2018 BACS Regional Programming Contest C. BACS, Scoundrel Shopkeeper and Contiguous Sequence (模拟)
Description
Solution
模拟
Code
const int maxn = 1e2 + 7;
int a[maxn];
int main() {int T;scanf("%d",&T);for(int cas = 1;cas <= T;++cas) {int n,m;scanf("%d %d",&m,&n);ll sum = 0;for(int i = 1;i <= n;++i) {scanf("%d",&a[i]); sum += a[i];}bool flag1 = false, flag2 = false;if(sum == m) flag1 = true;for(int i = 1;i < n;++i) {if(a[i+1] - a[i] == 1) {flag2 = true; break;}}printf("Case %d: Thank You BACS!!!", cas);if(flag1) printf(" Thik ache."); else printf(" Bojjat dokandar!!");if(flag2) printf(" Yes\n"); else printf(" No\n"); }
}
2018 BACS Regional Programming Contest C. BACS, Scoundrel Shopkeeper and Contiguous Sequence (模拟)相关推荐
- 2018-2019 ICPC Northwestern European Regional Programming Contest (NWERC 2018)
2018-2019 ICPC Northwestern European Regional Programming Contest (NWERC 2018) 题号 题目 知识点 难度 A Access ...
- 2018 German Collegiate Programming Contest (GCPC 18)
2018 German Collegiate Programming Contest (GCPC 18) Attack on Alpha-Zet 建树,求lca 代码: #include <al ...
- 2021 HZNU Winter Training Day 17 (2018 German Collegiate Programming Contest (GCPC 18))
2021 HZNU Winter Training Day 17 (2018 German Collegiate Programming Contest (GCPC 18)) 题目 A B C D E ...
- 2021-2022 ACM-ICPC Latin American Regional Programming Contest
2021-2022 ACM-ICPC Latin American Regional Programming Contest J. Joining Pairs 思路: 本题显然答案为NNN的情况为两条 ...
- 2020-2021 ICPC Southeastern European Regional Programming Contest (SEERC 2020)
2020-2021 ICPC Southeastern European Regional Programming Contest (SEERC 2020) B. Reverse Game 题目描述: ...
- The 2020 ICPC Asia Shenyang Regional Programming Contest I题 Rise of Shadows（数论）
题目链接The 2020 ICPC Asia Shenyang Regional Programming Contest 题目大意: 一天内有H小时,每小时M分钟,时针分针以恒定速率旋转. 现在若时针 ...
- The 2020 ICPC Asia Yinchuan Regional Programming Contest
The 2020 ICPC Asia Yinchuan Regional Programming Contest A 开三个vector数组存储x,y,z轴上的点,unique+erase去重 #in ...
- The 2022 ICPC Asia Hangzhou Regional Programming Contest
比赛连接:Dashboard - The 2022 ICPC Asia Hangzhou Regional Programming Contest - Codeforces A. Modulo Rui ...
- Gym 101964 2018-2019 ACM-ICPC Southeastern European Regional Programming Contest (SEERC 2018)
传送门 A.Numbers B.Broken Watch 先考虑最简单的情况,就是a,b,c都相等的情况,这个时候答案显然只会跟n有关系,在n个线段里面选3个的情况就是C(n,3),其中有一部分不合法 ...
最新文章
- WR：微生物污染源解析中宿主特异性标记物在中国的表现特征
- IndexError: too many indices for array
- 【数字信号处理】傅里叶变换性质 ( 傅里叶变换线性性质 | 傅里叶变换时移性质 )
- AngularJS 深入理解 $scope 转载▼
- sqlite java需要按照,SQLite:java/jdbsqlite和python/sqlite3的区别
- 【收藏】编译安装keepalived
- 51中断编程c语言,[新人求指教]51C语言编程可否用中断令循环结束提早结束
- ajax和spa的区别,在XX团上消费过一次不正规的Spa，现在过来两个月公安局打电话叫我过去...
- java 线程 内存分配内存_漫谈JAVA语言的内存分配
- Eclipse中使用Gradle构建Java Web项目
- python如何使数据加行_如何使用 Python 插入行
- java计算两点距离,java计算两点间的距离方法总结，java计算两点距离
- 虚拟同步发电机_学术简报基于分散式微电网的虚拟同步发电机无通信预同步并网方案...
- （几何方面：正六边形面积）编写一个程序，提示用户输入正六边形的边长并显示它的面积。
- Android接入微信登陆
- 电商广告推荐系统案例
- 线上线下教学如何有效衔接
- YOLO---Darknet下的学习笔记
- 四位urf8存入mysql_MySql 中文写入数据库乱码及Incorrect string value: '\xF0\x9F...' for column 'XXX' at row 1解决...
- jpg图片转换成pdf的方法