尝试这个：

Date date = new Date(logEvent.timeSTamp); DateFormat formatter = new SimpleDateFormat("HH:mm:ss:SSS"); String dateFormatted = formatter.format(date);

其他符号列表

long second = (millis / 1000) % 60; long minute = (millis / (1000 * 60)) % 60; long hour = (millis / (1000 * 60 * 60)) % 24; String time = String.format("%02d:%02d:%02d:%d", hour, minute, second, millis);

我将向您展示三种方式(a)从长整型值中获取分钟字段，(b)使用所需的date格式打印。 一个使用java.util.Calendar ，另一个使用Joda-Time ，最后一个使用Java 8及更高版本内置的java.time框架。

java.time框架取代了旧的捆绑date时间类，并受Joda-Time(由JSR 310定义)的启发，并由ThreeTen-Extra项目扩展。

使用Java 8及更高版本时，java.time框架是要走的路。 否则，比如Android，使用Joda-Time。 java.util.Date/.Calendar类非常麻烦，应该避免。

java.util.Date＆.Calendar

final long timestamp = new Date().getTime(); // with java.util.Date/Calendar api final Calendar cal = Calendar.getInstance(); cal.setTimeInMillis(timestamp); // here's how to get the minutes final int minutes = cal.get(Calendar.MINUTE); // and here's how to get the String representation final String timeString = new SimpleDateFormat("HH:mm:ss:SSS").format(cal.getTime()); System.out.println(minutes); System.out.println(timeString);

乔达时间

// with JodaTime 2.4 final DateTime dt = new DateTime(timestamp); // here's how to get the minutes final int minutes2 = dt.getMinuteOfHour(); // and here's how to get the String representation final String timeString2 = dt.toString("HH:mm:ss:SSS"); System.out.println(minutes2); System.out.println(timeString2);

输出：

24

09：24：10：254

24

09：24：10：254

java.time

long millisecondsSinceEpoch = 1289375173771L; Instant instant = Instant.ofEpochMilli ( millisecondsSinceEpoch ); ZonedDateTime zdt = ZonedDateTime.ofInstant ( instant , ZoneOffset.UTC ); DateTimeFormatter formatter = DateTimeFormatter.ofPattern ( "HH:mm:ss:SSS" ); String output = formatter.format ( zdt ); System.out.println ( "millisecondsSinceEpoch: " + millisecondsSinceEpoch + " instant: " + instant + " output: " + output );

毫秒自始至终：1289375173771瞬间：2010-11-10T07：46：13.771Z输出：07：46：13：771

可以使用apache commons(commons-lang3)及其DurationFormatUtils类。

org.apache.commonscommons-lang33.1

例如：

String formattedDuration = DurationFormatUtils.formatDurationHMS(12313152); // formattedDuration value is "3:25:13.152" String otherFormattedDuration = DurationFormatUtils.formatDuration(12313152, DurationFormatUtils.ISO_EXTENDED_FORMAT_PATTERN); // otherFormattedDuration value is "P0000Y0M0DT3H25M13.152S"

希望它可以帮助…

long second = TimeUnit.MILLISECONDS.toSeconds(millis); long minute = TimeUnit.MILLISECONDS.toMinutes(millis); long hour = TimeUnit.MILLISECONDS.toHours(millis); millis -= TimeUnit.SECONDS.toMillis(second); return String.format("%02d:%02d:%02d:%d", hour, minute, second, millis);

干

logEvent.timeStamp / (1000*60*60)

会给你几个小时，而不是几分钟。 尝试：

logEvent.timeStamp / (1000*60)

你最终会得到与之相同的答案

TimeUnit.MILLISECONDS.toMinutes(logEvent.timeStamp)

public static String timeDifference(long timeDifference1) { long timeDifference = timeDifference1/1000; int h = (int) (timeDifference / (3600)); int m = (int) ((timeDifference - (h * 3600)) / 60); int s = (int) (timeDifference - (h * 3600) - m * 60); return String.format("%02d:%02d:%02d", h,m,s);

尝试这个：

String sMillis = "10997195233"; double dMillis = 0; int days = 0; int hours = 0; int minutes = 0; int seconds = 0; int millis = 0; String sTime; try { dMillis = Double.parseDouble(sMillis); } catch (Exception e) { System.out.println(e.getMessage()); } seconds = (int)(dMillis / 1000) % 60; millis = (int)(dMillis % 1000); if (seconds > 0) { minutes = (int)(dMillis / 1000 / 60) % 60; if (minutes > 0) { hours = (int)(dMillis / 1000 / 60 / 60) % 24; if (hours > 0) { days = (int)(dMillis / 1000 / 60 / 60 / 24); if (days > 0) { sTime = days + " days " + hours + " hours " + minutes + " min " + seconds + " sec " + millis + " millisec"; } else { sTime = hours + " hours " + minutes + " min " + seconds + " sec " + millis + " millisec"; } } else { sTime = minutes + " min " + seconds + " sec " + millis + " millisec"; } } else { sTime = seconds + " sec " + millis + " millisec"; } } else { sTime = dMillis + " millisec"; } System.out.println("time: " + sTime);