本文实例为大家分享了python实现人民币转大写人民币的具体代码，供大家参考，具体内容如下

直接上代码：

# -*- coding: utf-8 -*-

def changenum( change_number ):

format_num = ["零","壹","贰","叁","肆","伍","陆","柒","捌","玖"]

format_name = ["分", "角", "元",

"拾","百","千","万",

"拾","百","千","亿",

"拾","百","千","万",

"拾","百","千","兆"]

if type( change_number ) == str:

if '.' in change_number:

try: change_number = float( change_number )

except: raise ValueError, '%s can\'t change'%change_number

else:

try: change_number = int( change_number )

except: raise ValueError, '%s can\'t change'%change_number

if type( change_number ) == float:

real_numbers = []

for i in range( len( format_name ) - 3, -3, -1 ):

if change_number >= 10 ** i or i < 1:

real_numbers.append( int( round( change_number/( 10**i ), 2)%10 ) )

elif isinstance( change_number, (int, long) ):

real_numbers = [ int( i ) for i in str( change_number ) + '00' ]

else:

raise ValueError, '%s can\'t change'%change_number

zflag = 0

start = len(real_numbers) - 3

change_words = []

for i in range(start, -3, -1):

if 0 <> real_numbers[start-i] or len(change_words) == 0:

if zflag:

change_words.append(format_num[0])

zflag = 0

change_words.append( format_num[ real_numbers[ start - i ] ] )

change_words.append(format_name [i+2])

elif 0 == i or (0 == i%4 and zflag < 3):

change_words.append(format_name [i+2])

zflag = 0

else:

zflag += 1

if change_words[-1] not in (format_name[0], format_name[1]):

change_words.append("整")

return ''.join(change_words)

#测试

# print changenum(865324.98)

#查看输出的结果是否正确

以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持脚本之家。