[20171115]关于逻辑读的疑问.txt

--//有网友指出[20150209]为什么少1个逻辑读.txt,链接:http://blog.itpub.net/267265/viewspace-1430902/
--//如何验证是这样操作的.

1.环境:

SCOTT@test> @ver1

PORT_STRING                    VERSION        BANNER
------------------------------ -------------- --------------------------------------------------------------------------------
x86_64/Linux 2.4.xx            11.2.0.3.0     Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit Production

SCOTT@test> create table t3 as select rownum id,'test' data from dual connect by level<=100;
Table created.

SCOTT@test> alter table t3 minimize records_per_block;
Table altered.

--这样就实现每块100条记录.

SCOTT@test> insert into t3  select 100+rownum id,'test' data from dual connect by level<=400;
400 rows created.

SCOTT@test> commit ;
Commit complete.

--这样总共插入100条记录. 正好占满一个1个extents.(我使用assm,前面有L1,L2,以及段头),剩下仅仅5块.

SCOTT@test> select * from dba_extents where owner=user and segment_name='T3';
OWNER  SEGMENT_NAME  SEGMENT_TYPE  TABLESPACE_NAME  EXTENT_ID    FILE_ID   BLOCK_ID      BYTES     BLOCKS RELATIVE_FNO
------ ------------- ------------- ---------------- --------- ---------- ---------- ---------- ---------- ------------
SCOTT  T3            TABLE         USERS                    0          4        536      65536          8            4

--//分析表略.
--//首先说明为什么这样?
1.首先提取1条作为1个逻辑读,我感觉像是形成输出模板.
2.逻辑读不会跨块,我在源链接没有说明这点,vage的书上有说明.

--如果我设置array=98呢?
--读1,98,1 ,98,2, 96,4, 94,6, 92,8,这样在加上块头1个逻辑读(我使用11g的版本),应该是12个逻辑读.

--//以上计算存在错误,应该是:(感谢网友指正)
--//读1,98,1 ,97,3, 95,5, 93,7, 91,9,这样在加上块头1个逻辑读,应该是12个逻辑读.

2.验证问题:
SCOTT@book> alter session set statistics_level=all ;
Session altered.

select * from t3;
SCOTT@book> @ &r/dpc '' ''
PLAN_TABLE_OUTPUT
-------------------------------------
SQL_ID  8xs59s0kcpn57, child number 1
-------------------------------------
select * from t3
Plan hash value: 4161002650
--------------------------------------------------------------------------------------------------------------------
| Id  | Operation         | Name | Starts | E-Rows |E-Bytes| Cost (%CPU)| E-Time   | A-Rows |   A-Time   | Buffers |
--------------------------------------------------------------------------------------------------------------------
|   0 | SELECT STATEMENT  |      |      1 |        |       |     4 (100)|          |    500 |00:00:00.01 |      12 |
|   1 |  TABLE ACCESS FULL| T3   |      1 |    500 |  4500 |     4   (0)| 00:00:01 |    500 |00:00:00.01 |      12 |
--------------------------------------------------------------------------------------------------------------------
Query Block Name / Object Alias (identified by operation id):
-------------------------------------------------------------
   1 - SEL$1 / T3@SEL$1

--//网友另外的问题是如何验证确实是这样的情况呢? 使用10046跟踪,仅仅看到fetch的数量.
set array 98
@ &r/10046on 12
select * from t3;
@ &r/10046off

