原文转载链接找不着了。

以下问转载内容：

第一种：

--获取当前日期是本月的第几周
--测试：select dbo.getMonthWeek(getdate()) 结果:10月的第2周
CREATE function [dbo].[getMonthWeek](@d datetime)
returns varchar(20)
as
begin
declare @returns varchar(20),@monthfirstDay datetime,@firstMondy datetimeselect @monthfirstDay=left(convert(varchar,@d,23),7)+'-01'if not exists(select 1 from master.dbo.spt_valueswhere type=N'P' and number between 0 and datediff(d,@monthfirstDay,@d)and datepart(dw,dateadd(d,number,@monthfirstDay))=2)
beginselect @monthfirstDay=dateadd(mm,-1,@monthfirstDay)
end;with t as(select 'days'=dateadd(d,number,@monthfirstDay)from master.dbo.spt_valueswhere type=N'P' and number<=7)select @firstMondy=min([days]) from twhere datepart(dw,[days])=2select @returns=rtrim(datepart(mm,@monthfirstDay))+'月的第'+rtrim(datediff(d,@firstMondy,@d)/7+1)+'周'return @returns
end

第二种：

--获取当前日期是本月的第几周
--测试：select dbo.WeekOfMonth(getDate());结果:2
CREATE   FUNCTION   [dbo].[WeekOfMonth](@day datetime)
RETURNS int
AS
begin  ----declare @day datetime
declare @num int
declare @Start datetime
declare @dd int
declare @dayofweek char(8)
declare @dayofweek_num char(8)
declare @startWeekDays int
---set @day='2009-07-05'
if datepart(dd,@day)=1
return 1
else
set @Start= (SELECT   DATEADD(mm,   DATEDIFF(mm,0,@day),   0)) --一个月第一天的
set @dayofweek= (datename(weekday,@Start)) ---得到本月第一天是周几
set @dayofweek_num=(select (case @dayofweek when '星期一' then 2
when '星期二' then 3
when '星期三' then 4
when '星期四' then 5
when '星期五' then 6
when '星期六' then 7
when '星期日' then 1
end))
set @dayofweek_num= 7-@dayofweek_num+1 ---得到本月的第一周一共有几天
---print @dayofweek_num   set @dd=datepart(dd,@day) ----得到今天是这个月的第几天
--print @dd
if @dd<=@dayofweek_num --小于前一周的天数
return 1
else
set @dd=@dd-@dayofweek_num
if @dd % 7=0  begin  set @num=@dd / 7  return @num+1  end  else --if @dd % 7<>0   set @num=@dd / 7
set @num=@num+1+1  return @num
end