有时候想看一下项目中的目录和文件结构，用python实现

主要用到这几个函数

import os

os.getcwd()  #获取当前运行程序的目录

os.listdir(path) #取得path下的文件和目录，返回值List类型

os.path.isdir(path) #判断path路径是否为目录

os.path.isfile(path)#判断path路径是否为文件

os.path.splitext(path)#对path路径切片,第二个为文件拓展名,例如'.py'

代码如下

import os

#只打印以下文件拓展名

cType = ['.py','.html','.css','.js','.sql']

def show_file(path,deep):

#取得当前目录下的文件夹以及文件，返回值List类型

file_list = os.listdir(path)

#实现遍历目录

for dir in file_list:

if os.path.isdir(path+'/'+dir):

if deep == 0:

print dir+'/'

else:

print '| '*deep+'+-'+dir+'/'

#递归打印

show_file(path+'/'+dir,deep+1)

#实现遍历文件

for file in file_list:

if os.path.isfile(path+'/'+file):

#过滤文件

for type in cType:

#对路径切片获得文件拓展名

if os.path.splitext(path+'/'+file)[1] == type:

if deep == 0:

print file

else:

print '| '*deep+'+-'+file

break;

if __name__ == '__main__':

path = os.getcwd()

print path

show_file(path,0)

例如打印某一目录结构：

/web/mycode/python/learn_web

serving_xml/

| +-templates/

| +-code.py

| +-__init__.py

basic_blog/

| +-templates/

| | +-new.html

| | +-base.html

| | +-index.html

| | +-edit.html

| | +-view.html

| | +-login.html

| +-scheme.sql

| +-model.py

| +-blog.py

| +-__init__.py

todo_list/

| +-templates/

| | +-base.html

| | +-index.html

| | +-admin.html

| +-model.py

| +-schema.sql

| +-todo.py

| +-__init__.py

方法二：

# coding=utf-8

__author__ = 'nianyu'

from os.path import basename, isdir, exists

from os import listdir

from sys import argv

def show_tree(path,depth=0):

print depth* '| ' + '|_', basename(path)

if(isdir(path)):

for item in listdir(path):

show_tree(path+'/'+item, depth+1)

def isExist(path):

if path[0] is not '/':

return False

if not exists(path):

return False

return True

if __name__ == "__main__":

args = argv

if len(args)>2:

print "more than one argument."

exit(0)

path = str(args[1])

if not isExist(path):

print "the file path do not exist."

exit(0)

# show_tree("./")

show_tree(path)