zip压缩包在解压过程中，遇到了错误，提示如下

java.lang.IllegalArgumentException: MALFORMED

at java.util.zip.ZipCoder.toString(Unknown Source)

at java.util.zip.ZipInputStream.readLOC(Unknown Source)

at java.util.zip.ZipInputStream.getNextEntry(Unknown Source)

at com.yc.utils.TestZip.extZipFileList(TestZip.java:40)

at com.yc.utils.TestZip.main(TestZip.java:21)

查阅网上的资料，有一个说是编码的问题，

看看老外怎么说，参考了一下，确实是编码的问题。附上我的部分解压缩代码

public static void unzip(String zipFilePath, String targetPath)

throws IOException {

OutputStream os = null;

InputStream is = null;

ZipFile zipFile = null;

try {

zipFile = new ZipFile(zipFilePath,Charset.forName("GBK"));

String directoryPath = "";

if (null == targetPath || "".equals(targetPath)) {

directoryPath = zipFilePath.substring(0, zipFilePath

.lastIndexOf("."));

} else {

directoryPath = targetPath;

}

Enumeration> entryEnum = zipFile.entries();

if (null != entryEnum) {

ZipEntry zipEntry = null;

while (entryEnum.hasMoreElements()) {

zipEntry = (ZipEntry) entryEnum.nextElement();

if (zipEntry.getSize() > 0) {

// 文件

File targetFile = FileUtil.buildFile(directoryPath

+ File.separator + zipEntry.getName(), false);

os = new BufferedOutputStream(new FileOutputStream(targetFile));

is = zipFile.getInputStream(zipEntry);

byte[] buffer = new byte[4096];

int readLen = 0;

while ((readLen = is.read(buffer, 0, 4096)) >= 0) {

os.write(buffer, 0, readLen);

os.flush();

}

is.close();

os.close();

}

if (zipEntry.isDirectory()) {

String pathTemp = directoryPath + File.separator

+ zipEntry.getName();

File file = new File(pathTemp);

file.mkdirs();

System.out.println(pathTemp);

// continue;

}

}

}

} catch (IOException ex) {

throw ex;

} finally {

if(null != zipFile){

zipFile.close();

zipFile = null;

}

if (null != is) {

is.close();

}

if (null != os) {

os.close();

}

}

}

声明：

zipFile = new ZipFile(zipFilePath,Charset.forName("GBK"));不是所有压缩包的编码都是GBK，针对不同情况需要特殊处理。