bytes| Cost (%CPU)| E-Time   | A-Rows |   A-Time   | Buffers |
---------------------------------------------------------------------------------------------------------------------
|   0 | SELECT STATEMENT   |      |      1 |        |       |   428 (100)|          |      1 |00:00:00.01 |    1544 |
|   1 |  SORT AGGREGATE    |      |      1 |      1 |     8 |            |          |      1 |00:00:00.01 |    1544 |
|*  2 |   TABLE ACCESS FULL| T    |      1 |     66 |   528 |   428   (0)| 00:00:01 |     96 |00:00:00.01 |    1544 |
---------------------------------------------------------------------------------------------------------------------

--//可以发现估计E-Rows如何计算的呢?

6.做10053跟踪:
D:\tools\sqllaji>cat 10053x.sql
execute dbms_sqldiag.dump_trace(p_sql_id=>'&1',p_child_number=>&2,p_component=>'Compiler',p_file_id=>'&&1');

SCOTT@test01p> @ 10053x f31kz63ksu1tc 0
PL/SQL procedure successfully completed.

***************************************
SINGLE TABLE ACCESS PATH
  Single Table Cardinality Estimation for T[T]
SPD: Return code in qosdDSDirSetup: NOCTX, estType = TABLE
  Column (#1):
    NewDensity:0.004545, OldDensity:0.000034 BktCnt:13140.000000, PopBktCnt:13140.000000, PopValCnt:10, NDV:32
  Column (#1): OWNER(VARCHAR2)
    AvgLen: 8 NDV: 32 Nulls: 0 Density: 0.000000
    Histogram: Top-Freq  #Bkts: 13140  UncompBkts: 13140  EndPtVals: 10  ActualVal: yes
  Table: T  Alias: T
    Card: Original: 14600.000000  Rounded: 66  Computed: 66.36  Non Adjusted: 66.36
  Access Path: TableScan
    Cost:  428.36  Resp: 428.36  Degree: 0
      Cost_io: 428.00  Cost_cpu: 14122025
      Resp_io: 428.00  Resp_cpu: 14122025
  Best:: AccessPath: TableScan
         Cost: 428.36  Degree: 1  Resp: 428.36  Card: 66.36  Bytes: 0

check parallelism for statement[<unnamed>]
kkfdtParallel: parallel is possible (no statement type restrictions)
    kkfdPaForcePrm: dop:1 ()
     use dictionary DOP(1) on table
kkfdPaPrm:- The table : 106380
kkfdPaPrm:DOP = 1 (computed from hint/dictionary/autodop)
kkfdiPaPrm: dop:1 serial(?)
***************************************

--//使用 NewDensity:0.004545.
 BktCnt:13140.000000, PopBktCnt:13140.000000 => 对应就是前10个流行值的总和.

--//非流行值的数量: 14600-13140=1460
--//非流行值的桶数量: 32-10=22
--//非流行值的数量/非流行值的桶数量 1460/22=66.36363636363636363636,四舍五入66,正好符合执行计划的推断.
--//NewDensity的计算 =1460/14600/22=.00454545454545454545,非常接近.

---恢复内容结束---

转载于:https://www.cnblogs.com/lfree/p/6947417.html

[20170603]12c Top Frequency histogram.txt相关推荐

  1. [20170604]12c Top Frequency histogram补充.txt

    [20170604]12c Top Frequency histogram补充.txt 1.环境: SCOTT@test01p> @ ver1 PORT_STRING               ...

  2. oracle 分桶函数,Oracle 12c新特性 - Top frequency histogram 3

    4.     生成top frequency histogram 的必要条件: 1). The data set has more than n distinct values.  (n表示桶数量) ...

  3. [20180914]oracle 12c 表 full_hash_value如何计算.txt

    [20180914]oracle 12c 表 full_hash_value如何计算.txt --//昨天在12c下看表full_hash_value与11g的full_hash_value不同,不过 ...

  4. Requests+Xpath 爬取豆瓣读书TOP并生成txt,csv,json,excel文件

    说明: ##来源:https://www.cnblogs.com/yizhiamumu/p/10270926.html 1 Requests+Xpath 爬取豆瓣读书TOP ''' Requests+ ...

  5. SQL调优指南笔记11:Histograms

    本文为SQL Tuning Guide第11章"Histograms"的笔记. 重要基本概念 endpoint value An endpoint value is the hig ...

  6. 2.1_11 Oralce 执行计划之3_直方图(Histograms)

    目录 Summarize 总结 一.Purpose of Histograms 二.When Oracle Database Creates Histograms 三.How Oracle Datab ...

  7. linux top p 乱码,将Linux top命令输入到指定文件时的乱码问题

    根据需求,项目需要读取linux系统环境参数,所以需要将top命令的输出结果输入到文件中.用重定向命令如下:top > result.txt .用vi打开文件: vi result.txt .显 ...

  8. 组合保险策略及相应模拟测算工具----Discrete Hedging: Guaranteed CPPI Structures

    组合保险策略及相应模拟测算工具----Discrete Hedging: Guaranteed CPPI Structures 最近将 open code 稍作修改  做了一个CPPI模拟测算工具,h ...

  9. r语言mfrow全程_如何使用R完成文章中图片处理小教程

    一起成长的经历 - 技术服务  课程定制 - - 如何使用R完成文章中图片处理小教程 - Two Histograms with melt colors 柱状图显示数值变量的分布.这篇文章解释了如何在 ...

最新文章

  1. 【控制】《多智能体系统一致性与复杂网络同步控制》郭凌老师-目录
  2. WebServices 简介
  3. mysql教程实验4.1_【MySQL】数据库课程实验
  4. 与JavaWeb有关的故事(Web请求与Java IO)
  5. win32com下载地址
  6. 还挺好看!用命令行画思维导图;66天机器学习之旅;斯坦福CS234 强化学习课程;哈佛CS50 计算机科学导论课程;前沿论文 | ShowMeAI资讯日报
  7. 查询oracle所有回收站,oracle 回收站
  8. for循环后面的分号
  9. 韩式多用动态图(甜蜜女孩)
  10. animate.css插件指南
  11. 2021最全大数据学习路线(建议收藏)
  12. brew安装时fatal: not in a git directory Error: Command failed with exit 128: git
  13. 奇点临近:互联网经济的供给侧革命和全球货币政策的新格林斯潘之谜
  14. 平面几何相关算法整理
  15. 创业兵法—选择最适合你的创业项目
  16. Bootstarp 响应式 Web模板
  17. MT6158原理图,MT6158处理器参数,MT6158射频芯片资料
  18. 激光SLAM-地图边界噪点的处理(地图的美化)--图像处理的方法
  19. JAVA docx/doc转html代码
  20. 石墨烯是一种由碳原子紧密堆积构成的二维晶体,你了解它的特性和应用吗?

热门文章

  1. SpringBoot响应Json数据乱码通过配置解决
  2. XCode中修改应用的名字
  3. springbatch的reader,如何使用mybatis?使用MyBatisCursorItemReader可以完美解决
  4. 【知识图谱】知识存储
  5. 电机控制器软件设计规范_电机控制器市场及重点企业分析
  6. SPringBoot+mybatis 框架搭建例子
  7. Unity重置Animator到初始状态和重复播放同一个Animation
  8. 转载 - 背景透明,文字不透明【学习】
  9. Android的init过程:init.rc解析流程
  10. 如何确定Oracle是32 Bit(位)的还是64 Bit(位)的?