5、完整的测试代码 [java] package org.ml.test; import java.text.ParseException; import java.text.SimpleDateFormat; import java.util.Calendar; import java.util.Date; public class CalendarDemo { public

5、完整的测试代码　　[java]

package org.ml.test;

import java.text.ParseException;

import java.text.SimpleDateFormat;

import java.util.Calendar;

import java.util.Date;

public class CalendarDemo {

public static void main(String[] args) {

String strDate = "2013-03-08";// 定义日期字符串

SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd");// 定义日期格式

Date date = null;

try {

date = format.parse(strDate);// 将字符串转换为日期

} catch (ParseException e) {

System.out.println("输入的日期格式不合理！");

}

System.out.println(strDate + "是:" + getWeek(date));

System.out.println(strDate + "是一年的第:" + getWeekOfYear(date) + "周");

System.out.println(strDate + "是一年的" + (date.getMonth() + 1) + "月有:"

+ getDaysOfMonth(date.getYear(), date.getMonth() + 1) + "天");

System.out.println(strDate + "距离" + (format.format(new Date())) + "还有"

+ getDaysBetween(date, new Date()) + "天");

}

// 根据日期取得星期几

public static String getWeek(Date date) {

// String[] weeks = {"星期日","星期一","星期二","星期三","星期四","星期五","星期六"};

// Calendar cal = Calendar.getInstance();

// cal.setTime(date);

// int week_index = cal.get(Calendar.DAY_OF_WEEK) - 1;

// if(week_index<0){

// week_index = 0;

// }

// return weeks[week_index];

SimpleDateFormat sdf = new SimpleDateFormat("EEEE");

String week = sdf.format(date);

return week;

}

// 取得日期是某年的第几周

public static int getWeekOfYear(Date date) {

Calendar cal = Calendar.getInstance();

cal.setTime(date);

int week_of_year = cal.get(Calendar.WEEK_OF_YEAR);

return week_of_year;

}

// 取得某个月有多少天

public static int getDaysOfMonth(int year, int month) {

Calendar cal = Calendar.getInstance();

cal.set(Calendar.YEAR, year);

cal.set(Calendar.MONTH, month-1);

int days_of_month = cal.getActualMaximum(Calendar.DAY_OF_MONTH);

return days_of_month;

}

// 取得两个日期之间的相差多少天

public static long getDaysBetween(Date date0, Date date1) {

long daysBetween = (date0.getTime() - date1.getTime() + 1000000) / 86400000;// 86400000=3600*24*1000  用立即数，减少乘法计算的开销

return daysBetween;

}

}

6、测试结果