我写了一个查询,并从出生日期开始,我计算出一个人的年龄,然后使用AS年龄创建一个年龄字段.

我的问题是,是否有可能再次匹配那个年龄段？

像这样的东西,

SELECT `candidates`.`candidate_id`,

`candidates`.`first_name`,

`candidates`.`surname`,

`candidates`.`DOB`,

`candidates`.`gender`,

DATE_FORMAT(NOW(), '%Y') - DATE_FORMAT(`candidates`.`DOB`, '%Y') - (DATE_FORMAT(NOW(), '00-%m-%d') < DATE_FORMAT(`candidates`.`DOB`, '00-%m-%d')) AS `age`

FROM `candidates`

WHERE `age` <= 20

任何帮助将不胜感激？

—–所以我把WHERE更改为HAVING,这是我的完整查询——

SELECT `candidates`.`candidate_id`,

`candidates`.`first_name`,

`candidates`.`surname`,

`candidates`.`DOB`,

`candidates`.`gender`,

`candidates`.`talent`,

`candidates`.`location`,

`candidates`.`availability`,

`candidate_assets`.`url`,

`candidate_assets`.`asset_size`

FROM `candidates`

LEFT JOIN `candidate_assets` ON `candidate_assets`.`candidates_candidate_id` = `C`.`candidate_id`

WHERE `C`.`availability` = 'yes'

AND C.talent = "actor"

AND C.skill = "accents"

AND C.gender = "male"

AND HAVING DATE_FORMAT(NOW(), '%Y') - DATE_FORMAT(`candidates`.`DOB`, '%Y') - (DATE_FORMAT(NOW(), '00-%m-%d') < DATE_FORMAT(`candidates`.`DOB`, '00-%m-%d')) <= 69

AND HAVING DATE_FORMAT(NOW(), '%Y') - DATE_FORMAT(`candidates`.`DOB`, '%Y') - (DATE_FORMAT(NOW(), '00-%m-%d') < DATE_FORMAT(`candidates`.`DOB`, '00-%m-%d')) <=19

AND HAVING DATE_FORMAT(NOW(), '%Y') - DATE_FORMAT(`candidates`.`DOB`, '%Y') - (DATE_FORMAT(NOW(), '00-%m-%d') < DATE_FORMAT(`candidates`.`DOB`, '00-%m-%d')) <=49

我收到以下错误,

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ‘HAVING DATE_FORMAT(NOW(), ‘%Y’) – DATE_FORMAT(candidates.DOB, ‘%Y’) – (DATE_’ at line 15

对于我的生活,我不知道它是什么.

解决方法:

一种方法是将原始查询包装为子查询,并将WHERE子句移动到外部查询：

SELECT * FROM (

SELECT `candidates`.`candidate_id`, -- this is the original query

`candidates`.`first_name`,

`candidates`.`surname`,

`candidates`.`DOB`,

`candidates`.`gender`,

DATE_FORMAT(NOW(), '%Y') - DATE_FORMAT(`candidates`.`DOB`, '%Y') - (DATE_FORMAT(NOW(), '00-%m-%d') < DATE_FORMAT(`candidates`.`DOB`, '00-%m-%d')) AS `age`

FROM `candidates` ) as innertable

WHERE `age` <= 20 -- this is now part of the outer query

澄清：这可以在MySQL 5中运行

注意：这假设原始查询有效

标签：mysql,sql

来源： https://codeday.me/bug/20190530/1185794.html