本文实例讲述了Python实现的根据文件名查找数据文件功能。分享给大家供大家参考，具体如下：

#-*- coding: UTF-8 -*-

import os

import shutil

AllFiles=[]

NameFiles=[]

def findFie(filePath):

pathDir = os.listdir(filePath)

for allDir in pathDir:

# print(allDir)

AllFiles.append(allDir)

#pass

#filepath = 'C:\\Users\\IBM_ADMIN\\Desktop\\cognos\\datastage\\71&72\\71\\71sns'

#copyfile = 'C:\\Users\\IBM_ADMIN\\Desktop\\cognos\\datastage\\71&72\\71mtp'

filepath = 'C:\\Users\\IBM_ADMIN\\Desktop\\cognos\\datastage\\71&72\\72\\72sns'

copyfile = 'C:\\Users\\IBM_ADMIN\\Desktop\\cognos\\datastage\\71&72\\72mtp'

shutil.rmtree(copyfile)

os.mkdir(copyfile)

findFie(filepath)

def readFile():

readFile = open('./jobname')

i = 0

for eachLine in readFile:

i= i + 1

#print(eachLine)

NameFiles.append(eachLine.replace('\n','')) # 去掉换行符

readFile()

#字符串比较

def doTheCompare():

for x in NameFiles:

print(x)

for y in AllFiles:

if x == y :

copyFrom = os.path.join(filepath,x)

copyTo = os.path.join(copyfile,x)

shutil.copyfile(copyFrom,copyTo)

else:

pass

#print ("file not find under sns process,thanks .please check with wumi.")

doTheCompare()

附：这里再补充一个更为简单的文件搜索功能示例：

# -*- coding:utf-8 -*-

import os

def search(path=".", name="1"):

for item in os.listdir(path):

item_path = os.path.join(path, item)

if os.path.isdir(item_path):

search(item_path, name)

elif os.path.isfile(item_path):

if name in item:

print(item_path)

if __name__ == "__main__":

search(path=r"D:\360Downloads",name="dll")

希望本文所述对大家Python程序设计有所帮助。