我使用(jsp，servlet，apache tomcat 9，eclipse neon，oracle 11g)创建了一个servlet项目。 我已经创建了index.jsp(以获取登录详细信息并重定向到LoginServlet以便在数据库表中进行用户名和密码验证。在index.jsp中，我什至提到了“ register.jsp”链接来进行首次登录的用户的注册)。 当我运行项目index.jsp时，页面打开。

当我提供用户ID和密码详细信息(在数据库中手动输入的用户名和密码详细信息)时，它成功地将我重定向到LoginServlet，然后是servlet。

但是，当我单击“注册”链接时，出现上述错误( HTTP状态[404]？[未找到]类型状态报告消息/TodayServlet/register.jsp描述原始服务器未找到以下内容的当前表示形式：目标资源或不愿意透露其存在。Apache Tomcat / 9.0.0.M20 )

我的问题是来自index.jsp，我无法打开“ register.jsp”(通过index.jsp中的定位标记提供的“ register.jsp”)。

请找到我的目录结构附件和主要的jsp，servlet和web.xml代码。

index.jsp(主要代码)：

pageEncoding="ISO-8859-1"%>

Insert title here

enter name:

enter pass:

New User Register here...!!!

register.jsp(主要代码)：

pageEncoding="ISO-8859-1"%>

Insert title here

enter name:

enter pass:

enter email:

RegisterServlet.java(主代码)：

package com.pack;

import java.io.IOException;

import java.io.PrintWriter;

import java.sql.Connection;

import java.sql.PreparedStatement;

import java.sql.ResultSet;

import javax.servlet.ServletException;

import javax.servlet.http.HttpServlet;

import javax.servlet.http.HttpServletRequest;

import javax.servlet.http.HttpServletResponse;

public class RegisterServlet extends HttpServlet {

protected void doPost(HttpServletRequest req, HttpServletResponse res) throws ServletException, IOException {

res.setContentType("text/html");

PrintWriter out=res.getWriter();

String uname1=req.getParameter("name1");

String upass1=req.getParameter("pass1");

String uemail1=req.getParameter("email1");

req.setAttribute("username", uname1);

try{

Connection conn=DbConnection.getConnection();

PreparedStatement ps=conn.prepareStatement("insert into register_table values(?,?,?)");

ps.setString(1, uname1);

ps.setString(2, upass1);

ps.setString(3, uemail1);

int i=ps.executeUpdate();

if(i>0){

req.getRequestDispatcher("WelcomeServlet").forward(req, res);

}

else{

out.print("try registering again ");

req.getRequestDispatcher("register.jsp").include(req, res);

}

}

catch(Exception e){

e.printStackTrace();

}

}

}

我没有遇到其他servlet(LoginServlet，WelcomeServlet ...)的问题

LoginServlet.java(完整代码)：

package com.pack;

import java.io.IOException;

import java.io.PrintWriter;

import java.sql.Connection;

import java.sql.PreparedStatement;

import java.sql.ResultSet;

import javax.servlet.RequestDispatcher;

import javax.servlet.ServletException;

import javax.servlet.http.HttpServlet;

import javax.servlet.http.HttpServletRequest;

import javax.servlet.http.HttpServletResponse;

public class LoginServlet extends HttpServlet {

protected void doPost(HttpServletRequest req, HttpServletResponse res) throws ServletException, IOException {

RequestDispatcher rd= null;

res.setContentType("text/html");

PrintWriter out=res.getWriter();

String upassword=req.getParameter("pass");

out.println(upassword);

String uname2=req.getParameter("name");

out.println(uname2);

try{

Connection con=DbConnection.getConnection();

out.println("conection established");

PreparedStatement ps=con.prepareStatement("select * from register_table where username=? and password=?");

ps.setString(1, uname2);

ps.setString(2, upassword);

ResultSet rs= ps.executeQuery();

if(rs.next()){

out.println("username is "+rs.getString(1)+" and pwd is "+rs.getString(2));

req.setAttribute("uid", uname2);

req.getRequestDispatcher("MainServlet").forward(req, res);

}else{

out.println("user name or password incorrect.Check and login again or register");

req.getRequestDispatcher("index.jsp").include(req, res);

}

}catch(Exception e){

e.printStackTrace();

}

}

}

web.xml(代码)：

TodayServlet

index.html

index.htm

index.jsp

default.html

default.htm

default.jsp

LoginServlet

LoginServlet

com.pack.LoginServlet

LoginServlet

/LoginServlet

RegisterServlet

RegisterServlet

com.pack.RegisterServlet

RegisterServlet

/RegisterServlet

WelcomeServlet

WelcomeServlet

com.pack.WelcomeServlet

WelcomeServlet

/WelcomeServlet

MainServlet

MainServlet

com.pack.MainServlet

MainServlet

/MainServlet

目录结构：

TodayServlet(项目名称)> src> com.pack> servlets

web-inf>(web.xml和jsp文件)