在会计的时候，用到将数字转换为大写，也就是讲数字转为汉字

外汇出入金流程https://www.fx61.com/supportclass cnumber:

cdict = {}

gdict = {}

xdict = {}

def __init__(self):

self.cdict = {1: u'', 2: u'拾', 3: u'佰', 4: u'仟'}

self.xdict = {1: u'元', 2: u'万', 3: u'亿', 4: u'兆'} # 数字标识符

self.gdict = {0: u'零', 1: u'壹', 2: u'贰', 3: u'叁', 4: u'肆', 5: u'伍', 6: u'陆', 7: u'柒', 8: u'捌', 9: u'玖'}

def csplit(self, cdata): # 拆分函数，将整数字符串拆分成[亿，万，仟]的list

g = len(cdata) % 4

csdata = []

lx = len(cdata) - 1

if g > 0:

csdata.append(cdata[0:g])

k = g

while k <= lx:

csdata.append(cdata[k:k + 4])

k += 4

return csdata

def cschange(self, cki): # 对[亿，万，仟]的list中每个字符串分组进行大写化再合并

lenki = len(cki)

i = 0

lk = lenki

chk = u''

for i in range(lenki):

if int(cki[i]) == 0:

if i < lenki - 1:

if int(cki[i + 1]) != 0:

chk = chk + self.gdict[int(cki[i])]

else:

chk = chk + self.gdict[int(cki[i])] + self.cdict[lk]

lk -= 1

return chk

def cwchange(self, data):

cdata = str(data).split('.')

cki = cdata[0]

if len(cdata) == 1:

i = 0

chk = u''

cski = self.csplit(cki) # 分解字符数组[亿，万，仟]三组List:['0000','0000','0000']

ikl = len(cski) # 获取拆分后的List长度

# 大写合并

for i in range(ikl):

if self.cschange(cski[i]) == '': # 有可能一个字符串全是0的情况

chk = chk + self.cschange(cski[i]) # 此时不需要将数字标识符引入

else:

chk = chk + self.cschange(cski[i]) + self.xdict[ikl - i] # 合并：前字符串大写+当前字符串大写+标识符

chk = chk + u'整'

else:

i = 0

chk = u''

cski = self.csplit(cki) # 分解字符数组[亿，万，仟]三组List:['0000','0000','0000']

ikl = len(cski) # 获取拆分后的List长度

# 大写合并

for i in range(ikl):

if self.cschange(cski[i]) == '': # 有可能一个字符串全是0的情况

chk = chk + self.cschange(cski[i]) # 此时不需要将数字标识符引入

else:

chk = chk + self.cschange(cski[i]) + self.xdict[ikl - i] # 合并：前字符串大写+当前字符串大写+标识符

# 处理小数部分

ckj = cdata[1]

lenkj = len(ckj)

if lenkj == 1: # 若小数只有1位

if int(ckj[0]) == 0:

chk = chk + u'整'

else:

chk = chk + self.gdict[int(ckj[0])] + u'角整'

else: # 若小数有两位的四种情况

if int(ckj[0]) == 0 and int(ckj[1]) != 0:

chk = chk + u'零' + self.gdict[int(ckj[1])] + u'分'

elif int(ckj[0]) == 0 and int(ckj[1]) == 0:

chk = chk + u'整'

elif int(ckj[0]) != 0 and int(ckj[1]) != 0:

chk = chk + self.gdict[int(ckj[0])] + u'角' + self.gdict[int(ckj[1])] + u'分'

else:

chk = chk + self.gdict[int(ckj[0])] + u'角整'

return chk

if __name__ == '__main__':

pt = cnumber()

print(pt.cwchange('14524')) # 壹万肆仟伍佰贰拾肆元整