--//查看跟踪文件:
=====================
PARSING IN CURSOR #139637584924536 len=17 dep=0 uid=83 oct=3 lid=83 tim=1510707143940419 hv=539881914 ad='7c3af540' sqlid='7pm8xmnh2vwdu'
select * from t3
END OF STMT
PARSE #139637584924536:c=4000,e=4035,p=0,cr=8,cu=0,mis=1,r=0,dep=0,og=1,plh=4161002650,tim=1510707143940418
EXEC #139637584924536:c=0,e=24,p=0,cr=0,cu=0,mis=0,r=0,dep=0,og=1,plh=4161002650,tim=1510707143940533
WAIT #139637584924536: nam='SQL*Net message to client' ela= 2 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1510707143940613
FETCH #139637584924536:c=999,e=46,p=0,cr=3,cu=0,mis=0,r=1,dep=0,og=1,plh=4161002650,tim=1510707143940707
WAIT #139637584924536: nam='SQL*Net message from client' ela= 312 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1510707143941086
WAIT #139637584924536: nam='SQL*Net message to client' ela= 1 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1510707143941153
FETCH #139637584924536:c=0,e=76,p=0,cr=1,cu=0,mis=0,r=98,dep=0,og=1,plh=4161002650,tim=1510707143941213
WAIT #139637584924536: nam='SQL*Net message from client' ela= 2462 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1510707143943711
WAIT #139637584924536: nam='SQL*Net message to client' ela= 1 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1510707143943830
FETCH #139637584924536:c=0,e=78,p=0,cr=2,cu=0,mis=0,r=98,dep=0,og=1,plh=4161002650,tim=1510707143943895
WAIT #139637584924536: nam='SQL*Net message from client' ela= 2395 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1510707143946326
WAIT #139637584924536: nam='SQL*Net message to client' ela= 1 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1510707143946395
FETCH #139637584924536:c=0,e=76,p=0,cr=2,cu=0,mis=0,r=98,dep=0,og=1,plh=4161002650,tim=1510707143946459
WAIT #139637584924536: nam='SQL*Net message from client' ela= 3601 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1510707143950095
WAIT #139637584924536: nam='SQL*Net message to client' ela= 1 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1510707143950157
FETCH #139637584924536:c=0,e=73,p=0,cr=2,cu=0,mis=0,r=98,dep=0,og=1,plh=4161002650,tim=1510707143950218
WAIT #139637584924536: nam='SQL*Net message from client' ela= 3598 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1510707143953880
WAIT #139637584924536: nam='SQL*Net message to client' ela= 1 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1510707143953940
FETCH #139637584924536:c=1000,e=72,p=0,cr=2,cu=0,mis=0,r=98,dep=0,og=1,plh=4161002650,tim=1510707143954000
WAIT #139637584924536: nam='SQL*Net message from client' ela= 3607 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1510707143957641
WAIT #139637584924536: nam='SQL*Net message to client' ela= 1 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1510707143957701
FETCH #139637584924536:c=0,e=55,p=0,cr=1,cu=0,mis=0,r=9,dep=0,og=1,plh=4161002650,tim=1510707143957744
STAT #139637584924536 id=1 cnt=500 pid=0 pos=1 obj=90670 op='TABLE ACCESS FULL T3 (cr=13 pr=0 pw=0 time=36 us cost=4 size=9500 card=500)'

*** 2017-11-15 08:52:31.840
WAIT #139637584924536: nam='SQL*Net message from client' ela= 7882935 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1510707151840765
CLOSE #139637584924536:c=0,e=21,dep=0,type=0,tim=1510707151840950
=====================

$ grep "FETCH #139637584924536" /u01/app/oracle/diag/rdbms/book/book/trace/book_ora_63061.trc
FETCH #139637584924536:c=999,e=46,p=0,cr=3,cu=0,mis=0,r=1,dep=0,og=1,plh=4161002650,tim=1510707143940707
                                                      ~~~
FETCH #139637584924536:c=0,e=76,p=0,cr=1,cu=0,mis=0,r=98,dep=0,og=1,plh=4161002650,tim=1510707143941213
FETCH #139637584924536:c=0,e=78,p=0,cr=2,cu=0,mis=0,r=98,dep=0,og=1,plh=4161002650,tim=1510707143943895
FETCH #139637584924536:c=0,e=76,p=0,cr=2,cu=0,mis=0,r=98,dep=0,og=1,plh=4161002650,tim=1510707143946459
FETCH #139637584924536:c=0,e=73,p=0,cr=2,cu=0,mis=0,r=98,dep=0,og=1,plh=4161002650,tim=1510707143950218
FETCH #139637584924536:c=1000,e=72,p=0,cr=2,cu=0,mis=0,r=98,dep=0,og=1,plh=4161002650,tim=1510707143954000
FETCH #139637584924536:c=0,e=55,p=0,cr=1,cu=0,mis=0,r=9,dep=0,og=1,plh=4161002650,tim=1510707143957744

--//注意看r=..,从这里仅仅看出第一次提取1行(看下划线)

SCOTT@book> set autot traceonly
SCOTT@book> select * from t3;
500 rows selected.
Execution Plan
---------------------------
Plan hash value: 4161002650
--------------------------------------------------------------------------
| Id  | Operation         | Name | Rows  | Bytes | Cost (%CPU)| Time     |
--------------------------------------------------------------------------
|   0 | SELECT STATEMENT  |      |   500 |  4500 |     4   (0)| 00:00:01 |
|   1 |  TABLE ACCESS FULL| T3   |   500 |  4500 |     4   (0)| 00:00:01 |
--------------------------------------------------------------------------
Statistics
----------------------------------------------------------
          0  recursive calls
          0  db block gets
         12  consistent gets
          0  physical reads
          0  redo size
       8458  bytes sent via SQL*Net to client
        574  bytes received via SQL*Net from client
          7  SQL*Net roundtrips to/from client
          0  sorts (memory)
          0  sorts (disk)
        500  rows processed

--//从SQL*Net roundtrips to/from client=7  仅仅看出网络往返的次数.与fetch的次数对应的.

