HDU 2602 Bone Collector DP(01背包)

Bone Collector

Time Limit:1000MS Memory Limit:32768KB 64bit IO Format:%I64d & %I64u

Description

Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …
The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ?

Input

The first line contain a integer T , the number of cases.
Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone.

Output

One integer per line representing the maximum of the total value (this number will be less than 2 ³¹).

Sample Input

Sample Output

14

很基础的一道dp熟悉一下

#include <iostream>
#include <cstring>
#include <cstdio>
#include <algorithm>
#include <queue>
#include <vector>
#include <iomanip>
#include <math.h>
#include <map>
using namespace std;
#define FIN     freopen("input.txt","r",stdin);
#define FOUT    freopen("output.txt","w",stdout);
#define INF     0x3f3f3f3f
#define lson    l,m,rt<<1
#define rson    m+1,r,rt<<1|1
typedef long long LL;const int MAXN=1005;
int dp[MAXN][MAXN];
int value[MAXN];
int volume[MAXN];int main()
{//FINint T;scanf("%d",&T);while(T--){int n,v;scanf("%d%d",&n,&v);for(int i=1;i<=n;i++)scanf("%d",&value[i]);for(int i=1;i<=n;i++)scanf("%d",&volume[i]);memset(dp,0,sizeof(dp));for(int i=1;i<=n;i++)for(int j=0;j<=v;j++){if(j>=volume[i])dp[i][j]=max(dp[i-1][j],dp[i-1][j-volume[i]]+value[i]);elsedp[i][j]=dp[i-1][j];}printf("%d\n",dp[n][v]);}}

转载于:https://www.cnblogs.com/Hyouka/p/5730984.html

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