482. License Key Formatting

最后更新

一刷
11-Jan-2017

这个题是Ez难度的吧。。。

注意edge cases就行。

熟悉下Character的方程:
Character.isDigit(c);
Character.isAlphabetic(c);

另外String.toUpperCase()就可以，没必要每一个char都尝试Character.toUpperCase()

Time Complexity:
O(N)
Space: constant

public class Solution {public String licenseKeyFormatting(String S, int K) {if (K <= 0 || S.length() == 0) return "";StringBuilder sb = new StringBuilder();int total = 0;for (int i = S.length() - 1; i >= 0; i --) {char c = S.charAt(i);if (Character.isDigit(c) || Character.isAlphabetic(c)) {sb.append(c);if (++total % 4 == 0) {sb.append('-');}}}sb.reverse();if (sb.length() != 0 && sb.charAt(0) == '-') {sb.deleteCharAt(0);}return sb.toString().toUpperCase();}
}

转载于:https://www.cnblogs.com/reboot329/p/6276676.html

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