--//如何查看呢?我仅仅知道10200事件,可以做到.其它不是很清楚.做一个验证看看:

$ oerr ora 10200
10200, 00000, "consistent read buffer status"
// *Cause:
// *Action:

set array 98
ALTER SESSION SET EVENTS '10200 TRACE NAME CONTEXT FOREVER, LEVEL 1';
select  *  from t3;
ALTER SESSION SET EVENTS '10200 TRACE NAME CONTEXT OFF';

SCOTT@book> @ &r/pp
TRACEFILE
--------------------------------------------------------------------------------
/u01/app/oracle/diag/rdbms/book/book/trace/book_ora_63220.trc

$ grep "started" /u01/app/oracle/diag/rdbms/book/book/trace/book_ora_63220.trc
ktrget2(): started for block  <0x0004 : 0x01000223> objd: 0x0001622e
ktrget2(): started for block  <0x0004 : 0x01000223> objd: 0x0001622e
ktrget2(): started for block  <0x0004 : 0x01000223> objd: 0x0001622e
ktrget2(): started for block  <0x0004 : 0x01000224> objd: 0x0001622e
ktrget2(): started for block  <0x0004 : 0x01000224> objd: 0x0001622e
ktrget2(): started for block  <0x0004 : 0x01000225> objd: 0x0001622e
ktrget2(): started for block  <0x0004 : 0x01000225> objd: 0x0001622e
ktrget2(): started for block  <0x0004 : 0x01000226> objd: 0x0001622e
ktrget2(): started for block  <0x0004 : 0x01000226> objd: 0x0001622e
ktrget2(): started for block  <0x0004 : 0x01000227> objd: 0x0001622e
ktrget2(): started for block  <0x0004 : 0x01000227> objd: 0x0001622e
--//读1,98,1 ,97,3, 95,5, 93,7, 91,9,这样在加上块头1个逻辑读,应该是12个逻辑读.
--//但是仅仅看出读取块的顺序.

--//实际上还有1个简单的算法:
记录数量/array_size+block的数量.

SCOTT@book> set array 50
SCOTT@book> set autot traceonly
500 rows selected.
Execution Plan
---------------------------
Plan hash value: 4161002650
--------------------------------------------------------------------------
| Id  | Operation         | Name | Rows  | Bytes | Cost (%CPU)| Time     |
--------------------------------------------------------------------------
|   0 | SELECT STATEMENT  |      |   500 |  4500 |     4   (0)| 00:00:01 |
|   1 |  TABLE ACCESS FULL| T3   |   500 |  4500 |     4   (0)| 00:00:01 |
--------------------------------------------------------------------------
Statistics
----------------------------------------------------------
          0  recursive calls
          0  db block gets
         16  consistent gets
          0  physical reads
          0  redo size
       9202  bytes sent via SQL*Net to client
        618  bytes received via SQL*Net from client
         11  SQL*Net roundtrips to/from client
          0  sorts (memory)
          0  sorts (disk)
        500  rows processed
SCOTT@book> set autot off

--// 500/50+8 = 18 (与实际16相差2),块数量越多结果越接近.

[20171115]关于逻辑读的疑问.txt相关推荐

  1. mysql物理读和逻辑读,SQL Server中STATISTICS IO物理读和逻辑读的误区

    SQL Server中STATISTICS IO物理读和逻辑读的误区 人人知道,SQL Server中可以行使下面下令查看某个语句读写IO的情形 SET STATISTICS IO ON 那么这个下令 ...

  2. 案例精解:insert逻辑读暴增至20万,只因Oracle Recyclebin过大

    墨墨导读:某客户的数据库一条insert某段时间突然变慢,平均单次执行逻辑读暴增至20万,最终定位为insert时因可用空间不充足递归清理recyclebin中的对象导致. 概述 某客户的数据库一条i ...

