Majority Element：主元素

Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times.

You may assume that the array is non-empty and the majority element always exist in the array.

求主元素：包括n个元素的数组中。假设一个元素的出现次数大于n/2（向下取整）次。则该元素为主元素。

依据定义，则每两个数中必有一个是主元素，设定一个变量cnt=0。当两个数同样时。cnt++，不同一时候，cnt--。用变量

majority来记录主元素，每当cnt=0时，把当前元素赋给majority。成为候选的主元素。这样一来。最后的majority的值一定就是主元素。

代码例如以下：

class Solution {
public:
int majorityElement(vector<int> &num) {int majority;int cnt = 0;for(int i=0; i<num.size(); i++){if ( cnt ==0 ){majority = num[i];cnt++;}else{majority == num[i] ? cnt++ : cnt --;if (cnt > num.size()/2) return majority;}}return majority;}
};

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