实现这个功能很easy，仅仅须要重写moveCells方法就能够了。以下是源文件里的代码：

mxGraph.prototype.moveCells = function(cells, dx, dy, clone, target, evt) {if (cells != null && (dx != 0 || dy != 0 || clone || target != null)) {this.model.beginUpdate();try {if (clone) {cells = this.cloneCells(cells, this.isCloneInvalidEdges());if (target == null) {target = this.getDefaultParent();}}this.cellsMoved(cells, dx, dy, !clone && this.isDisconnectOnMove() && this.isAllowDanglingEdges(), target == null);if (target != null) {var index = this.model.getChildCount(target);this.cellsAdded(cells, target, index, null, null, true);}this.fireEvent(new mxEventObject(mxEvent.MOVE_CELLS, 'cells', cells, 'dx', dx, 'dy', dy, 'clone', clone, 'target', target, 'event', evt));} finally {this.model.endUpdate();}}return cells;
};

接下来要对这种方法进行改造。加一句就能够了

mxGraph.prototype.moveCells = function(cells, dx, dy, clone, target, evt) {clone=evt.ctrlKey;//对。就是这啦！

if (cells != null && (dx != 0 || dy != 0 || clone || target != null)) { this.model.beginUpdate(); try { if (clone) { cells = this.cloneCells(cells, this.isCloneInvalidEdges()); if (target == null) { target = this.getDefaultParent(); } } this.cellsMoved(cells, dx, dy, !clone && this.isDisconnectOnMove() && this.isAllowDanglingEdges(), target == null); if (target != null) { var index = this.model.getChildCount(target); this.cellsAdded(cells, target, index, null, null, true); } this.fireEvent(new mxEventObject(mxEvent.MOVE_CELLS, 'cells', cells, 'dx', dx, 'dy', dy, 'clone', clone, 'target', target, 'event', evt)); } finally { this.model.endUpdate(); } } return cells; };

是的。实现这个功能的确非常easy。可是往往实际项目中会有不同的需求。比方一个数据库关系图，复制一个字段到还有一张表中的时候；选择了多个图形而且包含关系线的是时候是否须要复制关系；假设图形存在子图形。是否须要一同复制；当前选择的图形是不是同意移动/复制。移动进入目标图形，目标图形是否同意该操作等等，这些就须要在这种方法区域中进行复杂的推断。