我有两个问题： -

问题编号：1(PHP相关)

我无法在PHP页面上显示图像数组。这里是我正在尝试的代码..

getUser.php

$q=$_GET["q"];

$con = mysql_connect('localhost', 'sulen', '123');

if (!$con)

{

die('Could not connect: ' . mysql_error());

}

mysql_select_db("holidayNet", $con);

$sql="SELECT * FROM image WHERE id = '".$q."'";

$result = mysql_query($sql);

echo "

while($row = mysql_fetch_array($result))

{

echo "

";

echo "

" . $row['FirstName'] . "";

echo "

" . $row['LastName'] . "";

echo "

" . $row['Age'] . "";

echo "

" . $row['Hometown'] . "";

$dir = 'images';

$file_display = array('jpg','jpeg','png','gif');

if (file_exists ($dir) == false) {

echo 'Directory \'', $dir, '\' not found!';

}

else{

$dir_contents = scandir($dir);

foreach($dir_contents as $file) {

$file_type = strtolower(end(explode('.', $file)));

If($file !== '.' && $file !== '..' && in_array($file_type, $file_display) ==

true) {

echo "

" . $row [''] . "";

}

}

}

/*echo "

" . $row['Job'] . "";*/

echo "

";

}

echo "

";

mysql_close($con);

?>

one.html

function showUser(str)

{

if (str=="")

{

document.getElementById("txtHint").innerHTML="";

return;

}

if (window.XMLHttpRequest)

{// code for IE7+, Firefox, Chrome, Opera, Safari

xmlhttp=new XMLHttpRequest();

}

else

{// code for IE6, IE5

xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");

}

xmlhttp.onreadystatechange=function()

{

if (xmlhttp.readyState==4 && xmlhttp.status==200)

{

document.getElementById("txtHint").innerHTML=xmlhttp.responseText;

}

}

xmlhttp.open("GET","getuser.php?q="+str,true);

xmlhttp.send();

}

Select a person:

Sulman qb

asd asd

Glenn Quagmire

Joseph Swanson

问题2(AJAX相关)

您可能在上面的代码中看到，在使用AJAX时，我从数据库检索图像目录路径。现在，我将如何将该目录路径给php文件getUser.php或

$dir = 'images'(need that path here !);