1124 Raffle for Weibo Followers（20 分）

2024-06-03 11:48:05

1124 Raffle for Weibo Followers（20 分）

John got a full mark on PAT. He was so happy that he decided to hold a raffle（抽奖） for his followers on Weibo -- that is, he would select winners from every N followers who forwarded his post, and give away gifts. Now you are supposed to help him generate the list of winners.

Input Specification:

Each input file contains one test case. For each case, the first line gives three positive integers M (≤ 1000), N and S, being the total number of forwards, the skip number of winners, and the index of the first winner (the indices start from 1). Then M lines follow, each gives the nickname (a nonempty string of no more than 20 characters, with no white space or return) of a follower who has forwarded John's post.

Note: it is possible that someone would forward more than once, but no one can win more than once. Hence if the current candidate of a winner has won before, we must skip him/her and consider the next one.

Output Specification:

For each case, print the list of winners in the same order as in the input, each nickname occupies a line. If there is no winner yet, print Keep going... instead.

Sample Input 1:

9 3 2
Imgonnawin!
PickMe
PickMeMeMeee
LookHere
Imgonnawin!
TryAgainAgain
TryAgainAgain
Imgonnawin!
TryAgainAgain

Sample Output 1:

PickMe
Imgonnawin!
TryAgainAgain

Sample Input 2:

2 3 5
Imgonnawin!
PickMe

Sample Output 2:

Keep going...

代码：

#include<bits/stdc++.h>
using namespace std;
map<string,int>mp;
char str[1005][22];
int main()
{int m,n,s;scanf("%d%d%d",&m,&n,&s);if(s>m){printf("Keep going...\n");return 0;}for(int i = 1;i <= m;i ++)scanf("%s",str[i]);for(int i = s ;i<=m;i+=n){if(mp[ str[i] ] != 0){while(i<m){i++;if(mp[str[i]] == 0){mp[str[i]]=1;printf("%s\n",str[i]);break;}}   }else{printf("%s\n",str[i]);  mp[str[i]] = 1; } }return 0;
}

1124 Raffle for Weibo Followers（20 分）相关推荐

【PAT (Advanced Level) Practice】1124 Raffle for Weibo Followers (20 分)
1124 Raffle for Weibo Followers (20 分) John got a full mark on PAT. He was so happy that he decided ...
PAT_A 1124. Raffle for Weibo Followers (20)
1124. Raffle for Weibo Followers (20) John got a full mark on PAT. He was so happy that he decided t ...
PTA甲1124 Raffle for Weibo Followers (20 point(s))
强烈推荐,刷PTA的朋友都认识一下柳神–PTA解法大佬本文由参考于柳神博客写成柳神的CSDN博客,这个可以搜索文章柳神的个人博客,这个没有广告,但是不能搜索还有就是非常非常有用的算法笔记全 ...
PAT-1124. Raffle for Weibo Followers (20)
1124. Raffle for Weibo Followers (20) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN ...
pat 1124 Raffle for Weibo Followers（20 分）
1124 Raffle for Weibo Followers(20 分) John got a full mark on PAT. He was so happy that he decided t ...
PAT 1124 Raffle for Weibo Followers python解法
1124 Raffle for Weibo Followers (20 分) John got a full mark on PAT. He was so happy that he decided ...
PAT甲级1124 Raffle for Weibo Followers ：[C++题解]哈希表、微博转发抽奖
文章目录题目分析题目来源题目分析来源:acwing 分析:开一个哈希表存已经中将的用户,避免重复发奖. 遍历所有m条姓名,从第一个中奖的开始,依次模拟即可. ac代码 #include< ...
PAT 1124 Raffle for Weibo Followers
PAT 1124 Raffle for Weibo Followers Java 1.题意输入:数字m,n,s,一串人名. 第s个为获奖的人,则s+n 为下一个获奖的人,如果此人已经获奖,那么则往后 ...
PAT（甲）1124 Raffle for Weibo Followers——未完成
题目链接按Ctrl单机链接,打开题目页面. 做题过程题目分值 20 分提交次数分值原因解决方案 1 12 答案错误重复n次 2 12 答案错误未解决收获:基本错题是通过样例猜题意,然 ...
1124 Raffle for Weibo Followers （20 分）
John got a full mark on PAT. He was so happy that he decided to hold a raffle(抽奖) for his followers ...

最新文章

热门文章