LeetCode Sum Root to Leaf Numbers (dfs)

问题：给出一个二叉树，求从根结点到叶子结点路径上构成的所有数的和

思路：自顶向下遍历过程中，递归的终止条件是，如果是叶子结点，返回上一层的数*10加上叶子结点的值。在遍历过程中，如果存在左子树，计算左子树的和，存在右子树，计算右子树的和，最后作累加

具体代码参考：

https://github.com/wuli2496/OJ/tree/master/LeetCode/Sum%20Root%20to%20Leaf%20Numbers

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