  3. Oracle 物理读 逻辑读 一致性读 当前模式读总结浅析

    Oracle 物理读 逻辑读 一致性读 当前模式读总结浅析 在ORACLE数据库中有物理读(Physical Reads).逻辑读(Logical Reads).一致性读(Consistant Get ...

  4. (未看)ORACLE物理读和逻辑读(SET AUTOTRACE ON 部分参数解释)[逻辑IO只有逻辑读,没有逻辑写]

    逻辑IO只有逻辑读,没有逻辑写 ORACLE物理读和逻辑读(SET AUTOTRACE ON 部分参数解释) set autotrace 产生部分信息解读的官方文档基本的定义为如下: recursiv ...

  5. Oracle逻辑读详解

    1.物理读(physical read) 当数据块第一次读取到,就会缓存到buffer cache 中,而第二次读取和修改该数据块时就在内存buffer cache 了以下是例子: 1.1 第一次读取 ...

  6. 初谈SQL Server逻辑读、物理读、预读

    前言 本文涉及的内容均不是原创,是记录自己在学习IO.执行计划的过程中学习其他大牛的博客和心得并记录下来,之所以想写下来是为了记录自己在追溯的过程遇到的几个问题,并把这些问题弄清楚. 本章最后已贴出原 ...

  7. oracle 优化逻辑读过高,详述逻辑读与arraysize的关系

    我们都知道,数据块是oracle最基本的读写单位,但用户所需要的数据,并不是整个块,而是块中的行,或列.当用户发出SQL语句时,此语句被解析执行完毕,就开始了数据的抓取阶段,在此阶段,服务器进程会先将 ...

  8. oracle如何降低逻辑读,如何降低该SQL的逻辑读

    语句: SELECT DISTINCT M.PACKAGEID AS PACKAGEID, M.PROCESSDEFINEID AS PROCESSDEFINEID, M.WORKFLOWNAME A ...

  9. 理解SQL SERVER中的逻辑读,预读和物理读

    在我的上一篇关于SQL SERVER索引的博文,有圆友问道关于逻辑读,预读和物理读的概念.我觉的还是写一篇博文能把这个问题解释清楚. SQL SERVER数据存储的形式 在谈到几种不同的读取方式之前, ...

最新文章

  1. 是时候了解一下Serverless了
  2. Vue项目碰到‘webpack-dev-server’不是内部或外部命令,也不是可运行的程序或批处理文件报错...
  3. 【C/C++】从技术学习和实际运用的角度来看,C/C++和Java到底区别在哪?C语言、C++学习路线?
  4. c++模板显示实例化,显示具体化,隐式实例化
  5. html5 sqlite存储图片,HTML5之Sqlite
  6. python中的os.path.realpath(__file__)
  7. win10系统优化与防范策略
  8. 小程序开发工具命令行启动配置
  9. C语言十折交叉验证,十折交叉验证10-fold cross validation, 数据集划分 训练集 验证集 测试集...
  10. python文件和数据格式化
  11. 利用 SysRq 键排除和诊断系统故障
  12. 看好699指纹手机暴露任泉的商业野心
  13. 【历史上的今天】8 月 18 日:硅谷神话的衰落;微软发布 QuickBASIC;Adobe Audition 问世
  14. 使用云服务器搭建Linux学习环境
  15. 夏天推荐凉快的地方不嫌多!四明山这里更是集凉爽与好玩一起
  16. 企业微信小程序_获取准确定位的方法及解决定位不准确的问题
  17. 探究正雅S8-SGTB与S8-SGHB
  18. 微信小程序几种常用弹窗提示方法
  19. java原始人生存繁殖的游戏,一款原始人生存繁殖的游戏
  20. php阿拉伯语字符串,PHP:如何检测输入字符串是否为阿拉伯语

热门文章

  1. VB 获得磁盘的文件系统
  2. Redis监控利器---Redis State
  3. GAN能生成3D图像啦!朱俊彦团队公布最新研究成果
  4. AlphaZero完胜三大世界冠军棋类程序:5000个TPU、自学一天
  5. Python 用Django创建自己的博客(2)
  6. 《计算机视觉:模型、学习和推理》一3.1 伯努利分布
  7. Git系列(七):使用Git管理二进制大对象
  8. 如何防范电改下分布式光伏的风险
  9. 静态路由实现负载均衡和高可用
  10. Spring强制使用CGLIB代理事务